CHEMISTRY COLLEGE

A rigid container of gas has a pressure of 1.72 atm and temperature of 21 oC. If the temperature increases to 85 oC, what is the new pressure in atm?

Answers

Answer 1

Answer:

Answer:

the new pressure is 2.09 atm

Explanation:

you have to use gay lussac's law so the formula is

p1/t1 = p2/t2

and convert C to Kelvin k=C+273.15

1.72atm/294.15 = p2/358.15

solve for p2 by multiplying 358.15 on both sides

p2=2.09 atm

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How many molecules are in 2.50 moles of co2

Answers

Explanation:

There are 1.51 x 1024 molecules of carbon dioxide in 2.50 moles of carbon dioxide.

Consider the following reaction: Pb(NO3)2(aq) + 2 NaCl(aq) → PbCl2(s) + 2 NaNO3(aq)If you react an excess of Pb(NO3)2with 26.3 g of NaCl, and you isolate 52.1 g of PbCl2, what is your percent yield?

Answers

Answer:

$\large \boxed{84.7 \, \%}$

Explanation:

Mᵣ: 58.44 278.11

Pb(NO₃)₂ + 2NaCl ⟶ PbCl₂ + 2NaNO₃

m/g: 26.3

1. Moles of NaCl

$\text{Moles of NaCl} = \text{26.3 g NaCl} * \frac{\text{1 mol NaCl}}{\text{58.44 g NaCl}} = \text{0.4505 mol NaCl}$

(b) Moles of PbCl₂

$\text{Moles of PbCl${_2}$} = \text{0.4505 mol NaCl} * \frac{\text{1 mol PbCl${_2}$}}{\text{2 mol NaCl}} = \text{0.2253 mol PbCl${_2}$}$

(c) Theoretical yield of PbCl₂

$\text{Mass of PbCl${_2}$} = \text{0.2253 mol PbCl${_2}$} * \frac{\text{278.11 g PbCl${_2}$}}{\text{1 mol PbCl${_2}$}} = \text{61.52 g PbCl${_2}$}$

(d) Percent yield

$\text{Percent yield} = \frac{\text{ actual yield}}{\text{ theoretical yield}} * 100 \,\% = \frac{\text{52.1 g}}{\text{61.52 g}} * 100 \, \% = \mathbf{84.7 \,\%}\n\n\text{The percent yield is $\large \boxed{\mathbf{84.7 \, \% }}$}$

Which is not the name of a family on the periodic tablea) Halogens
b) Noble Gases
c) Alkali Earth Metals
d) Actinides

Answers

Answer:

I think it's D

Explanation:

Actinides is the correct answer
your noble gases are in the 8th column
Your Halogens are your 7th column
and you alkali earth metals are the 2nd column

How is energy transfer connected to your life

Answers

Answer:

Baking, microwave, heating system for your house, water boiler, fridge.

lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL?

Answers

Answer:

The concentration is 0.036 mg/mL

Explanation:

Concentration = 0.2 mM = 0.2/1000 = 2×10^-4 M = 2×10^-4 mol/L × 180,000 mg/1 mol × 1 L/1000 mL = 0.036 mg/mL

How many moles are in 12.0 grams of O2

Answers

Answer:

Moles = 0.375

Explanation:

Moles= m/M

= 12/32 = 0.375mol

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What is the hydronium (H3O+) concentration of a solution with a pH of 3.60? A. 2.5 × 10-4 M B. 3.0 × 10-4 M C. 4.0 × 10-11 M D. 4.5 × 10-11 M

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.572C↽−−⇀DK2=0.226 Calculate the value of the equilibrium constant for the reaction D − ⇀ ↽ − A + 2 B .

Consider the following reaction at equilibrium: NO2(g) + CO(g) = NO(g) + CO2(g) Suppose the volume of the system is decreased at constant temperature, what change will this cause in the system? A shift to produce more NO A shift to produce more CO A shift to produce more NO2 No shift will occur