What is the alpha decay of Radon-198?

Answers

Answer 1
Answer:

The alpha decay of Radon-198 produces alpha particle and ¹⁹⁴₈₄Po.

What is alpha decay?

Alpha decay is a type of radioactive disintegration in which some unstable atomic nuclei spontaneously expel an alpha particle to dissipate excess energy.

Alpha decay of Radon-198 is shown as:

¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po

In the above decay from the parent nuclei, daughter nuclei (¹⁹⁴₈₄Po) and alpha particle (⁴₂He) is produced.

Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.

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Answer 2
Answer: 86198Rn => 24He + 84194Po

The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.


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How many moles of chlorine, cl, are there in 8 moles of carbon tetrachloride, ccl4?
The following three solutions are mixed: 100.0mL of 0.100M Na₂SO₄, 50.0mL of 0.300M ZnCl₂, and 100.0mL of 0.200M Ba(CN)₂. Cyanide (CN-) solubilities are not in most tables, but Ba(CN)₂ is soluble, Zn(CN)₂ is not. a. What ionic compounds will precipitate out of solution? b. What is the molarity of each ion remaining in the solution, assuming complete precipitation of all insoluble compounds, and assuming that volumes are additive?

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

Answers

Ideal gas law is valid only for ideal gas not for vanderwaal gas. Charles' gas law is used here. Therefore the new volume of the balloon in the hot room is  3.68 L.

What is ideal gas equation?

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. Vanderwaal gas can behave as ideal gas low pressure and high temperature.

Mathematically the relation between Pressure, volume and temperature can be given as

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

V₁/T₁ = V₂/T₂

3.50 L ÷298 K = V₂÷313 K

V₂ =  3.68 L

Therefore the new volume of the balloon in the hot room is 3.68 L.

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yes, according to charles law, this would be equal to 3.68 L

Which of the following statements is true for an exothermic reaction? The products have higher potential energy than the reactants, and the enthalpy change is negative.
The products have higher potential energy than the reactants, and the enthalpy change is positive.
The products have lower potential energy than the reactants, and the enthalpy change is negative.
The products have lower potential energy than the reactants, and the enthalpy change is positive.

Answers

Ans: The products have lower potential energy than the reactants, and the enthalpy change is negative.

In general, chemical reactions can be broadly classified into two categories:

1) Exothermic

2) Endothermic

Exothermic reactionsproceed with the evolution of heat. Here, the reactants have a higher potential energy which is released as the reaction progresses to form products. Consequently, the products are in a lower energy state. Since energy is released, the enthalpy change will be negative.

In contrast, endothermic reactions proceed with the absorption of heat. Here,the products will be in a higher energy state. Since energy is absorbed, the enthalpy change will be positive.

The enthalpy change for an exothermic reaction is negative because heat is being released, so that takes out two of the responses. Since energy is being released into the surroundings due to the exothermic reaction, the potential energy of the products is lower than that of the reactants. Energy is being put in to make the reaction occur, but then that energy is all being released into the surroundings thus a lower potential energy level for the products

Can you give examples of carbon in our nonliving environment?

Answers

Carbon is present in many natural minerals and rocks, such as diamond, graphite, limestone. Also carbon dioxide gas, carbon monoxide gas.

How many grams of KOH used to make 1.6 liters of 15% by mass solution with water as the solvent?

Answers

Given:

KOH used to make 1.6 liters of 15% by mass solution with water

 

Required:

grams of KOH

 

solution:

the density of KOH is equal to 2.12 kg/L

multiply  the known volume of KOH to the density and the percentage of KOH in water

mass of KOH = 1.6 L (2.12 kg/L)(0.15) = 22.61 grams of KOH

Convert 55 kilometers per hour into meters per second. Use the conversion factor 1 km = 1000 m.55 ______/ _____ ´ 1000 _____/1 ______ ´ 1 ______/60 ______
´ 1 _____/60 _____ = 15 _____

Answers

Answer:

916.7 m/s

Explanation:

Given:

The value of speed = 55 km/hr

To determine:

The corresponding value in meters/second i.e m/s

Formula:

Step 1:

Convert km to m

1 km = 1000 m

Therefore, 55 km = 55 km * 1000 m/1 km = 55,000 m

The speed now is = 55,000 m/hr

Step 2:

Convert hr to sec

60 sec = 1 hr

Speed = 55,000 m/hr *  1 hr/60 sec = 916.7 m/s

55km/1hr x 1000m/1km x 1hr/60min x 1min/60sec =

(55 x 1000)/(60 x 60) =

55000/3600=

Answer: 15.28 m/sec

If 3.85 moles of aluminum (Al) metal, with a density of 2.70 g/mL, are needed for a chemical reaction, how many milliliters of aluminum are needed?Select one:
a. 1.43 mL Al
b. 18.9 mL Al
c. 38.5 mL Al
d. 281 mL Al

Answers

To find mL of Al needed, start by finding grams of Al that are being used in this reaction:
(3.85mol Al)(27.0g/mol Al)= 104g Al needed.

Since density is m/v, and we know the density and the mass, we can find the volume:
2.70g/mL = (104.g)/mL
Isolate mL:
(104.g)/(2.70g/mL) = 38.5mL needed which is answer C :)