Jocelyn and Lorlesha are comparing the size of their villages in the Clash of Clans app. The area of Jocelyn's village is represented by the polynomial, 2w2+10w+12. the area of lorleshas village is represented by the polynomial, 3w2+4w-5, where e represents the width, in meters of their Town hall. part A: find the expression that represents the additional area Jocelyns village.

part B: find the expression that represents the combined total area of their villages.

Answers

Answer 1

Answer:

Answer:

A: $-w^(2)+6w+17$

B: $5w^(2)+14w+7$

Step-by-step explanation:

We have been given that the area of Jocelyn's village is represented by the polynomial $2w^(2)+10w+12$ . The area of Lorlesha's village is represented by the polynomial $3w^(2)+4w-5$ , where w represents the width, in meters of their Town hall.

A: To find the expression that will represent the additional area of Jocelyn's village, we will subtract the total area of Lorlesha's village from the total area of Jocelyn's village.

$\text{Additional area of Jocelyn's village}=2w^(2)+10w+12-(3w^(2)+4w-5)$

Let us distribute negative sign to simplify our expression.

$\text{Additional area of Jocelyn's village}=2w^(2)+10w+12-3w^(2)-4w+5$

Upon combining like terms we will get,

$\text{Additional area of Jocelyn's village}=2w^(2)-3w^(2)+10w--4w+12+5$

$\text{Additional area of Jocelyn's village}=(2-3)w^(2)+(10-4)w+12+5$

$\text{Additional area of Jocelyn's village}=-w^(2)+6w+17$

Therefore, the expression that represents the additional area Jocelyn's village is $-w^(2)+6w+17$ .

B: To find the expression that represents the combined total area of their villages we will add areas of Jocelyn's and Larlesha's village.

$\text{Combined total area}=2w^(2)+10w+12+(3w^(2)+4w-5)$

Upon combining like terms we will get,

$\text{Combined total area}=2w^(2)+3w^(2)+10w+4w+12-5$

$\text{Combined total area}=(2+3)w^(2)+(10+4)w+12-5$

$\text{Combined total area}=5w^(2)+14w+7$

Therefore the expression represents the combined total area of their villages is $5w^(2)+14w+7$ .

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If you drive 27.54 km to school and then 21.86 km to your
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You drive a total distance of 49.4 kilometers when you travel 27.54 kilometers to school and then 21.86 kilometers to your friend's house.

When you drive 27.54 km to school and then 21.86 km to your friend's place, you are covering a total distance of 49.4 kilometers. To calculate this, you simply add the two distances together:

Distance to school: 27.54 km

Distance to friend's place: 21.86 km

Total distance = 27.54 km + 21.86 km = 49.4 km

So, you drive a total of 49.4 kilometers when you travel to both school and your friend's house. This cumulative distance is the sum of the individual distances you cover for each leg of your journey. It's important to keep track of such distances, especially if you want to estimate fuel consumption, plan your commute, or calculate travel time accurately. In this case, you've covered 49.4 kilometers in total, which is the combined distance for your trip.

for more such questions on distance

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Answer:

49.4 km

Step-by-step explanation:

you add 27.54 plus 21.86 so 49.4 km total between school and to your friends house

Is 55.33 equal to 55.033

Answers

It’s is a thing called looking up the an

Make m the subject when g=square root sign over m-5

Answers

Answer:

m = g² + 5

Step-by-step explanation:

Step 1: Write equation

g = √(m - 5)

Step 2: Solve for m

Square both sides: g² = m - 5
Add 5 to both sides: g² + 5 = m
Rewrite: m = g² + 5

Write sin^2(x)*cos^2(x) as a single power of cosine, show work

Answers

This is what you're looking for if I'm not mistaken
sin²x + cos²x = 1
So:
sin²x = 1 - cos²x

∴ sin²x * cos²x = (1 - cos²x) * cos²x
= cos²x.(1 - cos²x)
(= cos²x - cos⁴x)

Solve for x: x^2 + 14x + 49

Answers

Answer: -7twice

Step-by-step explanation:

This is a question on root of quadratic equation. The interpretation of the question

x² 14x + 49 is

x² + 14x + 49 = 0.meaning that we are to find two possible values for x that will make the expression equal 0.

We can use any of the methods earlier taught. For the purpose of this class, I am using factorization methods

x² + 14x + 49 = 0

Now, find the product of the first and the last terms, is

x² × 49 = 49×²

Now find two terms such that their productbis 49x² and their sum equals 14x, the one in the middle.

We have several factors of 49x² but only one will give sum of 14x. Because of the time, I will only go straight to the required factors .

49x² = 7x × 7x and the sum gives 14x the middle terms..

Now we now replace the middle one by the factors and then factorize by grouping.

x² + 14x + 49 = 0

x² + 7x + 7x + 49 = 0

x(x + 7) + 7(x + 7) = 0

(x + 7)(x + 7). = 0

Now to find this value of x,

x + 7 = 0

x. = -7twice.

The root of the equation = -7twice.

The question is: 5 < b - 3

Answers

Answer:

8 <b

Step-by-step explanation:

5 < b - 3

Add 3 to each side

5+3< b-3+3

8 <b

Answer:

8 < b

Step-by-step explanation:

1. Add 3 by both sides to eliminate the -3 on b - 3.

2. You get 8 < b.

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