What are the solution(s) to the quadratic equation 40 - x2 = 0?A. x = +2,10
B. x = +4/10
C. x = +2/5
D. x = -4/5
Answers
Answer:
A) x = ±
Step-by-step explanation:
I graphed the quadratic equation below and found the solutions to the equation.
If this answer is correct please make me Brainliest!
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What is the quotient of (x3 +3×^2-4x-12) ÷ (x^2 + 5x +6)
I'm really hoping one ou you all can help me understand.
Thanks for the help,
Huck
Answers
Answer:
51 and 136
Step-by-step explanation:
Since you don't know the side length, put an X in front of it. So the ratio becomes 3x:6x:8x.
Now, take the biggest number, 8 and set it to equal the side length.
8x=24.
x=3.
Now that you know x, multiply all of the values by 3, to get 24+18+9 which equals 51.
Repeat the process but with the smaller value.
3x=24.
x=8.
Multiply all the values by 8, 24+48+64, which equals 136. Therefore, the biggest perimeter is 136, and the smallest perimeter is 51.
Answers
50 miles per hour.
60 minutes per hour.
50 minutes out of 60 minutes (5/6).
5/6 * 50 = 41 2/3 or 42 (miles).
summer. He wants to have at least $200 in the account by the
end of summer. He withdraws $25 a week for his cell phone
bill.
Write an inequality that represents Keith's situation.
Answers
Answer:
- 500 - 25w ≥ 200
Explanation:
Translate every verbal statement into an algebraic statement,
1. Keith has $500 in a savings account at the beginning of the summer.
- Initial amount: 500
2. He wants to have at least $200 in the account by the end of summer.
- Final amount ≥ 200
3. He withdraws $25 a week for his cell phone bill.
- Call w the number of weeks
- Withdrawls = 25w
4. Write an inequality that represents Keith's situation.
- Create your model: Final amount = Initial amount - withdrawals ≥ 500
- 500 - 25w ≥ 200
With that inequality you can calculate how many week will pass before his account has less than the amount he wants to have in the account by the end of summer:
- 500 - 200 ≥ 25w
- 300 ≥ 25w
- 300/25 ≥ w
- 12 ≥ w
- w ≤ 12
That represents that he can afford spending $ 25 a week during 12 weeks to have at least $ 200 in the account.
Answers
Answers
When an equation of circle is expressed in the form:
(x-h)^2 + (y-k)^2 = r^2
(h, k) is the center and r is the radius.
The center = the coordinate you have plotted on the graph.
Radius = how many units long the circle extends to.
SO, let's plug this in.
Coordinate plotted = (0, -4)
0 = h
-4 = k
(x - {0})^2 + (y - {-4})^2 = 2^2
(x - 0)^2 + (y + 4)^2 = 4
(whenever we have two negative signs next to each other, it turns the digit to the right of the final negative sign positive.)
Now we are left with this final equation as a solution:
x^2 + (y + 4)^2 = 4.
I hope this helped~!
The standard form of a circle:
- the coordinates of a center of a circle
- the radius
We have:
the center:
the radius:
substitute
Answers
Answer:
See below
Step-by-step explanation:
2x+4 / x^2-x-6
= 2(x+2)/(x-3)(x+2)
= 2/(x-3)
So the 2 expressions are equivalent
The values of x which make the expressions undefined are those values which make the denominators 0
For 2x+4/ x^2-x-6 they are X=3 and x= -2.
For 2/x-3 they are x =3.