What is the pH of a solution with hydroxide ion concentration of 0.005

Answers

Answer 1
Answer:

Answer:

pH = 11.7

Explanation:

pOH= -log [OH]=-log[0.05]

=2.3

pOH+pH= 14

pH= 14-2.3= 11.7


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What is an acronym for the rainbow colors?I just want to know if anybody else knows this.

Answers

Answer:

ROYGBIV or Roy G

Explanation:

Thanks for the points!

Increasing which factor will cause the gravitational force between two objects to decrease?weights of the objects
distance between the objects
acceleration of the objects
masses of the objects

Answers

Increasing distance between the objects factor will cause the gravitational force between two objects to decrease. Therefore, option B is correct.

What causes gravitational force to decrease?

The gravitational force grows in proportion to the size of the masses . The gravitational force weakens rapidly as the distance between masses grows. Unless at least one of the objects has a lot of mass, detecting gravitational force is extremely difficult.

Gravity is affected by object size and distance between objects. Mass is a unit of measurement for the amount of matter in an object.

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. This means that the force of gravity increases with mass but decreases as the distance between objects increases.

Thus, option B is correct.

To learn more about the gravitational force, follow the link;

brainly.com/question/12528243

#SPJ6

Answer:

B

Explanation:

Convert 50g of calcium carbonate, CaCO3, into moles

Answers

Answer:
            Moles  =  0.5 mol

Solution:

Moles is related to mass as follow,

                                       Moles  =  Mass / M.mass   ----- (1)

Where;
           Mass  =  50 g

           M.mass  =  Ca (40) + C (12) + O₃ (16)₃  =  100 g/mol

Putting values in equation 1,

                                        Moles  =  50 g ÷ 100 g.mol⁻¹

                                        Moles  =  0.5 mol

of all the hydrogen nuclei in the ocean, 0.0156 how much deuterium could be obtained from 1.0 gal of ordinary tap water

Answers

Answer:

Poop Butt.

Explanation: Poop Butt.

Which of the following forces causes comets to regularly return to the inner solar system after being gone for many years?A. friction
B. magnetism
C. electromagnetic force
D. gravity

Answers

Answer is D. Gravity

Answer:

✨Gravity✨ hope this helps

Explanation:

Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when (Zn^2+)=0.22 M and(P_H2)= 0.87atm.

Answers

Answer:

pH = 2.059

Explanation:

At the Cathode:

The reduction reaction is:

2H^+ + 2e^- \to H_2   \ \ \ \mathbf{E^0_(red)= 0.00 \ V}

At the anode:

At oxidation reaction is:

Zn \to Zn^(2+) +2e^-   \ \ \ \mathbf{E^0_(ox) = 0.76 \ V}

The overall equation for the reaction is:

\mathbf{Zn + 2H^+ \to Zn^(2+) + H_2}

The overall cell potential is:

\mathbf{E^0_(cell)= E^0_(ox) + E^0_(red)}

\mathbf{E^0_(cell)= 0.76 \ V +0.00 \ V}

\mathbf{E^0_(cell)= 0.76\ V}

Using the formula for the Nernst equation:

E = E^0 - ( (0.0591)/(n))log (Q)\n

where;

E = 0.66

(Zn^2+)=0.22 M

Then

0.66 =0.76- ( (0.0591)/(2))log \bigg ( ([Zn^(2+) ] PH_2)/([H^+]^2) \bigg )

0.66 =0.76- 0.02955 * log \bigg ( (0.22*0.87)/([H^+]^2) \bigg )

3.4 = log ( 0.1914) - 2 log [H⁺]

3.4 = -0.7180 - 2 log [H⁺]

3.4 + 0.7180 = - 2 log  [H⁺]

4.118  = - 2  log  [H⁺]

pH = log [H⁺] = 4.118/2

pH = 2.059

The pH of the solution as described in the question is 2.7.

The equation of the reaction is;

Zn(s) + 2H^+(aq) ----> Zn^2+(aq) + H2(g)

The partial pressure of hydrogen can be converted to molarity using;

P= MRT

M = P/RT

M =  0.87atm/0.082 LatmK-1mol-1 × 298 K = 0.036 mol/L

We have to obtain the reaction quotient

Q = [Zn^2+] [H2]/[H^+]^2

Q = [0.22 ] [0.036]/[H^+]^2

Recall that, from Nernst equation;

E = E° - 0.0592/nlog Q

E° = 0.00V - (-0.76V) = 0.76V

0.660 =  0.76 - 0.0592/2logQ

0.660 - 0.76  =  - 0.0592/2logQ

-0.1 =  - 0.0592/2logQ

-0.1 × 2/ - 0.0592 = logQ

3.38 = log Q

Q = Antilog (3.38)

Q= 2.39 × 10^3

Now;

2.39 × 10^3 =  [0.22 ] [0.036]/[H^+]^2

2.39 × 10^3 = 7.92  × 10^-3/[H^+]^2

[H^+]^2 = 7.92  × 10^-3/2.39 × 10^3

[H^+] = 1.82  × 10^-3

pH = -log[H^+]

pH = -log[ 1.82  × 10^-3]

pH = 2.7

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