The example of base-conjugate acid pair is B. NH3 and NH4+.
A base-conjugate acid pair simply means a pair that consist of two substances that only differ by the presence of a proton (H+).
In this case, the example of base-conjugate acid pair is NH3 and NH4+ because bNH4+ is the conjugate acid of the base NH3.
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Answer:
NH3 and NH4+
Explanation:
NH4+ is the conjugate acid of the base NH3.
The mass will not change, because if you add or subtract any clay the mass doesn't change if u took some away or added any the mass would have changed.
Distance has a physical quantity which has been measured in meter. If a man travel then it will measured in meters that shows that how much he had travelled from one place to another place for all such type of things we use to measure the distance.
Centimeter is also been physical quantity which has to be used measure distance. 1 centimeter is just equal to 0.01 meter and 1 centimeter is just equal to 0.00001 kilometer and the kilometer has been large quantity to measure distance on the other hand centimeter is smaller quantity in which distance is measured.
Kilometer is also known as physical quantity which used to measure the distance of 1 kilometer which is equal to 1000 meter and 1 kilometer is just equal to 10,0000 centimeter.
For above conclusion, we easily states that the kilometer is large quantity to measure distance while centimeter is smaller quantity to measure distance. Centimeter is also a physical quantity which is use to measure distance. 1 centimeter is equal to 0.01 meter and 1 centimeter is equal to 0.00001 kilometer.
Therefore,The mass will not change, because if you add or subtract any clay the mass doesn't change if u took some away or added any the mass would have changed.
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Answer:
Explanation:
There is a fundamental length, the Planck length. It is the length that light (a photon) travels in a unit of time called the Planck time and conforms to the way to measure length in general, as given by the equation
L = ct
Where L is length (or distance), c the speed of light (3 X 10^8 meters/sec), and t the time the light travels in. The Planck length is exceedingly small (magnitude 10^-35 meters because the Planck time is short (10^-44 sec)
The Planck length, or any length based on the speed of light, is not subject to the imprecision we would find by measurement with a physical ruler, for example, because a ruler can expand or shrink or be bent or warped, etc.
Rather, length based on c (in a vacuum) is constant. This concept is another gift from Einstein’s theory of special relativity. It’s also the central concept in spacetime, though it would take some explaining for me to say why it is so.
Answer:
C15H24O
Explanation:
TO GET THE EMPIRICAL FORMULA, WE NEED TO KNOW THE MASSES AND CONSEQUENTLY THE NUMBER OF MOLES OF EACH OF THE INDIVIDUAL CONSTITUENT ELEMENTS.
FIRSTLY, WE CAN GET THE MASS OF THE CARBON FROM THAT OF THE CARBON IV OXIDE. WE NEED TO KNOW THE NUMBER OF MOLES OF CARBON IV OXIDE GIVEN OFF. THIS CAN BE CALCULATED BY DIVIVDING THE MASS BY THE MOLAR MASS OF CARBON IV OXIDE. THE MOLAR MASS OF CARBON IV OXIDE IS 44G/MOL
The combustion of 1.376 g of butylated hydroxytoluene (BHT) produced 4.122 g CO2 and 1.350 g H2O. Calculations yield an empirical formula of CH2O, indicating one carbon, two hydrogen, and one oxygen atom.
To determine the empirical formula of butylated hydroxytoluene (BHT), we can follow these steps:
1. **Find moles of CO2 and H2O produced:**
\[ \text{moles of } CO_2 = \frac{\text{mass of } CO_2}{\text{molar mass of } CO_2} \]
\[ \text{moles of } H_2O = \frac{\text{mass of } H_2O}{\text{molar mass of } H_2O} \]
2. **Find the mole ratio:**
Divide the moles of each element (C, H, and O) in CO2 and H2O by the smallest number of moles.
3. **Write the empirical formula:**
Use the mole ratios to write the empirical formula.
Let's perform the calculations:
\[ \text{Molar mass of } CO_2 = 12.01 \, \text{(C)} + 2 \times 16.00 \, \text{(O)} = 44.01 \, \text{g/mol} \]
\[ \text{Molar mass of } H_2O = 2 \times 1.01 \, \text{(H)} + 16.00 \, \text{(O)} = 18.02 \, \text{g/mol} \]
\[ \text{moles of } CO_2 = \frac{4.122 \, \text{g}}{44.01 \, \text{g/mol}} \approx 0.0938 \, \text{mol} \]
\[ \text{moles of } H_2O = \frac{1.350 \, \text{g}}{18.02 \, \text{g/mol}} \approx 0.0749 \, \text{mol} \]
Divide by the smallest number of moles (0.0749) to get a ratio close to 1:1:
\[ \text{C} : \text{H} : \text{O} \approx 1.25 : 1 : 1 \]
The ratio is approximately 1:1:1, so the empirical formula is CH2O.
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Water can dissolve many ionic and covalent compounds.
Water can dissolve many substances, but often requires large amounts of heat to be added.
Water is usually available.
Water is known as the 'universal solvent' because water can dissolve many ionic and covalent compounds.
It is considered as a universal solvent because it has the ability to dissolve large number of substances in it as compared to other liquids so that's why we can say that water is a universal solvent due to its high dissolving power.
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The best answer is the second statement. It is considered as a universal solvent since most substances dissolve in water. And comparing it to other liquids, it is the one who dissolves a wide range of substances. Also, it is an important substance for every living thing.
The volume of a 0.40 M Mg(NO3)2 solution contains 89g of Mg(NO3)2 is 1.5 L.
Solution is defined as a particular kind of homogenous combination made up of two or more different ingredients. Solute refers to the material that dissolves. Solvents are described as substances that do not dissolve. The substance known as salt water is a solution. A solute and a solvent combine to produce a solution; this is a physical, not a chemical process. A solution is produced when one substance splits apart or dissolves into another.
To calculate this, subtract 89g from 148.3g/mol, the molar mass of magnesium nitrate.
= 89 / 148.3
= 0.6 mole of magnesium nitrate
The volume of solution can be as
= 0.6 moles / 0.40 M
= 1.5 liter.
Thus, the volume of a 0.40 M Mg(NO3)2 solution contains 89g of Mg(NO3)2 is 1.5 L.
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