Select all (there's more than one) of the below chemicals that would be insoluble in water.a
NH4OH
b
NaNO3
c
PbCrO4
d
SrSO4
e
K3PO4
f
AgClO4
g
HgCl2
h
FeCO3
i
NH4Br
j
Li2Cr2O7
Answers
FeCO₃ and PbCrO₄ is insoluble in water.
Explanation:
If any substance added to water and it form ions then it is soluble in water otherwise it is insoluble in water.
a. NH₄OH - soluble in water
b. NaNO₃ - soluble in water
C. PbCrO₄ is insoluble in water
d. SrSO₄ slightly soluble in water
e. K₃PO₄ - Soluble in water
f. AgClO₄- Highly Soluble in water
g. HgCl₂ - Slightly soluble in water
h. FeCO₃ - insoluble in water
i. NH₄Br - soluble in water
j. Li₂Cr₂O₇ - soluble in water
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The answers are (1) and (3). Because the number of atoms in magnesium is 12.
Further Explanation
The atomic number or proton number (symbol Z) of a chemical element is the number of protons found in the nucleus. The amount is identical to the amount of charge in the core. The atomic number uniquely identifies chemical elements. In uncharged atoms, the atomic number is also the same as the number of electrons. The sum of atomic numbers Z and the number of neutrons N gives the mass number A of an atom. Because protons and neutrons have roughly the same mass (and the mass of electrons is ignored for many purposes) and nucleon bond energy is always small compared to nucleon mass, when the atomic mass of each atom is expressed in units of integrated atomic mass (into a quantity called "mass relative isotope "), worth about 1% of all A. numbers. Atoms with the same atomic number Z but neutron N numbers are different, and therefore have different atomic masses, known as isotopes. More than three-quarters of the elements present in nature are in a mixture of isotope conditions, and the average mass of the isotope for the mixture of isotopes of an element (called relative atomic mass) in the environment on Earth, determines the standard atomic weight of the element. Historically, the weight of these atomic elements (compared to hydrogen) is the amount that can be measured by chemists in the 19th century.
The writing of the elemental symbol was introduced in the Middle Ages by John Dalton (1810) who made a very simple elemental symbol as a circle. Along with the development of the discovery of the element J.J Berzelius (1779-1848) made the symbol of the element that is used as the basis for writing the element symbol until now, with the provisions: one symbol element consisting of one letter, then the writing must be in capital letters. Two symbol elements consisting of two letters, then the writing with capital letters in the first letter, and lowercase letters for the second.
The chemical formula of a substance states the type and the relative number of atoms contained in that substance. The number that states the number of atoms of an element in a chemical formula is called the index number. Chemical formulas may be either molecular formulas or empirical formulas.
The formula could be a formula that states the number of atoms of the weather that frame one molecule of a compound. So the molecular formula expresses the actual arrangement of matter molecules.
Learn more
definition of The atomic number brainly.com/question/564750
definition of The writing of the elemental symbol brainly.com/question/564750
Details
Grade: High School
Subject: Chemistry
keywords: The atomic number
H20(g)
1. Balance the equation above by putting coefficients into each blank space.
1C5H12+ 8O2----- 5CO2+ 6 H2O (this is what I got)
2. How many atoms of oxygen are in 144 grams of pentane?
step 1: 144g of C5H12*(1mole/72.17)= 1.995moles of C5H12
step 2: 1.995moles of C5H12*(8moles of O2/1mole of C5H12)= 15.962 moles of O2
step 3: 15.962 moles of O2*(6.02*10^23 atoms of O2/1mole of O2)= 9.609*10^24 atoms of O2 (I don't know if I did this right)
3. How many atoms of oxygen are in 192 grams of carbon dioxide gas?
step 1: 192 grams of CO2 *(1mole of CO2/44.01grams of CO2)= 4.363 moles of CO2
step two: 4.36moles of CO2* ( 1 mole of O2/1mole of CO2)=
step 3: 4.363* (6.02*10^23) = 2.627*10^24 atoms of O2 (I don't know if this is correct.
