CHEMISTRY HIGH SCHOOL

What is the pH of a 0.028M solution (pH=-log(M))A) 3.56
B)2.88
C)1.55
D)1

Answers

Answer 1
Answer:

Answer:

C

Explanation:

-log(0.028)=1.55
Answer 2
Answer:

Answer:

ph =-log (28 x 10^-2)

= -(log 28 +log10^-2) ie using indices

= -(1.44+(-2) )

=-(-0.56)

= 0.56

=approximately (1) ans

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In which part of the Milky Way galaxy is our sun located?halo
bulge
center
spiral

Answers

The Sun's location in the Milky Way, specifically in the Orion Arm, about 26,000 light years from the center.

Our Sun is located in the spiral part of the Milky Way galaxy. More specifically, it is found in one of the galaxy's spiral arms, known as the Orion Arm, or sometimes the Orion Spur.

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Learn more about Sun's location in the Milky Way here:

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it is located in the center

What does Hess’s law state?

Answers

Hess's law states that the energy change in an overall chemical reaction is equal to the sum of the energy changes in the individual reactions comprising it. In other words, the enthalpy change of a chemical reaction (the heat of reaction at constant pressure) does not depend on the pathway between the initial and final states. The law is a variation of the first law of thermodynamics and conservation of energy.

Answer:

C. The enthalpy of a reaction is the sum of the enthalpies of intermediate reactions.

Explanation:

The heat of any reaction  ΔH∘f  for a specific reaction is equal to the sum of the heats of reaction for any set of reactions which in sum are equivalent to the overall reaction.

The half-life of a radioactive isotope is 20.0 minutes. What is the total amount of a 1.00-gram sample of this sample of this isotope remaining after 1.00 hour?

Answers

The amount remaining is obtained using the half life data. The total amount remaining after one hour is equal to 1/( e^ (ln2/(20/60))*1). The final answer is 0.125 grams. 

Answer: 0.125 grams

Explanation:

Radioactive decay follows first order kinetics.

Half-life of give isotope = 20 minutes

\lambda =\frac{0.693}{t_{(1)/(2)}}=(0.693)/(20)=0.03465min^(-1)

N=N_o* e^(-\lambda t)

N = amount left after time t= ?

N_0 = initial amount  = 1.0 g

\lambda = rate constant

t= time = 1 hour = 60 min

N=1.0* e^{- 0.03465mi^(-1)* 60min}

N=0.125g

Thus amount left after 1 hour is 0.125 grams

6.7 g of LiNO3 from a 20 %(m/m) LiNO3 solution.

Answers

20%(m/m)

20 g  LiNO₃------------- 100 g solution
6.7 g LiNO₃ ------------ ?

m = 6.7 * 100 / 20

m = 670 / 20

m = 33.5 g 

hope this helps!

No so that 01) In how many different ways can we arrange letten of the word HEURISTICS. C'must always occur at the third place?

Answers

Answer:

Given the word is '' HEURISTICS '' the Total no of letters is 10 Since C mus

Explanation:

How do you find the IUPAC name for a compound like ZnO

Answers

To find the IUPAC name for compounds, you must memorize prefixes and suffixes and other terms in determining or naming a compound. The IUPAC name for compound ZnO is Oxozinc or Zinc Oxide. I hope this helps you on your assignment.
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