CHEMISTRY HIGH SCHOOL

Butyric acid is responsible for the odor in rancid butter. A solution of 0.25 m butyric acid has a ph of 2.71. What is the ka for the acid?

Answers

Answer 1

Answer:

Answer:

Ka = 1.5 -10^-5

Explanation:

Step 1: Data given

Molarity of the solution = 0.25 M

pH = 2.71

Step 2 The equation

C3H7COOH + NaOH ⇆ C3H7COONa + H2O

Step 3: Calculate pKa

pH = (pKa-log[acid])/2

2pH = pKa -log[acid]

pKa = 2pH +log[acid]

⇒with pH = 2.71

⇒with log[acid] = -0.60

pKa=2*2.71 -0.60

pKa = 5.42 - 0.60

pKa = 4.82

Step 4: Calculate Ka

pKa = -log(Ka)

Ka = 10^-4.82

Ka = 1.5 -10^-5

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For each of the following strong base solutions, determine [OH−],[H3O+], pH, and pOH of 1.13×10^−2 M Ba(OH)2, 1.8x10^-4 M KOH, and 5.3x10^-4 M Ca(OH)2

Answers

pH calculations of strong base solutions are pretty direct. It all depends on how many OH- ions are dissociated and the concentration of the solution.

Ba(OH)2:

Since there are 2 OH- ions, the concentration of [OH-] is twice the concentration of the solution. Take the pOH by using the equation pOH = -log[OH-]. From here, you can get the pH by subtracting the pOH from 14. Finally, calculate the [H3O+] or [H+] concentration by using the equation pH = -log[H+] or [H+] = 10^(-pH)

[OH-] = 2 x 1.13x10^-2 M = 2.26x10^-2
pOH = -log[OH-] = 1.65
pH = 14 - 1.65 = 12.35
[H3O+] = 10^(-12.35) = 4.47x10^-13

Follow the same rule for the other compounds.

KOH:

[OH-] = 1.8x10^-4 M
pOH = -log[OH-] = 3.74
pH = 14 - 3.74 = 10.26
[H3O+] = 10^(-10.26) = 5.50x10^-11

Ca(OH)2:
[OH-] = 2 x 5.3x10^-4 M = 1.06x10^-3 M
pOH = -log[OH-] = 2.97
pH = 14 - 2.97 = 11.03
[H3O+] = 10^(-11.03) = 9.33x10^-12

What is the volume of 70.0 g of ether if the density of isether 0.70 g/mL

Answers

D = m / V

0.70 g/mL = 70.0 g / V

V = 70.0 / 0.70

V = 100 mL

hope this helps!

Write the balanced equation for the reaction that occurs when methanol, CH3OH (I) is burned in air. What is the coefficient of methanol in the balanced equation? (A) 1 (B) 3 (C) 2 (D) 4 (E) 3/2

Answers

Answer:

Explanation:

Methanol is an organic compound which burns with oxygen to produce carbon dioxide and water.

$2CH_3OH_((l))+3O_2_((g))\rightarrow 2CO_2_((g))+4H_2O_((g))$

Multiply coefficients times subscripts for each element in the formula, We get that there are 2 number of atoms of the carbon, 8 number of atoms of the hydrogen, and 8 number of atoms of the oxygen on both sides of equation. Hence, it is balanced.

The coefficient of methanol from the balanced reaction is 2.

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Answers

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Answer:

Pretty sure, don't quote me on this, but I think that the answer is the magma. So sorry if I'm wrong! Learned this last year and it was a brief recap so don't remember the exact answer.

Explanation:

Justify water is compound

Answers

Water is a compound. A compound is made up of two or more elements. In the case of water, or H2O, there are 2 hydrogen atoms present and 1 oxygen atom. I hope this helps you on your assignment. Good luck!

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Answers

Describe how the catalyst, zymase speeds up the reaction shown

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