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Can someone help me with isosceles triangles???

Answers

Answer 1

Answer:

Answer:

1) x = 75°

2) x = 180° - 2×40° = 180° - 80° = 100°

3) x = 180° - 2×73° = 180° - 146° = 34°

4) x = (180° - 122°) : 2 = 58° : 2 = 29°

5) x = 90° - (180° - 80°) : 2 = 90° - 100° : 2 = 90° - 50° = 40°

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Using the 1 to 9 at the most time each, fill in the boxes to make a true statement

Answers

Answer:

Step-by-step explanation:

8*8 is 64

Since it looks like the empty box is an exponent, and there are 2 8s being multiplied, the answer is 2

Forty-five CEO’s from the electronics industry were randomly sampled and a 99 % % confidence interval for the average salary of all electronics CEO’s was constructed. The interval was $101,866<μ<$115,016 $101,866<μ<$115,016 To make more useful inferences from the data, it is desired to reduce the width of the confidence interval. What will result in a reduced interval width? Select one: a. Any of these methods will result in a reduced interval width. b. Keep the sample size the same and decrease the confidence level. c. Keep the sample size the same and increase the confidence level. d. Decrease the sample size and keep the same confidence level.

Answers

Answer:

b. Keep the sample size the same and decrease the confidence level.

Step-by-step explanation:

We first have to find the critical value of z, which depends of the confidence level.

90% confidence level

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = (1-0.9)/(2) = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

99% confidence level

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = (1-0.99)/(2) = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

The width of the interval is:

$W = z*(\sigma)/(√(n))$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

So, as z increses, so does the width. If z decreases, the width decreases. Lower confidence levels have lower values of z.

As n increases, the width decreses.

What will result in a reduced interval width?

b. Keep the sample size the same and decrease the confidence level.

-4= -(x-8)
negative four equals negative (parentheses x minus 8 parentheses)

Answers

-4=-x-8
+4. +4
—————
0=-x-4
x=-4

The sum of two numbers is -14, if one number is subtracted from the other, their difference is 2, find the numbers.

Answers

Answer:uu

-10 and -12

Step-by-step explanation:

A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 42 states. What is the probability that she selects the route of four specific capitals? Is it practical to list all of the different possible routes in order to select the one that is best?P(she selects the route of four specific capitals): _____.
Is it practical to list all of the different possible routes in order to select the one that is best?
A.
Yes, it is practical to list all of the different possible routes because the number of possible permutations is very small.
B.
Yes, it is practical to list all of the different possible routes because the number of possible permutations is very large.
C.
No, it is not practical to list all of the different possible routes because the number of possible permutations is very small.
D.
No, it is not practical to list all of the different possible routes because the number of possible permutations is very large.

Answers

Answer:

P (She selects the route of four specific capitals) = $(1)/(2686320)=(3.7226)10^(-7)$

D. No,it is not practical to list all of the different possible routes because the number of possible permutations is very large.

Step-by-step explanation:

Let's start assuming that each route is equally likely to be chosen.

Assuming this, we can calculate P(A) where the event A is ''She selects the route of four specific capitals'' doing the following :

P(A) = Favourable cases in which the route of four specific capitals is selected / Total number of ways in 4 of 42 states

The favourable cases in which the route of four specific capitals is selected is equal to 1 .

For the denominator we need the permutation number of 4 in 42.

The permutation number is defined as :

$nPr=(n!)/((n-r)!)$

$42P4=(42!)/((42-4)!)=(42!)/(38!)=2686320$

The probability of event A is : $(1)/(2686320)=(3.7226)10^(-7)$

Finally for the other question : The option D is the correct because the number of possible permutations is 2686320 and is very large to be listed.

Plz help I will mark brainlest!

Answers

number 12 : answer is b

Answer:

the first picture is 5.2 so b

The second picture is 2 and a half centimeters so also b

TRUST ME

Step-by-step explanation:

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