Given: R=2m KL = LM = KM
Find: V and
Surface Area of the cone
Given: R=2m KL = LM = KM Find: V and - 1

Answers

Answer 1
Answer:

Answer:

The volume of the cone is 3π≈9.42.

The surface area of the cone is 9π≈28.27.

Step-by-step explanation:

If we make a section of the sphere and the cone, we have a equilateral triangle inscribed in a circle (see picture attached).

We only know the numerical value of the radius R, that is 2 m.

From the picture, we have

\bar{KM}=2\cdot R\cdot cos(30^(\circ))=2R(√(3))/(2)=√(3)R= 2√(3)

The radius of the base of the cone is

r=\bar{KO}=\bar {KM}/2=(2√(3))/2=√(3)

The height of the cone can be calculated as:

h=\bar{LO}=\bar{KL}\cdot cos(30^(\circ))=(2√(3))*(√(3)/2})=3

The volume of the cone can be calculated as:

V=(1)/(3)\pi r^2h=(1)/(3)\pi (√(3))^2*3=3\pi\approx9.42

The surface area of the cone is:

S=S_(base)+S_(face)=\pi r^2+\pi r l=\pi r^2+\pi r (\bar{KL})\n\nS=\pi(√(3))^2+\pi √(3)*2√(3)=3\pi+2\pi*3=(3+6)\pi=9\pi\approx 28.27


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We cannot easily factor anything, so we resort to the quadratic equation. The work is attached as an image.

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Answer:

Step-by-step explanation:

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