PHYSICS COLLEGE

Two wooden boxes of equal mass but different density are held beneath the surface of a large container of water. Box A has a smaller average density than box B. When the boxes are released, they accelerate upward to the surface. Which box has the greater acceleration?

Answers

Answer 1

Answer:

Answer:

Box A

Explanation:

Let mass of each wooden box =m

Density of box A= $\rho_A$

Density of box B = $\rho_B$

$\rho_A<\rho_B$

Density, $\rho=(m)/(V)$

$V_A=(m)/(\rho_A)$

$V_B=(m)/(\rho_B)$

Density of inversely proportional to volume.

The volume of box with smaller density is larger than the volume of box with large density.

$V_A>V_B$

When the boxes are submerged under water.

Then, the buoyant force= $\rho_l Vg$

Where V=Volume of displace fluid.

$\rho=$ Density of fluid

Buoyant force of box A= $\rho_lV_Ag$

Buoyant force of box B= $\rho_lV_Bg$

Force=Buoyant force

$ma_A=\rho_lV_Ag$

$ma_B=\rho_lV_Bg$

Acceleration is directly proportional to volume.

Therefore,the box with large volume has greater acceleration.

Hence, the box A has greater acceleration.

Answer 2

Answer:

Answer:

Explanation:

Let boxes A and B has equal mass of M and volume be Va and Vb

their density be da and db

given da < db

M / Va < M/Vb

Va> Vb

Buoyant force on box A in water = weight of displaced water

= volume of displaced water x density of water x g

= Va x d x g , d is density of water

Aa = acceleration on box A

= buoyant force on A / mass of A

= Va x d x g / M

Similarly acceleration on box B

Ab = Va x d x g / M

Since Va > Vb

Aa > Ab

So box A will have greater acceleration.

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1. A mass suspended from a spring oscillates vertically with amplitude of 15 cm. At what distance from the equilibrium position will the speed of the mass be 25% of its maximum speed?

Answers

Answer:

The value of the distance is $\bf{14.52~cm}$ .

Explanation:

The velocity of a particle(v) executing SHM is

$v = \omega \sqrt{A^(2) - x^(2)}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~`~(1)$

where, $\omega$ is the angular frequency, $A$ is the amplitude of the oscillation and $x$ is the displacement of the particle at any instant of time.

The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., $x = 0$ .

The maximum velocity( $\bf{v_(m)}$ ) is

$v_(m) = \omega A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Divide equation (1) by equation(2).

$(v)/(v_(m)) = \frac{\sqrt{A^(2) - x^(2)}}{A}~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)$

Given, $v = 0.25 v_(m)$ and $A = 15~cm$ . Substitute these values in equation (3).

$&& (1)/(4) = \frac{\sqrt{15^(2) - x^(2)}}{15}\n&or,& A = 14.52~cm$

Which is the best description of the scientific theory

Answers

Explanation:

a scientific theory is a well substantiated explanation of some aspect of the nature world, based on a body of facts that have been repeatedly confirmed through observation and experiment. search fact-supported theories are not "guesses" but reliable account of the real world .

When two point charges are a distance d part, the electric force that each one feels from the other has magnitude F. In order to make this force twice as strong, the distance would have to be changed toA) √2d
B) d/√2
C) d/4
D) 2d
E) d/2

Answers

Answer:b

Explanation:

Given

Force of attraction is F when charges are d distance apart.

Electrostatic force is given by

$F=(kq_1q_2)/(d^2)---1$

where k=constant

$q_1$ and $q_2$ are charges

d=distance between them

In order to double the force i.e. 2F

$2F=(kq_1q_2)/(d'^2)----2$

divide 1 and 2 we get

$(F)/(2F)=(d'^2)/(d^2)$

$d'=(d)/(√(2))$

What is the force of gravity acting on a 1-kg m mass? (g = 9.8 m/s ^ 2)

Answers

Answer: Use this F=Ma.

Explanation: So your answer will be

F=1 Kg+9.8 ms-2

So the answer will be

F=9.8N

How'd I do this?

I just used Newton's second law of motion.

I'll also put the derivation just in case.

Applied force α (Not its alpha, proportionality symbol) change in momentum

Δp α p final- p initial

Δp α mv-mu (v=final velocity, u=initial velocity and p=v*m)

or then

F α m(v-u)/t

So, as we know v=final velocity & u= initial velocity and v-u/t =a.

So F α ma, we now remove the proportionality symbol so we'll add a proportionality constant to make the RHS & LHS equal.

So, F=kma (where k is the proportionality constant)

k is 1 so you can ignore it.

So, our equation becomes F=ma

(a) Is the velocity of car A greater than, less than, or the same as thevelocity of car B?
(b) Is the initial position of car A greater than, less than, or equal to the
initial position of car B?
(c) In the time period from t = 0 tot = 1 s, is car A ahead of car B,
behind car B, or at the same position as car B?

Answers

a. ) Is the velocity of car A less than the velocity of car B b. the initial position of car A greater than the initial position of car B c. ahead In the time period from t = 0 tot = 1 s, is car A ahead of car B?.

what is velocity ?

Velocity is the parameter which is different from speed, can be defined as the rate at which the position of the object is changed with respect to time, it is basically speeding the object in a specific direction in a specific rate.

Velocity is a vector quantity which shows both magnitude and direction and The SI unit of velocity is meter per second (ms-1). If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.

Finding the final velocity is simple but few calculations and basic conceptual knowledge are needed.

For more details regarding velocity, visit

brainly.com/question/12109673

#SPJ2

Answer:

a. less than, b. greater than, c. ahead

Explanation:

If a photon has a frequency of 5.20 x 10^14 hertz, what is the energy of the photon ? Given : Planck's constant is 6.63 x 10^-34 joule-seconds.

Answers

For this you would use planck's equation.

E = hv, where v = the frequency and h = planck's constant.

So E = 5.20 x10^14 x 6.63 x 10^-34
= 3.45 x 10^-19 Joules

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