A circle is shown. A secant and a tangent intersect at a common point outside of the circle to form an angle that measure 51 degrees. The measure of the first arc formed is x degrees and the measure of the second arc formed is 160 degrees.What is the value of x?

x =

Answers

Answer 1
Answer:

The value of x in the circle is 58°

Secant and tangent intersection

when a secant and a tangent meets outsides of a circle, the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs. Therefore,

51° = 1 / 2 (160 - x)

Therefore,

51 = 80 - x / 2

51 - 80 = - 1 /2 x

-29 = - 1 / 2 x

multiply both sides by -2

-29 ×  2 = - 1 / 2 x × -2

x = 58

Therefore, the value of x is 58 degrees

learn more on secant and tangent here;brainly.com/question/14697178

Answer 2
Answer:

Answer:

58

Step-by-step explanation:

just did it on edg


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An isosceles triangle has base angles that each measure 48°. Which equation can be used to find x, the measure of the third angle of this isosceles triangle in degrees?

Answers

Answer:

Step-by-step explanation:

It would be 48+48+x=180, since 3 angles in any triangle will always measure 180, by definition of a triangle. I guess you could also do 2(48)+x=180, but the first equation just makes it more intuitive I guess. The reason why this works is because since 3 angles must equal 180, the missing angle, x, must be the value of 180-48-48, since that would be the remaining value needed to make a triangle

What is the solution to the system of equations below?y=-6x-10
and
y=-3x-21
(2, -22)
(2,48)
(-2, 2)
(-2, -20)

Answers

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equations

y=-6x-10

y=-3x-21

solving the system of the equations

Arrange the equation variables for elimination

\begin{bmatrix}y+6x=-10\n y+3x=-21\end{bmatrix}

y+3x=-21

-

\underline{y+6x=-10}

-3x=-11

\begin{bmatrix}y+6x=-10\n -3x=-11\end{bmatrix}

solve

-3x=-11

Divide both sides by -3

(-3x)/(-3)=(-11)/(-3)

x=(11)/(3)

\mathrm{For\:}y+6x=-10\mathrm{\:plug\:in\:}x=(11)/(3)

y+6\cdot (11)/(3)=-10

y+6\cdot (11)/(3)=-10

y=-32

Therefore, the solutions to the system of the equations are:

y=-32,\:x=(11)/(3)

But, it seems none of the options is true.

Answer:

A. (2, -22)

Step-by-step explanation:

I just took the test and i got a one hundred! I really hope it helped!!!!

F(x)= 2x+1/3x-4 H(x)=3x³-7EvaluateF(x)–¹And Fh(4)

Answers

f(x) = (2x + 1)/(3x - 4)
h(x) = 3x³ - 7

f(x) = (2x + 1)/(3x - 4)
y = (2x + 1)/(3x - 4)
y(3x - 4) = (3x - 4)((2x + 1)/(3x - 4))
y(3x) - y(4) = 2x + 1
3xy - 4y = 2x + 1
3xy - 2x = 4y + 1
x(3y) - x(2) = 4y + 1
x(3y - 2) = 4y + 1
(x(3y - 2))/(3y - 2) = (4y + 1)/(3y - 2)
x = (4y + 1)/(3y - 2)
y = (4x + 1)/(3x - 2)
f^(-1)(x) = (4x + 1)/(3x - 2)

f(h(4)) = 3x³ - 7
f(h(4)) = 3(4)³ - 7
f(h(4)) = 3(64) - 7
f(h(4)) = 192 - 7
f(h(4)) = 185

f^(-1)(x) - f(h(4)) =(4x + 1)/(3x - 2) - 185
f^(-1)(x) - f(h(4)) =(4x + 1)/(3x - 2) = (185(3x - 2))/(3x - 2)
f^(1)(x) - f(h(4)) =(4x + 1)/(3x - 2) = (555x - 370)/(3x - 2)
f^(-1)(x) - f(h(4)) =((4x + 1) - (555x - 370))/(3x - 2)
\f^(-1)(x) - f(h(4)) =((4x - 555x) + (1 - 370))/(3x - 2)
f^(-1)(x) - f(h(4)) =(-551x - 369)/(3x - 2)

3,9,6,9,27,24,27,81,78,81,243,?find out last figure to complete series

Answers

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Phil deposited $1,000 in a savings account. how much will he have in his account in two years if his account is compounded annually at a 2% interest rate?

Answers

$1400
.................

Answer:

I chose the same answer give the dude a round of applouse

Step-by-step explanation: