A projectile is fired in such a way that its horizontal range is equal to 13.5 times its maximum height. What is the angle of projection?
Answers
Horizontal range: x = v0² sin 2 α / g
13.5 v0² sin² α /2 g = v0² sin 2 α /g / : v0²/g
6.75 sin² α = 2 sin α cos α / : sin α
6.75 sin α = 2 cos α / : cos α
6.75 tan α = 2
tan α = 0.2963
α = tan^(-1) 0.2963
α = 16.504° ≈ 16.5°
The angle of projection is 16° 30`.
Answer:
Maximum height: h = v0² sin² α / 2 g
Horizontal range: x = v0² sin 2 α / g
13.5 v0² sin² α /2 g = v0² sin 2 α /g / : v0²/g
6.75 sin² α = 2 sin α cos α / : sin α
6.75 sin α = 2 cos α / : cos α
6.75 tan α = 2
tan α = 0.2963
α = tan^(-1) 0.2963
α = 16.504° ≈ 16.5°
The angle of projection is 16° 30`.
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Explanation:
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Answer:
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In the fluid pressure is a measure of force per unit area, in this case force is the weight of the fluid that increases as we descend. Therefore, the pressure increases with the depth of the fluid.
The correct answer a
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Answers
Answers
Answer: 1.38 m/s to the right.
Explanation: We can solve this problem using the principle of conservation of momentum. The momentum of an object is defined as the product of its mass and velocity, and the total momentum of a closed system is conserved, meaning that the total momentum before a collision is equal to the total momentum after the collision.Let the initial velocity of the dart be v, and let the final velocity of the dart and the block be vf. The momentum of the dart before the collision is given by p = mv, where m is the mass of the dart. The momentum of the dart and block after the collision is given by (m + M)vf, where M is the mass of the block.Using the principle of conservation of momentum, we have:p = (m + M)vfSubstituting the given values, we get:0.012 kg v = (0.012 kg + 0.2 kg) 0.78 m/sSimplifying, we get:v = (0.212 kg) (0.78 m/s) / 0.012 kgv ≈ 1.38 m/sTherefore, the velocity of the dart just before it hits the block is approximately 1.38 m/s to the right.
B.) general relativity
C.) law of conservation of momentum
D.) thermodynamics
Answers
B. A crayon melting on a hot sidewalk.
C. Beach sand getting warmed by the sun.
D. An egg getting cooked in a pot of boiling water.
Answers
A). The hot burner is in contact wit the pot,
warming it with conduction.
B). The hot sidewalk is in contact with the crayon,
melting it with conduction.
C). The sun is not in contact with anything, and there is
no fluid to convect between it and the sand. The only way
for the sun to transfer heat to the sand is with radiation.
D). The boiling water is in contact with the egg,
warming it with conduction.
b. 2 times
c. 1/4
d. 4 times
Answers
Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :
where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and
are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get
Therefore, the force exerted between S and q is 4 times the force exerted between S and p.
I believe the answer is "4 times".