MATHEMATICS COLLEGE

-189=4x-3(-4+15) WHAT IS THE ANSWER TO THIS PROBLEM?

Answers

Answer 1

Answer:

Answer:

4/15

Step-by-step explanation:

Answer 2

Answer:

Answer: x= -39

Step-by-step explanation: Let's solve your equation step-by-step.

−

189

−

(

−

)

Step 1: Simplify both sides of the equation.

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189

−

(

−

)

−

189

−

189

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Step 2: Flip the equation.

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189

Step 3: Add 33 to both sides.

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189

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156

Step 4: Divide both sides by 4.

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156

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What is the y-intercept of the line your equation X-1/2Y = -6A.-6

B.-3

C.0

D.12

Answers

9514 1404 393

Answer:

D. 12

Step-by-step explanation:

Set x=0 and solve for y.

0 -1/2y = -6

y = (-2)(-6) = 12 . . . . . . multiply by -2 to clear the fraction

The y-intercept is 12.

Please help it’s due at 5

Answers

Answer:

nei prossimi giorni, che si è svolto il convegno

One ticket is drawn at random from each of the two boxes.(A) 1 2 3 4 5

(B) 1 2 3 4 5 6

Find the chance that

(a) one of the number is 2 and the other is 5

(b) sum of the numbers is 7

(c) one number is bigger than twice the other

Answers

Answer:

a.1/15

b.1/6

c.1/3

Step-by-step explanation:

number of outcomes from box 1=5

number of outcomes from box 2=6

therefore total number of outcomes=6×5

=30

a. number of times receiving a ticket 2 and the other 5 =2

therefore probability= 2/30

=1/15

b.number of combinations for 7= 5 (1+6, 2+5,5+2,4+3,3+4.)

therefore probability= 5/30

=1/6

c.number of times one number was bigger than twice the other=10 (1+3,3+1,1+4,4+1,1+5,5+1,1+6,2+5,5+2,2+6)

therefore probability= 10/30

=1/3

Paired t‐Test for Mean Comparison with Dependent Samples To study the effects of an advertising campaign at a supply chain, several stores are randomly selected with the following observed before‐ and after‐advertising monthly sales revenues: Store number 1 2 3 4 5
Old sales revenue (mil. $) 5.2 6.5 7.2 5.7 7.6
New sales revenue (mil. $) 6.4 7.8 6.8 6.5 8.2
Let μ₁ and μ₂ be the means of old and new sales revenues, both in millions of dollars per month.
(a) At α = 0.05, test H0: μ2 ≤ μ1 versus H1: μ2 > μ1. Sketch the test. Interpret your result.
(b)Sketch and find the p‐value of the test. Would you reject H0 if α = 0.01?

Answers

Answer:

a) $t=(\bar d -0)/((s_d)/(√(n)))=(0.7 -0)/((0.678)/(√(5)))=2.308$

$p_v =P(t_((4))>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

b) The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Step-by-step explanation:

Part a

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

1=test value old , 2 = test value new

1: 5.2 6.5 7.2 5.7 7.6

2: 6.4 7.8 6.8 6.5 8.2

The system of hypothesis for this case are:

Null hypothesis: $\mu_2- \mu_1 \leq 0$

Alternative hypothesis: $\mu_2 -\mu_1 >0$

The first step is calculate the difference $d_i=y_i-x_i$ and we obtain this:

d: 1.2, 1.3, -0.4, 0.8, 0.6

The second step is calculate the mean difference

$\bar d= (\sum_(i=1)^n d_i)/(n)=0.7$

The third step would be calculate the standard deviation for the differences, and we got:

$s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =0.678$

The 4 step is calculate the statistic given by :

$t=(\bar d -0)/((s_d)/(√(n)))=(0.7 -0)/((0.678)/(√(5)))=2.308$

The next step is calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_((4))>2.308) =0.0411$

So the p values is lower than the significance level given 0.05, so then we can conclude that we reject the null hypothesis.

Part b

The p value is illustrated on the figure attached.

If we select $\alpha=0.01$ we see that $p_v >\alpha$ so then we have enough evidence to FAIL to reject the null hypothesis.

Solve the following quadratic equation. (x+12)^2=1 A. x = 11 and x = 13 B. x = -11 and x = -13 C. x = -11 and x = 13 D. x = 11 and x = -13Will make brainiest!!!

Answers

Answer:

Step-by-step explanation:

(x+12)^2=1

(x+12)= +or - 1

when

x+12=1

x=1-12 =-11

when

x+12=-1

x=-1-12 =-13

then

x=-11 and x= -13

Answer:

Step-by-step explanation:

Plato

Which of the following expressions has the greatest value when x=5? show how you arrived at your choice.2x^2+7

x^3-5/3

10x -2/ x-3

Answers

Answer:

2x^2+7

Step-by-step explanation:

Let x=5

2x^2+7

2 ( 5)^2 +7 = 2*25 +7 = 50+7 = 57

(x^3-5)/3

(5^3 -5)/3 = (125-5)/3 = 120/3 = 40

(10x -2)/ (x-3)

(10*5-2)/(5-3) = (50-2)/(2) = 48/2 = 24

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