In shorthorn cattle, coat colors are governed by a codominant pair of alleles R and W. The homozygous genotype RR produces red, the other homozygote produces white and the heterozygote produces roan ( a mixture of red and white). The presence of horns is produced by the homozygous recessive genotype pp and the polled condition by its dominant allele P. If roan cows heterozygous for the horned gene are mated to a horned, roan bull, what phenotype ratio is expected in the offspring?
Answers
Answer:
1/8 Red, polled
1/8 Red, horned
1/4 roan, polled
1/4 roan, horned
1/8 white, horned.
1/8 white, horned.
Explanation:
Roan cow with heterozygous horned genotype = RWPp
Roan, horned bull genotype = RWpp
Crossing the two:
RWPp x RWpp
Offspring:
2 RRPp = Red, polled
2 RRpp = Red, horned
4 RWPp = roan, polled
4 RWpp = roan, horned
2 WWPp = white, polled
2 WWpp = white, horned.
Hence, the phenotypic ratio is:
1/8 Red, polled
1/8 Red, horned
1/4 roan, polled
1/4 roan, horned
1/8 white, horned.
1/8 white, horned.
Answer:
The phenotypic ratio of the cattle offsprings is as follows:
Red polled = 1/8
Red horned = 1/8
White polled = 1/8
White horned = 1/8
Roan polled = 2/8
Roan horned = 2/8
Explanation:
This is a cross involving two genes; one coding for coat color and the other for horn in cattle. The alleles of the first gene (Red, R and White, W) are codominant i.e. will both be expressed in a heterozygous state (Roan, RW). The polled allele (P) is dominant over the horned allele (p) in the second gene.
According to the question, a roan cow that is heterozygous for the horned gene will have genotype, RWPp while a roan bull that is horned will have genotype, RWpp. Hence, in a cross between these two cattles, each parent will undergo meiosis to produce the following possible gamete combinations;
RWPp- RP, Rp, WP, Wp
RWpp- Rp, Rp, Wp, Wp
These gametes used in a punnet square (see attachment) will produce 16 possible offsprings with 6 distinct phenotypes. The phenotypes are:
Red polled (RRPp or RRPP) = 2/16 or 1/8
Red horned (RRpp) = 2/16 or 1/8
White polled (WWPP or WWPp) = 2/16 or 1/8
White horned (WWpp) = 2/16 or 1/8
Roan polled (RWPP or RWPp) = 4/16 or 2/8
Roan horned (RWpp) = 4/16 or 2/8
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Answer: The frequency of the homozygous recessive genotype is the value of
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Answer:
The answer to the question is
The expected frequency of homozygotes for the allele in a population at Hardy-Weinberg Equilibrium is 0.998
Explanation:
From the question, we have the frequency of an allele = 0.999
By Hardy-Weinberg Equilibrium
p² + 2pq + q² = 1 and p + q = 1
p = dominant allele frequency in the population
q = recessive allele frequency in the population
p² = homozygous dominant individuals percentage
q² = homozygous recessive individuals percentage
2pq = heterozygous individuals percentage
Therefore the frequency of the homozygotes for the allele = 0.999² = 0.998001 ≅ 0.998 to three decimal places
The Hardy-Weinberg equilibrium states that the genetic disparity in a population will remain unchanged from generation to generation in the absence of evolutionary disturbing influences