MATHEMATICS HIGH SCHOOL

Multiply. start fraction k plus 3 over 4 k minus 2 end fraction dot left parenthesis 12 k squared plus 2 k minus 4 right parenthesis

Answers

Answer 1

Answer:

Answer:

$\therefore ((k+3))/((4k-2)).(12k^2+2k-4)=3k^2+11k+6$

Step-by-step explanation:

Factorization of a Quadratic polynomial:

In order to factorize $ax^2+bx+c$ we have to find out the numbers p and q such that, p+q = b and pq=ac.

Finding the two integers p and q, we rewrite the middle term of the quadratic as px+qx. Then by grouping of the terms we can get desired factors.

Multiplication of two binomial:

(a+b)(c+d)

=a(c+d)+b(c+d)

=(ac+ad)+(bc+bd)

=ac+ad+bc+bd

Given that,

$((k+3))/((4k-2)).(12k^2+2k-4)$

$=((k+3))/(2(2k-1)).2(6k^2+k-2)$ [ taking common 2]

$=((k+3))/((2k-1)).(6k^2+k-2)$ [ cancel 2]

$=((k+3))/((2k-1)).(6k^2+4k-3k-2)$

$=((k+3))/((2k-1)).\{2k(3k+2)-1(3k+2)\}$

$=((k+3))/((2k-1)).(3k+2)(2k-1)$

$=(k+3).(3k+2)$

$=3k^2+9k+2k+6$

$=3k^2+11k+6$

$\therefore ((k+3))/((4k-2)).(12k^2+2k-4)=3k^2+11k+6$

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Simplify the expression

Answers

Answer:

f(x) = 5x² + 2x

g(x) = 6x - 6

Step-by-step explanation:

$(5x^3-8x^2-4x)/(6x^2-18x+12)\n\n6(x^2-3x+2)\ne0\ \iff\ x=(3\pm√(9-8))/(2)\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\n\n\n(5x^3-8x^2-4x)/(6x^2-18x+12)=(x(5x^2-8x-4))/(6(x^2-3x+2))=(x(5x^2-10x+2x-4))/(6(x^2-2x-x+2))=\n\n\n=(x[5x(x-2)+2(x-2)])/(6[x(x-2)-(x-2)]) =(x(x-2)(5x+2))/(6(x-2)(x-1))=(x(5x+2))/(6(x-1))=(5x^2+2x)/(6x-6)\n\n\nf(x)=5x^2+2x\n\ng(x)=6x-6$

Simplify.7 square root of 3 end root minus 4 square root of 6 end root plus square root of 48 end root minus square root of 54A) 11 square root of 6 end root minus 7 square root of 12
B) 11 square root of 3 end root minus 7 square root of 6
C) negative 3 square root of 9
D) 4 square root of 9

Answers

The simplest form of the expression ''7 square root of 3 end root minus 4 square root of 6 end root plus the square root of 48 end root minus the square root of 54'' would be, ''11 square root of 3 end root minus 7 square root of 6''. Hence, option B is true.

Used the concept of the square root of a number that states that,

The square root of a number is the number that, when multiplied by itself, gives the original number.

Given that the expression is,

7 square root of 3 end root minus 4 square root of 6 end root plus the square root of 48 end root minus the square root of 54.

Now, the mathematical form of the expression is,

$7√(3) - 4√(6) + √(48) - √(54)$

Simplify each term,

$7√(3) - 4√(6) +4 √(3) - 3√(6)$

Combine like terms,

$7√(3) +4 √(3) - 4√(6) - 3√(6)$

$11√(3) - 7√(6)$

It can be written as,

11 square root of 3 end root minus 7 square root of 6.

Hence, option B is true.

To learn more about square root visit:

brainly.com/question/428672

#SPJ6

$7√(3)-4√(6)+√(48)-√(54)=7√(3)-4√(6)+√(16*3)-√(9*6)\n=7√(3)-4√(6)+4√(3)-3√(6)=11√(3)-7√(6)$

Need to see how you divide 247÷100

Answers

It's very easy to divide 100 into a number because although it might be a decimal, there is no really difficult dividing going on.

100 goes into 247
2 times and then there is .47 remaining. This means 100 cannot be divided equally into this number but it will be a decimal.

Your answer would look like this:

2.47

Mr young has 30 times as many pencils as jack. The whole class has 200 times as many pencils as jack. If jack has 2pencils, how many pencils does mr young have ? And the whole school have?

Answers

well you would do 30*2= 60
and that would be your answer

Ellen plans to have two children but doesn't know if they will be boy-boy, girl-girl, or boy-girl. What is the probability that she will have two girls?0.25
0.5
0.75
1.00

Answers

Answer:

Option A. 0.25

Step-by-step explanation:

Ellen plans two children but does not know if they will be boy-boy, girl-girl or boy-girl.

For the first baby to be the girl child

Probability = $(1)/(2)$

Similarly probability for second baby to be the girl child will be $(1)/(2)$

Now both the children are girl to probability for this event will be

= $(1)/(2)$ × $(1)/(2)$

= $(1)/(4)$

= 0.25

Option A. 0.25 is the answer.

.25 because you would look at it like a boy-girl situation and this problem is more of a science problem. Anyways, if you do BG(BoyGirl) x BG(BoyGirl) it equals BB(Boy Boy), BG( Boy Girl ), another BG and a GG ( Girl Girl ) so there is a 1/4 chance of having 2 girls which is the same as .25.

Monica earned twice as much as Samuel mowing lawns. if Monica earned $48, how much did Samuel earn

Answers

monica earned 2×samuel's paycheck
so, if monica earns 48, we set that equal to 2×samuel's paycheck (let Y represent his paycheck)
so, 48=2×Y divide each side by 2
Y=24, so samuel made $24

Samuel earned $96 this is bc 48 + 48 = 96

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