The average speed of a golden eagle is 30 mph and the average speed of a peregrine falcon is 48 mph. How far will the peregrine falcon fly in the time it takes the eagle to fly 40 miles?

Answers

Answer 1
Answer:

The peregrine falcon flies in the time it takes the eagle to fly 40 miles is 64 miles away.

What is the average speed?

The average speed is the total distance traveled by the object in a particular time interval.

The average speed is a scalar quantity.

The average speed of a golden eagle is 30 mph and the average speed of a peregrine falcon is 48 mph.

The time to fly 40 miles (that time is x):

miles        hours

30      ⇒       1

40      ⇒       x

We use the ruleof three which is to multiply the cross quantities on the table and divide by the remaining quantity:

x = 40(1)/30

x = 4/3 hour

it takes the eagle 4/3  flies to fly 40 miles.

Now we use the velocity of the falcon: 48mph, which can also be represented as:

miles        hours

48      ⇒       1  

and we need the distance in miles that the falcon flies in 4/3 hours :

miles        hours

48      ⇒       1

x        ⇒       4/3

Again we use the rule of three (multiply cross quantities and divide by the remainingquantity)

x = (48)× (4/3)

x = 64 miles

Hence, the peregrine falcon flies in the time it takes the eagle to fly 40 miles is 64 miles away.

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Answer 2
Answer:

Answer:

64

Step-by-step explanation:

64 miles


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I will give brainlyist and extra points for correct answer ( no links )

Answers

Answer:

7. 56

8. 117

Step-by-step explanation:

7.

Add the lengths of the sides. Each square on the grid has side 2 units.

9 + 4 + 4 + 8 + 11 + 3 + 2 + 15 = 56

8.

Find the lengths of the bases and the height of the trapezoid. Each square on the grid is 2 units.

Area of trapezoid = (1/2)(b1 + b2)h

area = (1/2)(15 + 11)(9) = 117

What are the following proof triangle LMN equals triangle OPQ

Answers

Answer:

D. SSS

Step-by-step explanation:

Was given to us that the corresponding sides are congruent so is SSS.

Side Side Side Theorem tells us that if am the sides of a triangle are having the same measurement with the corresponding sides of another triangle then the two triangles are congruent.

100 POINTS PLEASE HELP ON HW

Answers

Answer:

Solution given:

f(x)=x²

g(x)=x+5

h(x)=4x-6

now

23:

(fog)(x)=f(g(x))=f(x+5)=(x+5)²=+10x+25

24:

(gof)(x)=g(f(x))=g(x²)=+5

25:

(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36

26:

(hof)(x)=h(f(x))=h(x²)=4x²-6

27;

(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1

28:

(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14

Answer:

the answer is 4x - 4

Step-by-step explanation:

If a new truck costs $43,750 and it depreciates 18% per year, what will the truck be worth in 5 years? 1 SEE ANSWER

Answers

if it depreciates by 18%, then as each year passes, its worth is reduced to 82% of its value
So, after 5 years, it is worth 43750

HELP 100 PointsIf △NMK ≅ △TRP, then answer the following questions:
a. Complete the congruence statement: △MNK ≅ △_______
b. What side is congruent to ≅ ______
c. Solve for x. _____

Answers

The given statements to be completed are completed as follows;

A) △MNK ≅ △RTP

B) TR ≅ NM

C) x = 7

We are given that;

△NMK ≅ △TRP

This means that Triangle NMK is congruent to Triangle TRP.

A) The naming of △NMK is now △MNK. Thus, we have to now re-name Triangle TRP to match the naming of △MNK. Thus;

△MNK ≅ △RTP

B) From the 2 given triangles, we can see that TR and NM are the same length and also perpendicular lines.

Thus they are congruent to each other and as such;

TR ≅ NM

C) Since TR and NM are congruent to each other. Then;

TR = NM

Thus;

3x - 1 = 20

3x = 20 + 1

3x = 21

x = 21/3

x = 7

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Answer:

A-△MNK ≅ △RTP

B- TR≅NM

C- X=7

Step-by-step explanation:

I did the assignment loves.

If BC = x − 2, CD = 19, and BD = 3x − 11, what is BD? Simplify your answer and write it as a proper fraction, mixed number, or integer. Could you please type the answer in a step by step.

Answers

Answer:

UV = 15

BD= 31

Step-by-step explanation:

Since, U is the midpoint of TV.

Therefore,

TU = UV

x + 10 = 3x

x - 3x = - 10

-2x = - 10

x = - 10/-2

x = 5

UV = 3x = 3*5

UV = 15

BD = BC + CD

3x - 11 = x - 2 + 19

3x - 11 = x + 17

3x - x = 11 + 17

2x = 28

x = 28/2

x = 14

BD = 3x - 11 = 3*14-11 = 42 - 11

BD= 31

Final answer:

We used the relationship that BC + CD = BD and then solved for x, which we found to be 14. We then substituted 14 for x in the equation for BD, which gave us a result of 31.

Explanation:

In the given question, we have a piece of a line divided into different sections: BC, BD, and CD with their respective lengths. BD is represented through a variable equation. We know that BC + CD = BD, this is a fundamental property of geometry that the sum of the lengths of two consecutive sections of a line is equal to the total length. So, substitute the given values:

x − 2 + 19 = 3x − 11

Simplify the equation by combining like terms: x + 17 = 3x - 11. Now, let's solve for x:

First, consolidate x's on one side by subtracting 'x' on both sides. We get 17 = 2x - 11.

Next, add 11 on both sides to solve for x. We get, 28 = 2x.

Finally, divide by 2 on both sides to find x, x = 14.

Now, we can find BD by substituting x into the equation 3x - 11, we get:

BD = 3*14 - 11 = 42 - 11 = 31.

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