Why must water be heated at about 80 degrees during esterification

Answers

Answer 1

Answer: The esters need to evaporate to be smelled.

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3. give reasons(a) A gas fills completely thevessel in which it is kept.(b)A gas exerts pressure on thewalls of the container(c) A wooden table should becalled a solid(d) We can easily move our handin air but to do the samethrough a solid block of wood we need a karateexpertwe need a karate expert.
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In what way are all sound waves and light waves similar?

Answers

Hello.In a homogeneous environment, the distribution of the light waves and sound waves is rectilinear and uniform (in constant speed).

So sound waves, and light waves. Well they are both waves, they can be reflected/refracted.

Write a nuclear equation for the fusion of two h−2 atoms to form he−3 and one neutron.

Answers

'Heavy' hydrogen (the isotope deuterium) , 2/1H is involved ,

[2= mass number, 1= atomic (proton) number]

2/1H + 2/1H → 3/2He + 1/0n

Which of these phrases best describes an atom?(1) a positive nucleus surrounded by a hard negative shell(2) a positive nucleus surrounded by a cloud of negative charges
(3) a hard sphere with positive particles uniformly embedded
(4) a hard sphere with negative particles uniformly embedded

Answers

number two because of yall study this in sciwnce class yall will get it

There is a correlation between algae height and the snout-to-vent length of a group of marine iguanas in the Galapagos; as algae height increases for a given island, so does iguana length. Why would the body size of this population of iguanas correlate with algae height?Differential reproduction of larger animals is favored when adequate nutrition is supplied by larger algae.
Increased variation in animal size is favored when large plant species are present in a healthy ecosystem.
Overproduction of smaller animals is favored when algae swards are short and vice versa when algae swards are long.
Traits are exchanged between iguana and algae populations so that taller algae result in larger iguana populations

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The body size of this population of iguanas correlate with algae height because Traits are exchanged between iguana and algae populations so that taller algae result in larger iguana populations

Answer;

The correct answer would be Differential reproduction of larger animals is favored when adequate nutrition is supplied by larger algae.

The size of the food influences the size of the organism.

Due to availability of larger food or larger algae, longer iguanas tend to live and survive more.

Thus, the tend to survive and reproduce more as compared to the shorter iguanas.

Similarly, when algae or food is not available, then larger iguanas die due to malnutrition and shorter iguanas tend to survive.

What is the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K ? Express your answer using three significant figures. Would the volume be different if the gas was argon (under the same conditions)? The volume would be the lower for argon gas. The volume would be the same for argon gas. The volume would be the greater for argon gas.

Answers

Answer: 2.93 L

Explanation:

AI-generated answer

To find the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Rearranging the equation to solve for V:

V = (nRT) / P

Plugging in the given values:

n = 0.108 mol

R = 0.0821 L·atm/(mol·K) (the ideal gas constant)

T = 306 K

P = 0.909 atm

V = (0.108 mol * 0.0821 L·atm/(mol·K) * 306 K) / 0.909 atm

Calculating this expression, we find that the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K is approximately 2.93 L.

Now, let's consider the second part of the question: Would the volume be different if the gas was argon (under the same conditions)?

The volume would be the same for argon gas.

According to the ideal gas law, at the same temperature, pressure, and number of moles, the volume occupied by a gas is the same regardless of the gas's identity. Therefore, if we replaced helium gas with argon gas while keeping the same conditions of pressure, temperature, and number of moles, the volume occupied by argon gas would be the same, approximately 2.93 L.

SELECT ALL THAT APPLYat STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)
1. Will contain the same number of molecules
2. Will contain the same number of atoms
3. Will occupy the same volume
4. Will have the same g.f.w

Answers

at STP conditions, 0.25 moles of CO2(g), H2(g), NH3(g)

The answers are:
1. Will contain the same number of molecules
3. Will occupy the same volume

Answer: The correct answer is Option 1 and Option 3.

Explanation:

We are given:

0.25 moles of $CO_2,H_2\text{ and }NH_3$

STP conditions states that 1 mole of a gas occupies 22.4 L of volume.

The volume occupied by all the gases at STP will be $0.25* 22.4=5.6L$

According to mole concept: 1 mole of a compound contains $6.022* 10^(23)$ number of molecules or 1 mole of an element contains $6.022* 10^(23)$ number of atoms.

We know that the given gases are compounds. Thus, all the three gases will have $0.25* 6.022* 10^(23)=1.5055* 10^(23)$ number of molecules.

Hence, the correct answer is Option 1 and Option 3.

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