The rear window in a car is approximately a rectangle, 1.3 m wide and 0.30 m high. The inside rear-view mirror is 0.50 m from the driver’s eyes and 1.50 m from the rear window. What are the minimum dimensions that the rear-view mirror should have if the driver is to be able to see the entire width and height of the rear window in the mirror without moving her head?

Answers

Answer 1
Answer:

Final answer:

The minimum dimensions for the rear-view mirror should be a height of 0.890 m and a width of 1.3 m.

Explanation:

In order for the driver to be able to see the entire width and height of the rear window in the rear-view mirror without moving their head, the mirror should have minimum dimensions that allow for this visibility. Let's calculate the minimum height and width required for the rear-view mirror.

Height of the mirror:The mirror should be half the height of the driver, which is given as 1.715 m at the top and 0.825 m at the bottom. Therefore, the height of the mirror should be 0.890 m (1.715 m - 0.825 m).

Width of the mirror:The mirror should be wide enough to capture the entire width of the rear window. The width of the rear window is given as 1.3 m, so the width of the mirror should be at least 1.3 m. Therefore, the minimum dimensions of the rear-view mirror should be a height of 0.890 m and a width of 1.3 m.

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Answers

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Answers

I don't actually understand what your question is, but I'll dance around the subject
for a while, and hope that you get something out of it.

-- The effect of gravity is:  There's a pair of forces, in both directions, between
every two masses.

-- The strength of the force depends on the product of the masses, so it doesn't matter whether there's a big one and a small one, or whether they're nearly equal. 
It's the product that counts.  Bigger product ==> stronger force, in direct proportion.

-- The strength of the forces also depends on the distance between the objects' centers.  More distance => weaker force.  Actually, (more distance)² ==> weaker force.

-- The forces are equal in both directions.  Your weight on Earth is exactly equal to
the Earth's weight on you.  You can prove that.  Turn your bathroom scale face down
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If you put a little mirror down under the numbers, you'll see that it's the same as
the force that attracts you toward the Earth when the scale is right-side-up.

-- When you (or a ball) are up on the roof and step off, the force of gravity that pulls
you (or the ball) toward the Earth causes you (or the ball) to accelerate (fall) toward the Earth. 
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Answers

D because friction will slow it down going up hills (for safety reasons) and you go really fast going down.

Answer:

Decrease the friction between the wheels and the track.

Explanation:

Decrease the friction between the wheels and the track. Friction opposes motion. If the amount of friction is decreased, the speed of the cars should increase.

This answer is for the question on usa testprep

A 50-kg ice skater is holding a 3-kg ball, moving at a steady +5 m/s. She then throws the ball backwardsat -10 m/s, if so what would her final velocity be?

Answers

Answer: 5.9 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_(o) must be equal to the final momentum p_(f):

p_(o)=p_(f)(1)

Where:

p_(o)=(m_(1)+m_(2))V_(o)(2)

p_(f)=m_(1)U_(f)+m_(2)V_(f)(3)

m_(1)=50 kg is the mass of the skater

m_(2)=3 kg is the mass of the ball

V_(o)=5 m/s is the initial velocity of the skater and the ball

V_(f)=-10 m/s is the final velocity of the ball

U_(f) is the final velocity of the skater

Substituting (2) and (3) in (1):

(m_(1)+m_(2))V_(o)=m_(1)U_(f)+m_(2)V_(f)(4)

Isolating U_(f):

U_(f)=((m_(1)+m_(2))V_(o)-m_(2)V_(f))/(m_(1))(5)

U_(f)=\frac{(50 kg+3 kg)5 m/s}-(3 kg)(-10 m/s)}{50 kg}(6)

Finally:

U_(f)=5.9 m/s