What is the probability of a die coming up with the number 10?

Answers

Answer 1
Answer:

Answer:

0

Step-by-step explanation:

0 is the probability of a die coming up with the number 10

because a die contains numbers from 1 to 6 so probability of numbers coming between are possible but 10 is not possible


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Solve the equations 5x-8y=145x-7y=6
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The sum of the squares of two consecutive odd positive integers is 74. Find the integers.

Answers

Let first odd number be x

Then that would be x^2 + (x+2)^2=74. We need to solve for x.

x^2 + (x+2)^2=74\n\ \nx^2 + x^2 + 4x+4 = 74\n\ \n2x^2 + 4x +4=74\n\ \n2x^2+4x-70 = 0\n\ \n2(x^2+2x-35)=0\n\ \n2(x+7)(x-5)=0\n\ \nx=-7\text{ or }5

But we need positive integers so we would have \boxed{x=5}, so then our integers would be x, x+2 = 5, 7

Check work:

5² + 7² = 25 + 49 = 74.

So our integers would be 5 and 7.

Hope this helps.
Let’s use a sample set.
Let’s use 5 and 7.
5•5=25
7•7=49
49+25=74
The integers are 5 and 7. The way I found this was by thinking of 9 and 11 at first. I knew that it would be entirely way too much, but 3 and 1 would be too little. 5 and 7 fit in the middle of those two samples.

Your answer is 5 and 7.

In a large university, 20% of the students are business majors. A random sample of 100 students is selected, and their majors are recorded. a) Compute the standard error of the proportion. b) What is the probability that the sample contains at least 12 business majors

Answers

Answer:

a. 0.04

b. 0.9772

Step-by-step explanation:

Please check attachment for complete solution and step by step explanation

Final answer:

The standard error of the proportion is 0.04. The probability of having at least 12 business students in a sample of 100 can be found by using the binomial distribution formula, though precise calculation would require the use of statistical software.

Explanation:

In a large university, 20% of students are business majors. The question is asking about the standard error and the probability of having at least 12 business students in a random sample of 100 students.

a) The standard error (SE) of the proportion is calculated as the square root of [p(1-p)/n], where 'p' is the proportion of business majors (0.2 in this case)and 'n' is the sample size (100 in this case). So, the SE = sqrt[(0.2)(0.8)/100] = sqrt[0.0016] = 0.04.

b) In order to calculate the probability that there are at least 12 business students, we would use the binomial distribution. Using the binomial distribution formula P(X >= x) = 1 - P(X < x), where 'X' is a random variable representing the number of business majors, and 'x' is 12. Since the calculation is tedious, one would use statistical software or a calculator to find this probability. Typically, the result would be greater than 0.

Learn more about Probability and Standard Error here:

brainly.com/question/33667940

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A right cone with a radius of 4 inches and a square pyramid both have a slant height of 5 inches. Both solids have the same surface area. Find the length of a base edge of the pyramid. Round your answer to the nearest hundredth.

Answers

The surface area of the cone is given by:
SA=πrl
Thus the surface area of the cone will be:
SA=π×4×5
SA=20π=63.932

Surface area of the pyramid is given by:
SA=1/2×4×(b×l)
thus the base length will be:
63.932=10l
thus
l=6.3932 in

3 times the sum of one third of a number and 8 is 11

Answers

Answer:

3((1)/(3)x+8)=11

Step-by-step explanation:

It says 3 times the sum of one third of a number and 8, so we group that expression into the parentheses. Since there is a key word is, we need to put an equal sign.

What are the factors of the product represented below?TILES
A. (2x2 + 1)(3x2 + 1)
+
B. (5x + 1)(x+1)
C. (2x + 1)(3x + 1)
O D. (3x + 1)(2x+2)

Answers

Answer:

C

Step-by-step explanation:

The top is 2x + 1 and the left is 3x + 1

Answer:

C

The top is 2x + 1 and the left is 3x + 1

Plz help me simply this

Answers

Answer:

Step-by-step explanation:

\sqrt[5]{u^(10)*p^(15)}*\sqrt[4]{u^(16)*p^(18)}=  \sqrt[5]{u^(2*5)*p^(3*5)}*\sqrt[4]{u^(4*4)*p^(16*2)}\n\n\n=\sqrt[5]{(u^(2))^(5)*(p^(3))^(5)}*\sqrt[4]{(u^(4))^(4)*p^(4*4)*p^(2)}\n\n=\sqrt[5]{(u^(2))^(5)*(p^(3))^(5)}*\sqrt[4]{(u^(4))^(4)*(p^{4)^(4)}*p^(2)}\n\n=u^(2)*p^(3) * u^(4)*p^(4)*\sqrt[4]{p^(2)}\n\n=u^(2+4)*p^(3+4)*\sqrt[4]{p^(2)}\n\n= u^(6)p^(7)\sqrt[4]{p^(2)}