Answer:
A. No, it would not succeed.
B. Yes, the attack will succeed.
Explanation:
In the seven-layer OSI model of computer networking, packet strictly refers to a protocol data unit at layer 3, the network layer. So if an attacker wants to insert bogus/ fake packets this will happen at the network layer.
A. IPSec works on network layer (the IP layer) of the OSI model protecting and authenticating IP packets. It provides data integrity, authentication and confidentiality between participating peers at the IP layer.
Thus, inserting bogus packets into the communications by an attacker will not have any affect on security of a system which has IPSec security and therefore it will not succeed.
B. SSL/TLS is an application layer protocol that fits into layer 5 to 7 of the OSI model. However, an attack by inserting bogus packets into the communications will succeed as SSL only provides protection for layer 5 to 7 and not the network layer.
The types of messages which flow across an SDN controller northbound and southbound APIs are:
The recipient of these messages sent from the controller across the southbound interface, and who sends messages to the controller across the northbound interface are:
This refers to the exchange of information between different people or computers using a medium which also gives feedback.
Read more about communication here:
brainly.com/question/25793182
Answer and Explanation:
Messages flow across an SDN controller's:
Northbound APIs:
• Messages which help in read/write state of the network and developing flow tables within the
state management layer.
• Notifications for the state-change events.
• The interaction between the controller and network control applications is done through the
northbound interface.
• Network control applications send messages to the controller.
Southbound APIs:
• Messages which help for the up-to-date view of the network's state like message for the
attached link has gone up or down, new devices are joined the network, or indications of the
device is up or down.
• Controller's southbound interface is the communication among the controller and the controlled
devices. Controlled devices are the recipients of the messages sent form the controller.
Answer:
The answer is "For the stop and wait the value of S and R is equal to 1".
Explanation:
C++ program for calculating the average of scores
#include <iostream>
using namespace std;
const int n=5;//As per question only 5 test scores were there
int numbers[5];
void getscore(int i)//defining function for taking input
{
cin >> numbers[i];
while(numbers[i]<0 || numbers[i]>100)//score should be between 0 to 100
{
cout<<"\nThe number should be between 0 to 100\n";
cin>>numbers[i];
}
}
int main()//driver function
{
cout << "Enter 5 scores:\n";
for (int i = 0; i < n; i++)
{
getscore (i);//calling function each time for input
}
int s = 101;
double avg = 0;
for (int i = 0; i < n; i++)//loop for finding the smallest
{
s = numbers[i] < s ? numbers[i] : s;
}
for (int i = 0; i < n; i++) //loop for finding the Average
{
avg += numbers[i];
}
avg -= s;
avg /= 4;
cout << "Average of the four scores are: " << avg<< endl;//printing the output
return 0;
}
Output
Enter 5 scores:
4
5
6
7
8
Average of the four scores are: 6.5
Answer:
int main()
{
int A1= {5,3,4,8,9,0,7};
int SArri1 = sizeof(A1);
printf("Original array: ");
for (int i=0; i < SArri1;i++)
printf("", A1[i] );
int i, sum = 20, n= 0;
printf("\nArray pairs whose sum equal to 20: ");
for (int i=0; i<SArri1; i++)
for (int j=i+1; j<SArri1; j++)
if (A1[i]+A1[j] == sum)
{
Printf(“\n”, array1[i])
Printf(“,”,array1[j]);
n++;
}
printf("\nNumber of pairs whose sum equal to 20: ",n)
return 0;
}
Explanation:
First of all, you should create the array of integers, and put random numbers. Then you have to save in a constant the size of the array (in this code is called SArr1) With a for you can print all the numbers that are on the array because then you will print all array pairs whose sum is equal to a specified numer. in this code we are going to use 20.
then with a condition (if) you are going to compare one of number of the array with all the others and check if its equal to 20. If yes, it going to print the numbers that answer to that condition and it's going to add +1 to the variable n (for this you will need to use two bucles for)
Then you can print the number of pairs whose sum is equal to 20 by printing n
Answer:
Half Center Right Left, theres four
Explanation:
Answer:
C) X=40.24 Y=24.33 Z=20.75
Explanation: