PHYSICS COLLEGE

The switch in the circuit has been in the left position for a long time. At t=0 it moves to the right position and stays there.a. Write the expression for the capacitor voltage v(t), fort≥0. b. Write the expression for the current through the 2.4kΩ resistor, i(t), fort≥0+.

Answers

Answer 1

Answer:

Pls refer to attached file

Explanation:

The block slide on the horizontal surface is "24.99 m" far.

According to the question,

Vertical height = 5.0 m
Coefficient of friction = 0.20

Let,

The time taken be "t".

Now,

→ $s = ut+ (1)/(2) at^2$

By substituting the values, we get

$5 = (1)/(2)* 9.8* t^2$

$t = 1.01 \ sec$

The final velocity will be:

→ $v_1 = gt$

$= 9.8* 1.01$

$= 9.899 \ m/s$

Now,

→ $t = (u)/(a)$

$= (9.899)/(0.2* 9.8)$

$= 5.05 \ seconds$

hence,

The distance will be:

→ $s = ut+0.5* at^2$

$= 9.899(5.05)-0.5* (0.2* 9.8* 5.05^2)$

$= 24.99 \ m$

Thus the above approach is right.

Learn more about friction here:

brainly.com/question/18851133

Answer:

The block slides on the horizontal surface 25 m before coming to rest.

Explanation:

Hi there!

For this problem, we have to use the energy-conservation theorem. Initially, the block has only gravitational potential energy (PE) that can be calculated as follows:

PE = m · g · h

Where:

m = mass of the block.

g = acceleration due to gravity.

h = height at which the block is located.

As the block starts to slide down the track, its height diminishes as well as its potential energy. Due to the conservation of energy, energy can´t disappear, so the loss of potential energy is compensated by an increase of kinetic energy (KE). In other words, as the block slides, the potential energy is converted into kinetic energy. The equation of kinetic energy is the following:

KE = 1/2 · m · v²

Where:

m = mass of the block.

v = speed of the block.

Then, at the bottom of the ramp, the kinetic energy of the block will be equal to the potential energy that the block had at the top of the ramp.

Initial PE = KE at the bottom

When the block starts sliding horizontally, friction force does work to stop the block. According to the energy-work theorem, the change in the kinetic energy of an object is equal to the net work done on that object. In other words, the amount of work needed to stop the block is equal to its kinetic energy. Then, the work done by friction will be equal to the kinetic energy of the block at the bottom, that is equal to the potential energy of the block at the top of the track:

initial PE = KE at the bottom = work done by friction

The work done by friction is calculated as follows:

W = Fr · Δx

Where:

W = work

Fr = friction force.

Δx = traveled distance.

And the friction force is calculated as follows:

Fr = μ · N

Where:

μ = coefficient of friction.

N = normal force.

Since the block is not accelerated in the vertical direction, in this case, the normal force is equal to the weight (w) of the block:

Sum of vertical forces = ∑Fy = N - w = 0 ⇒N = w

And the weight is calculated as follows:

w = m · g

Where m is the mass of the block and g the acceleration due to gravity.

Then, the work done by friction can be expressed as follows:

W = μ · m · g · Δx

Using the equation:

intial PE = work done by friction

m · g · h = μ · m · g · Δx

Solving for Δx

h/μ = Δx

5.0 m / 0.20 = Δx

Δx = 25 m

The block slides on the horizontal surface 25 m before coming to rest.

URGENT!!!!!! Assume that a wire has 1.5 ohms of resistance. If the wire is connected to two batteries with a total voltage of 3.0 V, how much current will flow through the wire? 3.0 amps 2.3 amps 2.0 amps 1.0 amps

Answers

Answer:

2.0 amps

Explanation:

Current is the ratio of voltage to resistance:

I = V/R = (3.0)/(1.5) = 2.0

The current in the wire is 2.0 amps.

Find the linear velocity of a point moving with uniform circular motion, if the point covers a distance s in the given amount of time t. s

Answers

Answer:

The linear velocity is represented by the following expression: $v = (s)/(t)$

Explanation:

From Rotation Physics we know that linear velocity of a point moving with uniform circular motion is:

$v = r\cdot \omega$ (Eq. 1)

Where:

$r$ - Radius of rotation of the particle, measured in meters.

$\omega$ - Angular velocity, measured in radians per second.

$v$ - Linear velocity of the point, measured in meters per second.

But we know that angular velocity is also equal to:

$\omega = (\theta)/(t)$ (Eq. 2)

Where:

$\theta$ - Angular displacement, measured in radians.

$t$ - Time, measured in seconds.

By applying (Eq. 2) in (Eq. 1) we get that:

$v = (r\cdot \theta)/(t)$ (Eq. 3)

From Geometry we must remember that circular arc ( $s$ ), measured in meters, is represented by:

$s = r\cdot \theta$

$v = (s)/(t)$

The linear velocity is represented by the following expression: $v = (s)/(t)$

A foot is 12 inches and a mile is 5280I ft exactly. A centimeter is exactly 0.01m or mm. Sammy is 5 feet and 5.3tall. what is Sammy's height in inches?

Answers

Answer:

65.3 Inches tall

Explanation:

If Sammy is 5 feet and 5.3 inches tall, we simply need to convert the feet to inches, and sum the remaining inches from his height to determine his overall height in inches.

So, 5 feet = (12 inches/1foot) * (5 feet) = 60 inches

And 60 inches + 5.3 inches = 65.3 inches.

Hence, Sammy is 65.3 inches tall.

Cheers.

A small metal bead, labeled A, has a charge of 28 nC .It is touched to metal bead B, initially neutral, so that the two beads share the 28 nC charge, but not necessarily equally. When the two beads are then placed 5.0 cmapart, the force between them is 4.8×10^−4 N . Assume that A has a greater charge. What is the charge qA and qB on the beads?

Answers

Answer:

Explanation:

Let the charge on bead A be q nC and the charge on bead B be 28nC - qnC

Force F between them

4.8\times10^{-4} = $(9*10^9* q*(28-q)*10^(-18))/((5*10^(-2))^2)$

=120 x 10⁻⁸ = 9 x q(28 - q ) x 10⁻⁹

133.33 = 28q - q²

q²- 28q +133.33 = 0

It is a quadratic equation , which has two solution

q_A = 21.91 x 10⁻⁹C or q_B = 6.09 x 10⁻⁹ C

When the sun and moon pull at right angles to the earth wat kinda tide can yu expect

Answers

Answer:

A neap tide. Hope this helps

Explanation:

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The switch in the circuit has been in the left position for a long time. At t=0 it moves to the right position and stays there.a. Write the expression for the capacitor voltage v(t), fort≥0. b. Write the expression for the current through the 2.4kΩ resistor, i(t), fort≥0+.

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