Answer: the coordinates are (3,-7)
Step-by-step explanation: just took the khan academy quiz! hope you do well loves <3
To find the coordinates of point B, we first apply the midpoint formula, with point M as the midpoint and point A given. Solving for point B's coordinates we find they are (3, -7).
In order to find the coordinates of point B, we need to use the midpoint formula. The midpoint M of two points A (x1, y1) and B (x2, y2) is given as:
M = [(x1 + x2)/2 , (y1 + y2)/2].
Given that the midpoint M is (-1.5, -1) and point A is (-6,5), we can use the midpoint formula to calculate the coordinates of point B by rearranging the formula to solve for x2 and y2 (the coordinates of point B):
x2 = 2*xm - x1, y2 = 2*ym - y1.
Plugging in known values, the x-coordinate of point B (x2) = 2*-1.5 - (-6) = 3 and the y-coordinate of point B (y2) = 2*-1 - 5 = -7.
So, the coordinates of point B are (3, -7).
Learn more about Midpoint Formula here:
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153.8 = 3.14r^2
Divide each side by 3.14 to get r alone.
48.9 = r^2
Take the square root of each side to isolate r.
r = 6.999
r= 7
r=12.27
153.8-3.14=150.66
150.66 square root is 12.27
a) Write the regression equation with parameters from the R output.b) Suppose that the number of manufacturing enterprises employing 20 or more workers in Irvine is 250, could you predict that the annual mean concentration of sulfur dioxide in Irvine?c) What is the residual if in Irvine the annual mean concentration of sulfur dioxide is 15 micrograms per cubic meter.d) What is the value of the correlation coefficient?e) Calculate a 95% confidence interval for the slope of the model.f) Based on the confidence interval, is there a linear relationship between X and Y?
Answer:
Y = 0.0315x + 9.4764
Residual = 2.35
Correlation Coefficient = 0.847
Step-by-step explanation:
From the R output given :
Intercept = 9.4764
Slope = 0.0315
x = number of manufacturing enterprise employing 20 or more workers
y = annual mean concentration of Sulphur dioxide
The regression equation :
y = bx + c
b = slope ; c = intercept
y = 0.0315x + 9.4764
Prediction using the regression equation :
The predicted y value, when x = 250
y = 0.0315(250) + 9.4764
y = 17.3514
The residual, if actual annual concentration = 15
Y residual = 17.35 - 15 = 2.35
The correlation Coefficient value, R
R = √R²
R = √0.717
R = 0.847
Answer:
The algorithm is given below.
#include <iostream>
#include <vector>
#include <utility>
#include <algorithm>
using namespace std;
const int MAX = 1e4 + 5;
int id[MAX], nodes, edges;
pair <long long, pair<int, int> > p[MAX];
void initialize()
{
for(int i = 0;i < MAX;++i)
id[i] = i;
}
int root(int x)
{
while(id[x] != x)
{
id[x] = id[id[x]];
x = id[x];
}
return x;
}
void union1(int x, int y)
{
int p = root(x);
int q = root(y);
id[p] = id[q];
}
long long kruskal(pair<long long, pair<int, int> > p[])
{
int x, y;
long long cost, minimumCost = 0;
for(int i = 0;i < edges;++i)
{
// Selecting edges one by one in increasing order from the beginning
x = p[i].second.first;
y = p[i].second.second;
cost = p[i].first;
// Check if the selected edge is creating a cycle or not
if(root(x) != root(y))
{
minimumCost += cost;
union1(x, y);
}
}
return minimumCost;
}
int main()
{
int x, y;
long long weight, cost, minimumCost;
initialize();
cin >> nodes >> edges;
for(int i = 0;i < edges;++i)
{
cin >> x >> y >> weight;
p[i] = make_pair(weight, make_pair(x, y));
}
// Sort the edges in the ascending order
sort(p, p + edges);
minimumCost = kruskal(p);
cout << minimumCost << endl;
return 0;
}
(a) What is the measure of RQP? Explain your answer.
(b) What is the value of x? Explain your answer with work.
(c) What is the measure of QRP? Explain your answer with work.
(d) What is the measure of RPQ? Explain your answer with work.
Answer:
(a) 90°
(b) 8.75
(c) 63.75°
(d) 26.25°
Step-by-step explanation:
(a) A radius to a point of tangency is always perpendicular to the tangent line there. Q is the point of tangency of line PQ, so the segment RQ from the center of the circle, R, to that point makes a 90° angle with PQ. Angle RQP is 90°.
(b) The sum of the acute angles of a right triangle is 90°, so ...
(5x +20)° + (3x)° = 90° . . . . . the sum of the acute angles is 90°
8x + 20 = 90 . . . . . . . . . . . . simplify, divide by °
8x = 70 . . . . . . . . . . . . . . . . . subtract 20
70/8 = x = 8.75 . . . . . . . . . . . divide by the coefficient of x
(c) ∠QRP = (5x+20)° = (5·8.75 +20)° = 63.75° . . . . . use the value of x in the expression for the angle measure
(d) ∠RPQ = (3x)° = (3·8.75)° = 26.25° . . . . . use the value of x in the expression for the angle measure