PHYSICS COLLEGE

When a tennis ball is spun around in a circle on a string and the string breaks the tennis ballwill be pulled in a curved path away from the center because of Centrifugal force
True or false

Answers

Answer 1
Answer:

Answer:

False

whenever the string breaks, the ball will follow the straight line tangential path

Explanation:

No, the ball will not follow a curved path after the string breaks. Since, the the direction of velocity is tangential to each point of the circular motion. Therefore, it changes at every point. This produces an acceleration in the circle called centripetal acceleration. There is also a tangential component of acceleration acting on the ball during this motion.

So, whenever the string breaks, the ball will follow the straight line tangential path. Hence, the given statement is false.

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A electromagnetic wave of light has a wavelength of 500 nm. What is the energy (in Joules) of the photon representing the particle interpretation of this light?
Find the force necessary to start the crate moving, given that the mass of the crate is 32 kg and the coefficient of static friction between the crate and the floor is 0.57. Express your answer using two significant figures.
In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 48 N to the input piston, which has a radius r1. As a result, the output plunger, which has a radius r2, applies a force to the car. The ratio r2/r1 has a value of 9.0. Ignore the height difference between the input piston and output plunger and determine the force that the output plunger applies to the car.
A curve of radius 35 m isbanked; therefore, no frictionis required at a speed of 7m/s of a car. What is the?banking angle ​
A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 4.9 m. The total mass of the empty balloon and basket is mb = 121 kg and the total volume is Vb = 0.073 m3. Assume the average person that gets into the balloon has a mass mp = 73 kg and volume Vp = 0.077 m3. 1)What is the volume of helium in the balloon when fully inflated? m3 2)What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium. N

A 84-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.73 as. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.4 s, and then comes to rest.What does the spring scale register During the first 0.80s of the elevator’s ascent?

Answers

Answer:

SR=949.2N

Explanation:

From the question we are told that:

Mass M=84kg

Speed V=1.2m/s

Acceleration Time t_a=0.73

Constant speed Timet_s=5.0s

Deceleration time t_d=1.4s

Generally the equation for Acceleration is mathematically given by

a=(v)/(t)

Therefore acceleration for the first 0.80 sec is

a=(1.2)/(0.80)

a=1.5m/s^2

Therefore

Spring Reading=Normal force -Reaction

SR=m(g+a)

SR=84(9.8+1.5)

SR=949.2N

1. A surfboarder rides a wave for 23.7 m at a constant rate of 4.1 m/s. How long did his triptake?

Answers

Answer:

His trip took 5.78 seconds

Explanation:

23.7m divided by 4.1m/s = 5.78048780488

____ can be calculated if you know the distance that an object travels in one unit of time. A.motion
B.meter
C.Rate
D.Speed
E.velocity
F.slope
G.refrence point

PLS HELP NOW !!!

Answers

Speed can be calculated if you know the distance that an object travels in one unit of time, therefore the correct answer is option D.

What is speed?

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

Thus, Speed can be calculated if you know the distance that an object travels in one unit of time, therefore the correct answer is option D.

Learn more about speed from here, refer to the link;

brainly.com/question/7359669

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Answer:

D.Speed

Explanation:

The speed of an object is the distance the object travels in one unit of time.

Two cylinders with the same mass density rhoC = 713 kg / m3 are floating in a container of water (with mass density rhoW = 1025 kg / m3). Cylinder #1 has a length of L1 = 20 cm and radius r1 = 5 cm. Cylinder #2 has a length of L2 = 10 cm and radius r2 = 10 cm. If h1 and h2 are the heights that these cylinders stick out above the water, what is the ratio of the height of Cylinder #2 above the water to the height of Cylinder #1 above the water (h2 / h1)? h2 / h1 =

Answers

Answer:

Explanation:

