What does the Doppler Effect tell astronomers about the universe?

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Answer 1

Answer: The doppler effect tells us that as an object moves away from another object, the wavelength increases, and vice versa. So, if the universe is expanding and things are moving away from where you are, the wavelength from the light source, such as a galaxy, would increase. Also, if the universe was contracting and things were getting closer to where you are, the wavelength of the light emitted from the galaxy would decrease

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List three adjectives that can be used to describe a hue that is high intensity.
Erica (39 kg ) and Danny (46 kg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is moving upward past her at 4.6 m/s . At that instant he grabs hold of her.
Explain why the car reaches a top speed even though the thrust Force remains constant at 3500N
As we move above up from one trophic level to another in an energy pyramid, what happens to the energy?a. It decreases from one trophic level to another. b. It remains the same for each trophic level. c. It increases from one trophic level to another.
If the current in each wire is the same, which wire produces the strongest magnetic field?-a wire that is 1mm thick and not coiled-a wire that is 2mm thick and not coiled-a wire that is 1-mm thick and coiled-a wire that is 2-mm thick and coiled

Carlos gets tired of pushing and instead begins to pull with force Fpull at an angle to the horizontal.The block slides along the rough horizontal surface at a constant speed. A free-body diagram for the
situation is shown below. Blake makes the following claim about the free-body diagram:
Blake: “The velocity of the block is constant, so the net force exerted on the block must be zero.
Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied
force Fpull.”
What, if anything, is wrong with this statement? If something is
wrong, identify it and explain how to correct it. If this statement is
correct, explain why.

Answers

Answer:

The wrong items are;

1) The normal for FN equals the weight Fmg

2) The force of friction, Ff, equals the applied force Fpull

The corrected statements are;

1) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ)

Explanation:

The given statement was;

The velocity of the block is constant, so the net force exerted on the block must be zero. Thus, the normal force FN equals the weight Fmg, and the force of friction Ff equals the applied force Fpull

By the equilibrium of forces actin on the system, given that the applied force acts at an angle, θ, with the horizontal, we have;

The normal force is equal to the weight less the vertical component of the applied force;

That is we have, FN = Fmg - Fpull × sin(θ)

The friction force similarly, is equal to the horizontal component of the applied force;

Ff = Fpull × cos(θ)

The wrong items are therefore as follows;

1) The normal for FN equals the weight Fmg

1 i) The normal force is weight less the vertical component of the applied force Fpull

FN = Fmg - Fpull × sin(θ)

2) The force of friction, Ff, equals the applied force Fpull

2 i) The force of friction equals the horizontal component of the applied force Fpull

Ff = Fpull × cos(θ).

Final answer:

While Blake's statement about the normal force is correct, his claim about the applied force and friction force is partially accurate. In reality,the horizontal component of the applied force should equate to the friction force for the block to maintain a constant velocity.

Explanation:

Blake's claim that the normal force FN equals the weight Fmg is correct as these forces balance each other in the vertical direction. However, his claim that the force of friction Ff equals the applied force Fpull is only partially accurate. In reality, the horizontal component of Fpull (i.e., Fpull * cos(θ)) should equate to the friction force Ff, to maintain the constant velocity (the block is not accelerating). The vertical component of Fpull (i.e., Fpull * sin(θ)) reduces the effective weight of the block and thereby, the normal force.

To correct Blake's claim, the normal force FN is equal to the weight of the block minus the vertical component of the applied force, and the applied force's horizontal component equals the friction force. Hence, this is the correct solution considering both vertical and horizontal components of forces.

Learn more about Force Components here:

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Why don't satellites in orbit fall to the ground? Why they don't fly off into space?

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-- The satellite IS falling, but it never reaches the ground because
it's also moving "sideways" ... in the direction of the orbit ... and
because the Earth is shaped like a sphere.

The satellite is moving sideways fast enough so that by the time
it falls 1 foot, the Earth's surface has curved down away from it
1 foot, so it's still the same distance from the Earth's surface.

-- A satellite doesn't fly off into space for the same reason that
a yo-yo doing "around the world" on the end of a string doesn't
fly off ... It's being held onto the circle by the tension in the string,
a force that keeps pulling it toward the center of the circle.

There's a force on the satellite too, that keeps pulling it toward
the center of the Earth. It's the gravitational force between the
Earth and the satellite.

The satellite doesn't fly off into space for the same reason that
YOU don't do that either.

The complex balancing act between a satellite's forward speed and the gravitational force pressing upon it prevents satellites in orbit from falling to the ground or shooting off into space.

When a satellite is put into orbit, it reaches a fast enough speed to escape the Earth's gravitational attraction.

By continuously falling towards the Earth and moving forward at the same time, the satellite may maintain a stableorbit.

This motion results in a curved course, which causes the Earth to be in a constant state of freefall.

Although the satellite is constantly being drawn towards the Earth by gravity, its forward velocity prevents it from dropping.

Thus, satellites don't fall or break free into space and are kept in a stable orbit.

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What is a force that does not involve physical contact between two objects? a. gravitational force
c. constant force
b. field force
d. planetary force?

Answers

a force that does not involve physical contact between two objects ic called field force.

Can a human being die by licking a diamond?

Answers

Answer:

the answer of this question ❓ is no

One of the earliest applications of the mass spectrometer involved measuring the atomic masses of neon. Which discovery resulted from this analysis?Particles within atoms can carry electric charges.
Atoms consists of three different kinds of particles.
Many elements have several isotopes.
Ions form when atoms gain or lose electrons

Answers

i will have to agree with her i have been reading online and that is all i found that matches your answer so i say C

I am pretty sure that it is many elements have several isotopes....but i'm not exactly certain that it is.

Ok I'm doing physics gragh an I don't know how to find the impulse on a graph

Answers

OK instead of telling us what you don't know, it would actually be much more helpful if we could talk about what you DO know.

What is it a graph of ?

-- Impulse is (force applied) x (time the force persists).
Is there force or time anywhere on the graph ?
Is there acceleration anywhere on the graph, and do you know the mass ?
With acceleration and mass, you could calculate the force.

-- Impulse is also the change in momentum.
Is there momentum anywhere on the graph ?
Is there speed anywhere on the graph, and do you know the mass ?
With speed and mass, you can calculate the momentum.

We can use what you know to solve the problem. But we cannot use
what you don't know to solve the problem.

I just had the coolest idea: What if you took a picture of the Physics gragh
that you're doing, and post it here along with your question ? ! Then we
would have the same information that you have, and we could show you
how to use it.

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Brilliant***Thank you

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