A 12 volt car battery is connected to a 3 ohm brake light. What is the current carrying energy to the lights?

Answers

Answer 1

Answer:

Answer:

4 A

Explanation:

V = IR, where V=voltage, I=current, R=resistance. This is Ohm's Law. (remember that for units V = volts, Ω = ohms, A = amperes.)

V = IR

12 V = I * 3 Ω

12/3 = I

I = 4 A

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Water can dissolve many substances because it has an overall negative charge, allowing it to attack positively-charged ions.True or False?

Answers

true
1: Cation-positive charge2: Isotope-diff # of neutrons3: Element-it can be found on the periodic table(pure)4: Anion-negative charge5: Compound-even ration6: Ion-element with a charge(cations and anions are a more specific way of describing ions)Hope this helps!

8. Follow-up When the ferry leaves Guemes Island and heads backtoward Anacortes, its speed increases from 0 to 5.8 m/s in 9.25 s. What
is its average acceleration?

Answers

The average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².

Given the data in the question;

Initial speed; $u = 0$

Final speed; $v = 5.8m/s$

Time taken; $t = 9.25s$

To determine the average acceleration, we use the first equation of motion:

$v = u + at$

Where v is final speed, u is initial speed, a is acceleration and t is time taken.

We substitute our given values into the equation

$5.8m/s = 0 + [ a * 9.25s ]\n\n5.8m/s = a * 9.25s\n\na = (5.8m/s)/(9.25s)\n\na = 0.627m/s^2$

Therefore, the average acceleration of the ferry which leaves Guemes Island and heads back toward Anacortes is 0.627m/s².

Answer:

0.63m/s²

Explanation:

The average acceleration can be derived from using the formula:

V = u + at

Where v = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

V = u + at

V - u = at

a = v - u/t

a = ∆V/t

According to the provided information; v = 5.8m/s, u = 0m/s, t = 9.25s

a = ∆V/t

a = (5.8-0)/9.25

a = 5.8/9.25

a = 0.627

a = 0.63m/s²

Hence, the average acceleration is 0.63m/s²

A resistor is connected in series with an AC source that provides a sinusoidal voltage of v of t is equal to V times cosine of begin quantity omega times t end quantity, where V is the maximum voltage, omega is the angular frequency, and t is the time. The current supplied by this source that flows through this resistor is described with the function i of t is equal to I times cosine of begin quantity omega times t end quantity, where I is the maximum current. What is the average power supplied by this AC source?

Answers

Answer:

In circuits, the average power is defined as the average of the instantaneous power over one period. The instantaneous power can be found as:

$p(t)=v(t)i(t)$

So the average power is:

$P=(1)/(T)\intop_(0)^(T)p(t)dt$

But:

$v(t)=v_(m)cos(\omega t) \n \n i(t)=i_(m)cos(\omega t)$

So:

$P=(1)/(T)\intop_(0)^(T)v_(m)cos(\omega t)i_(m)cos(\omega t)dt \n \n P=(v_(m)i_(m))/(T)\intop_(0)^(T)cos^(2)(\omega t)dt \n \n But: cos^(2)(\omega t)=(1+cos(2\omega t))/(2)$

$P=(v_(m)i_(m))/(T)\intop_(0)^(T)((1+cos(2\omega t))/(2) )dt \n\nP=(v_(m)i_(m))/(T)\intop_(0)^(T)[(1)/(2)+(cos(2\omega t))/(2)]dt \n\nP=(v_(m)i_(m))/(T)[(1)/(2)(t)\right|_0^T +(sin(2\omega t))/(4\omega) \right|_0^T] \n \n P=(v_(m)i_(m))/(2T)[(t)\right|_0^T +(sin(2\omega t))/(2\omega) \right|_0^T] \n \n P=(v_(m)i_(m))/(2)$

In terms of RMS values:

$V_(RMS)=V=(v_(m))/(√(2)) \n \n I_(RMS)=I=(i_(m))/(√(2)) \n \n Then: \n \n P=VI$

A device that conveys information with analog signals and digital signals is called _____.a) an electron device

b) an electrical device

c) an electric device

d) an electronic device

Answers

I believe the correct answer from the choices listed above is option D. A device that conveys information with analog signals and digital signals is called an electronic device. They are components for controlling the flow of electrical currents for the purpose of information processing and system control.

the correct answer is D

Electrons in excited hydrogen atoms are in then = 3 energy level. How many different photon
frequencies could be emitted as the atoms return
to the ground state?
(1) 1 (3) 3
(2) 2 (4) 4

Answers

I can see three different transitions here:

3 --> 1

3 --> 2
followed by
2 --> 1 .

So we should expect to see three different 'colors'
being emitted from this excited mob.

If I was 14 stone what would my gravity be on venus

Answers

The acceleration of gravity on the surface of Venus (8.87 m/s^2) is 90.4% (rounded) of its value on Earth's surface (9.807 m/s^2). So if your weight on Earth is exactly 14 stone, then you would weigh 12st 9.2lb (rounded) on Venus.

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