An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm^3. of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture. Ag + (aq) + Fe2 + (aq) <==> Ag(s) + Fe3+ (aq) . What is the numerical value of Kc? . A 0.35 B 0.62 C 1.62 D 2.89

Answers

Answer 1

Answer: Kc = [Fe3+]/ ([Ag+] [Fe2+])
Initial concentrations [Ag+]= [Fe2+]= 1.0 mol/ dm^3 [Fe3+] =0.0 mol/dm^3
change: Ag+: (1.0 - .44) mol/dm^3 = 0.56 mol/ dm^3 = change of Fe2+. Change of Fe3+ is 0.56 mol/dm^3.
Equilibrium concentrations [Ag+] = [Fe2+] = 0.44 mol/dm^3 [Fe3+] = 0.56 mol/dm^3

Kc = 0.56/0.44^2 dm^3/mol = 2.89 dm^3 /mol

Answer 2

Answer:

Final answer:

The equilibrium constant Kc for the given reaction is calculated as [Fe3+]/[Ag+][ Fe2+] = 1.76, which is not among the provided answer choices.

Explanation:

To calculate the equilibrium constant, Kc, for the reaction Ag + (aq) + Fe2+ (aq) <==> Ag(s) + Fe3+ (aq), you need to know the concentrations of the ions at equilibrium. According to the question, the concentration of Ag+ is 0.44 mol/1.00 dm^3. Because AgNO3 completely dissociates into Ag+ and NO3- ions, the initial concentration of Fe2+ would also be 1.00 mol/dm^3. Given that the reaction has gone to completion, the concentration of Fe2+ at equilibrium would be 0.56 mol/dm^3 (1.00 - 0.44).

Furthermore, the reaction creates an equivalent amount of Fe3+, so its concentration at equilibrium would also be 0.44 mol/dm^3. Therefore, the equilibrium constant, Kc, is calculated as [Fe3+]/[Ag+][ Fe2+] = (0.44)/(0.44 * 0.56) = 1.76. Looking at the answer choices given, none of them matches with the calculated value. So, the correct value might be an option not mentioned here.

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While testing amylase activity, John uses a buffer of pH 6 and substrate starch. He incubates them at 104ºF (40ºC). All the tubes show glucose formation, except one, which had no starch solution. Why did this happen?A) the optimum pH for enzyme amylase is not pH 6
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Answers

While testing amylase activity, John uses a buffer of pH 6 and substrate starch. He incubates them at 104ºF (40ºC). All the tubes show glucose formation, except one, which had no starch solution because the substrate for amylase, starch, is not present so thats why it does not show glucose formation
so correct option is C
hope it helps

Answer:

Explanation:

Hydrogen bonding occurs in molecules when a _____________. (1 point)hydrogen atom forms a covalent bond with one other atom.
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Answers

Answer: hydrogen atom of a polarized molecule bonds with an electro negative atom.

Explanation:

Hydrogen bonds are special type of dipole dipole forces which are formed when hydrogen bonds with an electro negative element. Hydrogen bonds are strongest type of bonds .Example: Bond between Oxygen of one water molecule to the hydrogen of another water molecule as shown in the image below.

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Answer:

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Explanation:

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Answers

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Answers

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Answer:

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Answers

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Answers

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