CHEMISTRY HIGH SCHOOL

0.500dkg = ?g

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0.500dkg = ?g HELP PLS!!!! - 1

Answers

Answer 1
Answer:

Answer:10 grams

Explanation:

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A solution of salt (molar mass 90 g mol-1) in water has a density of 1.29 g/mL. The concentration of the salt is 35% by mass.a. Calculate the molality of the solution.

b. Calculate the molarity of the solution.

c. Calculate the mole fraction of the salt in the solution.

Answers

The molarity of the solution is 5.018 mol/L and molality of the solution 5.9846 mol/kg.

 

Assume 100 g of solution the salt concentration- 35 % and water will be 65 %.    

So,  

mass of salt = 35 g  

mass of water = 65 g  

Number of moles,  

\bold {moles = \frac {mass} { molar\ mass}}

So,    

moles of salt = 35 g / 90 (g/mol) = 0.389 mole  

moles of water = 65 / 18 = 3.6111 mole  

 

Volume of solution,

\bold {volume =\frac { mass } {density }}  

volume = 100 g / ( 1.29 g/ml)  

volume of solution = 77.52 ml = 0.07752 L  

 

a)

\bold {Molality = \frac {moles\ of \salt} { mass\ of\ water (kg)}}  

molality = 0.389 mol / 0.065 kg  

molality = 5.9846 mol/kg  

b)  

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L  

molarity = 5.018 mol/L  

c)    

 mole fraction of salt = moles of salt / total moles  

mole fraction of salt = 0.389 mol / ( 0.389 + 3.6111)  

mole fraction of salt = 0.09725

To know more about Molarity,

brainly.com/question/12127540

Answer:

a) 5.9846 mol/kg

b) 5.018 mol/L

c)0.09725

Explanation:

consider 100 g of solution

now

since the salt is 35 % , water will be 65 %

now

mass of salt = 35 g

mass of water = 65 g

we know that

moles = mass / molar mass

so

moles of salt = 35 g / 90 (g/mol) = 0.389 mol

moles of water = 65 / 18 = 3.6111 mol

now

volume of solution = mass of solution / density of solution

volume of solution = 100 g / ( 1.29 g/ml)

volume of solution = 77.52 ml

volume of solution = 0.07752 L

a)molality = moles of salt / mass of water (kg)

molality = 0.389 mol / 0.065 kg

molality = 5.9846 mol/kg

b)

molarity = moles of salt / volume of solution (L)

molarity = 0.389 mol / 0.07752 L

molarity = 5.018 mol/L

c)

now

total moles in the solution = moles of salt + moles of water

total moles in the solution = 0.389 + 3.6111

total moles in the solution = 4 mol

now

mole fraction of salt = moles of salt / total moles

mole fraction of salt = 0.389 mol / 4 mol

mole fraction of salt = 0.09725

Please show step by step and I will mark you as brainliest answer ❤️​

Answers

Answer: The pH of the solution is 13.

Explanation:

pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution.

pOH=-\log [OH^-]

We are given:

Concentration of Ca(OH)_2=0.05mol/dm^3=0.5mol/L          (Conversion factor: 1L = 1dm^3 )

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions

Concentration of OH^-=(2* 0.05)=0.1mol/L

Putting values in above equation, we get:

pOH=-\log (0.1)\n\npOH=1

We know:

pH+pOH=14\n\npH=14-1\n\npH=13

Hence, the pH of the solution is 13.

What are the properties of an ionic bond?

Answers

Answer:

Ionic Compounds have high boiling and melting points as they're very strong and require a lot of energy to break. The electrostatic forces of attraction between oppositely charged ions lead to the formation of ions. Ionic compounds form crystals. These compounds are brittle and break into small pieces easily.

Explanation:

If 10.0 liters of h2(g) at STP is heated to a temperature of 546 K, pressure remaining constant, the new volume of the gas will be

Answers

Answer:

20L

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 10L

Initial Temperature (T1) = stp = 273K

Final temperature (T2) = 546K

Final volume (V2) =..?

The new volume of the gas can be obtained by using the Charles' law equation as shown below:

V1/T1 = V2/T2

10/273 = V2/546

Cross multiply to express in linear form

273 x V2 = 10 x 546

Divide both side by 273

V2 = (10 x 546) / 273

V2 = 20L

Therefore, the new volume of the gas is 20L.
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