Given

density of cylinder is \rho _c=713 kg/m^3

Length of first cylinder is L_1=20 cm

radius r_1=5 cm

For cylinder 2 L_2=10 cm

r_2=10 cm

h_1 and h_2 are the height above water

E

as object is floating so its weight must be balanced with buoyant force

\rho _c(\pi )/(4)d_1^2L_1g=\rho _w(\pi )/(4)d_1^2(L_1-h_1)g----1

For 2nd cylinder

\rho _c(\pi )/(4)d_2^2L_2g=\rho _w(\pi )/(4)d_2^2(L_2-h_2)g----2

Dividing 1 and 2 we get

(L_1)/(L_2)=(L_1-h_1)/(L_2-h_2)

(20)/(10)=(20-h_1)/(10-h_2)

2h_2=h_1

\n\Rightarrow(h_2)/(h_1)=(1)/(2)                            

An object rests on a horizontal floor.the coefficient static friction is0.4 and acceleration of gravity is 9.8m/sdetermine the maximum force of the static friction and the minimum force of F​

Answers

Answer:

first of all since the value of mass of the object and force F(horizontal) or the relation between them is not mentioned , so there can be multiple effects and let us study them in cases.

Let us consider that mass of the object is m and the coefficient of friction is the coefficient of static friction of the surface{since friction can be static as well as dynamic} whose value(μ) as is given in the question is 0.2. Since the surface and the force applied are both horizontal so there will be no vertical component of the force applied which means that the normal force is N=weight of the object=mg where g is the acceleration due to gravity(9.8 m/s^2 on average on surface of earth).

Case 1:

When F<=μN. This means that when the value of F is less than or equal to μN then the static friction is equal to F. So the body remains stationary.

Case 2:

When F>μN. This means that when the value of F is greater than μN then the static friction is less than F. So the body starts moving and if the force applied F is constant then the body will start accelerating because coefficient of kinetic friction is less than that of static friction.

Explanation:

When an object rests on a horizontal floor. the coefficient of static friction is 0.4 and the acceleration of gravity is 9.8m/s, then the maximum force of friction would be 1.962M and the minimum force of friction would be zero when no external force is applied, where M represents the mass of the object

What is friction?

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

When an object is beginning to move as a result of an external force, limiting friction is involved. This frictional force balances the external force until the object is in a condition where it remains stationary.

maximum Frictional force= μN

where  μ is the coefficient of static friction

N is the normal reaction force having a value of mg

Thus, The maximum force of friction would be 1.962M, and the minimum force would be zero

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What is the magnitude and direction of the electric field atradiaConsider a coaxial conducting cable consisting of a conductingrod of radius R1 inside of a thin-walled conducting shell of radius 2(both are infinite length). Suppose the inner rod hasradiusR1= 1.3 mm and outer shell has radiusR2= 10R1Ifthe net charge density on the center rod isq1= 3.4×10−12C/mand the outer shell isq2=−2q1,a.)What is the magnitude and direction of the electric field atradial distancer= 5R1from the center rod

Answers

Answer:

 E = 9.4 10⁶ N / C,     The field goes from the inner cylinder to the outside

Explanation:

The best way to work this problem is with Gauss's law

             Ф = E. dA = qint / ε₀

 

We must define a Gaussian surface, which takes advantage of the symmetry of the problem. We select a cylinder with the faces perpendicular to the coaxial.

The flow on the faces is zero, since the field goes in the radial direction of the cylinders.

The area of ​​the cylinder is the length of the circle along the length of the cable

         dA = 2π dr L

          A = 2π r L

They indicate that the distance at which we must calculate the field is

         r = 5 R₁

         r = 5 1.3

         r = 6.5 mm

The radius of the outer shell is

         r₂ = 10 R₁

         r₂ = 10 1.3

         r₂ = 13 mm

         r₂ > r

When comparing these two values ​​we see that the field must be calculated between the two housings.

Gauss's law states that the charge is on the outside of the Gaussian surface does not contribute to the field, the charged on the inside of the surface is

         λ = q / L

         Qint = λ L

Let's replace

      E 2π r L = λ L /ε₀

       E = 1 / 2piε₀  λ / r

Let's calculate

         E = 1 / 2pi 8.85 10⁻¹²  3.4 10-12 / 6.5 10-3

         E = 9.4 10⁶ N / C

The field goes from the inner cylinder to the outside
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