4. A) CIRCLE ONE: True or False:
reactant you begin with fewer grams of is your limiting reactant.
B) If 32 g of oxygen gas and 32 g of pentane are combined, how much water will be produced, in moles? (Use your reaction from the top of the first page)
NEED HELP ASAP THANK YOU!!!
Answers
2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol
Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen
Step 3: 16= 9.6*10^24
3) The ratio of oxygen to carbon in CO2 is 1:2
so it's 192/3 = 64
64*2=128g
Moles = Mass/Mr = 128/32 = 4mol = 2.41*10^24 atoms of oxygen
Basically you needed to work out the mass of oxygen using ratios before using a moles equation instead of just working with moles
4) True
5) 1C5H12+ 8O2----- 5CO2+ 6 H2O
32g 32g
Moles of oxygen = Mass/Mr = 32/32= 1mol so you'd need 0.125mol of pentane to react fully
Moles of pentane= Mass/Mr = 32/72=0.4mol so you'd need 3.2mol of oxygen to react fully
This makes oxygen the limiting factor, because you need more of it to react fully with the pentane, so we use oxygen
Stoichiometry means for every 8mol of oxygen there's 5mol of CO2
So, 1/8*5=0.635mol of CO2
Answers
------------ * ---------------- =19.88 mol O2
4 mol Al 1mol Al
Answer:
39.75 mol O2
that will be the answer
Explanation:
(2) HClO2 (gram-formula mass = 68 g/mol)
(3) HClO3 (gram-formula mass = 84 g/mol)
(4) HClO4 (gram-formula mass = 100. g/mol)
Answers
The percentage mass composition of chlorine in HClO₃ is 42%.
What is the percentage mass composition of chlorine in each compound?
Percentage mas of chlorine is calculated as follows:
- Percentage mass composition = mass of element * 100%/mass of compound
atomic mass of chlorine = 35.5
(1) In HClO (gram-formula mass = 52 g/mol)
Percentage mass composition = 35 * 100% / 52 = 67.3%
(2) In HClO2 (gram-formula mass = 68 g/mol)
Percentage mass composition = 35 * 100%/68 = 51.4%
(3) HClO3 (gram-formula mass = 84 g/mol)
Percentage mass composition = 35 * 100% / 84 = 42%
(4) HClO4 (gram-formula mass = 100. g/mol)
Percentage mass composition = 35 * 100% / 100 = 35.5%
Therefore, the percentage mass composition of chlorine in HClO₃ is 42%.
Learn more about percentage mass composition at: brainly.com/question/18646836
Final answer:
None of the compounds have a percent composition of chlorine equal to 42%.
Explanation:
To find the compound with a percent composition of chlorine equal to 42%, we calculate the mass of chlorine in each compound and calculate the percent composition. Let's go through each option:
- HClO: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (35.5/52) * 100% ≈ 68.3%. Not equal to 42%
- HClO2: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (2 * 35.5/68) * 100% ≈ 104.4%. Not equal to 42%.
- HClO3: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (3 * 35.5/84) * 100% ≈ 150%. Not equal to 42%.
- HClO4: H = 1g/mol, Cl = 35.5g/mol. Percent composition of Cl = (4 * 35.5/100) * 100% = 142%. Not equal to 42%.
None of the compounds have a percent composition of chlorine equal to 42%. The correct answer is none of the above.
Learn more about Percent composition of chlorine here:
#SPJ12
(2) neutron (4) positron
Answers
The subatomic particle which will be attracted by a positively charged object is: Choice 3: Electrons.
By law of electricity; like charges repel while unlike charges attract.
In essence, the subatomic particle which will be attracted to a positively charged object is a negatively charged particle.
Since, protons are positively charged, neutrons have no charge, positrons are positively charged but electrons are negatively charged,
The subatomic particle which will be attracted by a positively charged object is; Electron.
Read. more:
(2) Neutrons have no charge, so won't be affected by positive charges
(3) Electrons have a negative charge, so will be attracted by a positive charge
(4) Positrons have a positive charge, so will be repelled by other positive charges
The answer is (3)