A helium balloon ride lifts up passengers in a basket. Assume the density of air is 1.28 kg/m3 and the density of helium in the balloon is 0.18 kg/m3. The radius of the balloon (when filled) is R = 4.9 m. The total mass of the empty balloon and basket is mb = 121 kg and the total volume is Vb = 0.073 m3. Assume the average person that gets into the balloon has a mass mp = 73 kg and volume Vp = 0.077 m3. 1)What is the volume of helium in the balloon when fully inflated? m3 2)What is the magnitude of the force of gravity on the entire system (but with no people)? Include the mass of the balloon, basket, and helium. N

Answers

Answer 1
Answer:

Answer:

1) The volume of helium in the ballon when is fully inflated is 492.8070 m³

2) The magnitude of the force of gravity (with no people) is 869.3119 N

Explanation:

Given:

ρair = density of air = 1.28 kg/m³

ρhelium = density of helium = 0.18 kg/m³

R = radius of balloon = 4.9 m

mtotal = 121 kg

Vtotal = 0.073 m³

mp = average mass per person = 73 kg

Vp = 0.077 m³

g = gravity = 9.8 m/s²

Questions:

1) What is the volume of helium in the balloon when fully inflated, Vhelium = ?

2) What is the magnitude of the force of gravity on the entire system (but with no people), Fg = ?

1) The volume of helium in the ballon when is fully inflated

V_(helium) =(4)/(3) \pi R^(3) =(4)/(3) \pi *4.9^(3) =492.8070m^(3)

2) First, you need to calculate the mass of helium

m_(helium) =\rho _(helium) *V_(helium) =0.18*492.8070=88.7053kg

The magnitude of the force of gravity (with no people)

F_(g) =m_(helium) *g=88.7053*9.8=869.3119N


Related Questions

The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole human bodies has a field strength of 5.81 T, and the current in the solenoid is 3.79 × 102 A. What is the number of turns per meter of length of the solenoid?
At what temperature will silver have a resistivity that is two times the resistivity of iron at room temperature? (Assume room temperature is 20° C.)
Of the four most important pathways by which stress affects health, the first one to occuris usually related to physiology
The most soaring vocal melody is in Johann Sebastian Bach's Mass in B minor. In one section, the basses, tenors, altos, and sopranos carry the melody from a low D to a high A. In concert pitch, these notes are now assigned frequencies of 146.8 Hz and 880.0 Hz. (Use 343 m/s as the speed of sound, and 1.20 kg/m3 as the density of air.)a. Find the wavelength of the initial note.b. Find the wavelength of the final note.c. Assume the choir sings the melody with a uniform sound level of 70.0 dB. Find the pressure amplitude of the initial note.d. Find the pressure amplitude of the final note.e. Find the displacement amplitude of the initial note.f. Find the displacement amplitude of the final note.
A suspended platform of negligible mass is connected to the floor below by a long vertical spring of force constant 1200 N/m. A circus performer of mass 70 kg falls from rest onto the platform from a height of 5.8 m above it. Find the maximum spring compression

Consult Interactive Solution 7.10 for a review of problem-solving skills that are involved in this problem. A stream of water strikes a stationary turbine blade horizontally, as the drawing illustrates. The incident water stream has a velocity of 16.0 m/s, while the exiting water stream has a velocity of -16.0 m/s. The mass of water per second that strikes the blade is 48.0 kg/s. Find the magnitude of the average force exerted on the water by the blade.

Answers

Explanation:

Initial speed of the incident water stream, u = 16 m/s

Final speed of the exiting water stream, v = -16 m/s

The mass of water per second that strikes the blade is 48.0 kg/s.

We need to find the magnitude of the average force exerted on the water by the blade. The force acting on an object is given by :

F=(m(v-u))/(t)

Here, (m)/(t)=48\ kg/s

F=48* (-16-16)\ N\n\nF=-1536\ N\n\n|F|=1536\ N

So, the magnitude of the average force exerted on the water by the blade is 1536 N.

Two cars, a Porsche Boxster convertible and a Toyota Scion xB, are traveling at constant speeds in the same direction. Suppose, instead, that the Boxster is initially 170 m behind the Scion. The speed of the Boxster is 24.4 m/s and the speed of the Scion is 18.6 m/s. How much time does it take for the Boxster to catch the Scion

Answers

Answer:

It will take 29.31 seconds for the Boxster to catch the Scion

Explanation:

Given the data in the question;

lets say Toyota Scion xB is car A and Porsche Boxster convertible is B and Toyota Scion xB is car A

the distance travelled by car A is

x = V_(A) × t

where  V_(A) is the speed of the car and t is time

the distance travelled by car B before reaching car A will be;

x + x₀ = V_(B) × t

Now lets replace x by V_(A) × t

so

(V_(A) × t) + x₀ = V_(B) × t

x₀ = (V_(B) × t) - (V_(A) × t)

x₀ = t (V_(B) - V_(A))

t = x₀ /  (V_(B) - V_(A))

so we substitute

t = 170 m  /  (24.4 - 18.6)  

t = 170 / 5.8

t = 29.31 s

Therefore; it will take 29.31 s for the Boxster to catch the Scion

HELP ASAP PLEASE!!!In which direction(s) does the ground shake during an earthquake?
A. sideways
B. up and down
C. back and forth
D. all of the above

Answers

Answer: D i am pretty sure

Explanation:

Answer:

all

Explanation:

A conveyor belt is used to move sand from one place to another in a factory. The conveyor is tilted at an angle of 18° above the horizontal and the sand is moved without slipping at the rate of 2 m/s. The sand is collected in a big drum 5 m below the end of the conveyor belt. Determine the horizontal distance between the end of the conveyor belt and the middle of the collecting drum.

Answers

The motion of sand is due to the movement of conveyor belt. The horizontal distance between the end of the conveyor belt and the middle of the collecting drum is 2.044 meters.

What is equation of motion?

The equation of motion is the relation between the distance, velocity, acceleration and time of a moving body.

The second equation of the motion for distance can be given as,

y=ut+(2)/(2)gt^2

Here, u is the initial body, g is the acceleration of the body due to gravity and t is the time taken by it.


Given information-

The conveyor is tilted at an angle of 18° above the horizontal.

The Sand is moved without slipping at the rate of 2 m/s.

The sand is collected in a big drum 5 m below the end of the conveyor belt.

The horizontal component of the velocity is given as,

v_y=2\cos 18

The vertical component of the velocity is given as,

v_y=2\sin18

Put the value in the above equation as,

y-y_0=v_yt+(1)/(2)gt^2

0-5=2\sin18 (t)+(1)/(2)*9.8\tiems t^2\nt=1.075\rm sec

The horizontal distance between the end of the conveyor belt and the middle of the collecting drum is,

d=v_xt\nd=2\cos18*1.075\nd=2.044\rm m

Thus, the horizontal distance between the end of the conveyor belt and the middle of the collecting drum is 2.044 meters.

Learn more about the equation of motion here;

brainly.com/question/13763238

Answer:

x = 2.044 m

Explanation:

given data

initial vertical component of velocity = Vy = 2sin18

initial horizontal component of velocity = Vx = 2cos18

distance from the ground yo = 5m

ground distance y = 0

from equation of motion

y = yo+ V_y t +(1)/(2)gt^2

0 = 5 + 2sin18+ (1)/(2)*9.8t^2

solving for t

t = 1.075 sec

for horizontal motion

x = V_x t

x = 2cos18*1.075

x = 2.044 m

Most elements in nature exist as mixture of two or more isotopes
t or f

Answers

Answer:

Atomic mass is a value that depends on the distribution of an element's isotopes in nature and the masses of those isotopes. Circle the letter of each sentence that is true about a carbon-12 atom. ... Most elements exist as a mixture of two or more isotopes.

So the answer is true.

Thank you and please rate me as brainliest as it will help me to level up

If the radio waves transmitted by a radio station have a frequency of 83.5 MHz, what is the wavelength of the waves, in meters

Answers

Answer: wavelength =3.52m

Explanation:

,λ=c/μ

where c=speed of the light,λ=wave length, μ=frequncy

c=3x10^8m/s

And

μ=83.5/MHz =85.3x10^6Hz==85.3x10^6Hz=

=85.3x10^6s-1

λ=c/μ

=3x10^8m/s/85.3x10^6s-1

=3.51699883

=3.52m