nonpolar covalent bond (with LD force)
The molarity of HCl after the first dilution is 0.024 M and after the second dilition, it is 0.0036M.
The problem at hand is a solution dilution problem in the field of Chemistry, usually tackled by the use of formula M1V1=M2V2, where M1 and V1 are the original molarity and volume, and M2 and V2 are the molarity and volume after dilution. In the first dilution, applying this formula gives (0.15 M)(4.00 mL) = (M2)(25.00 mL), solving for M2 gives a value of 0.024 M. The second dilution would similarly have the equation (0.024 M)(7.5 mL) = (M3)(50.0 mL), which gives M3 approximately 0.0036 M. Hence, the molarity of the first dilution would be 0.024 M and the molarity of the second dilution would be 0.0036 M.
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lava and soil
magma and silt
sand and lava
Answer:
suck dryeeeeeeeeeeeeeeeeeeeeeeeeeeeewwkkffjfkv3kmc,kflr
Explanation:
b)when the net force on an object decreases ,the objects acceleration increases
c)when the net force on an object decreases, the acceleration doesnt change
d)when the net force on an object decreases, the objects acceleration decreases
d. when the net force on an object decreases, the objects acceleration decreases
i took the test and got it right
Answer:
Mass of aluminium foil = 387.57_g
Explanation:
density of aluminium foil 2.70 g/cm³,
1_yd = 91.44_cm
1_in = 2.54_cm
Length of aluminum foil = 63.2_yd = 5779.008_cm
Width of aluminium foil = 11 in = 27.94_cm
Thickness of aluminium foil = 0.00035_in. = 0.000889_cm
Volume of aluminium foil = length × width × thickness = 5779.008_cm × 27.94_cm × 0.000889_cm = 143.54_cm^3
Mass of aluminium foil = (volume of aluminium foil) × (density of aluminium foil) = 143.54_cm³ × 2.70 g/cm³ = 387.57_g
To find the mass of the aluminium foil, calculate the volume and multiply it by the density. The mass of the foil is 0.3878 grams.
To find the mass of the aluminium foil, we need to calculate the volume and then multiply it by the density. First, let's convert the dimensions to the same unit. The aluminium foil is 63.2 yd long, which is equivalent to 190.4 ft. The width is 11 in, which is 0.92 ft, and the thickness is 0.00035 in, which is 2.92e-5 ft.
The volume of the foil can be calculated by multiplying the length, width, and thickness.
V = (190.4 ft) * (0.92 ft) * (2.92e-5 ft).
This gives us a volume of 5.0634e-3 cubic feet.
Next, we need to convert the volume to cubic centimetres because the density is given in g/cm³.
There are 28.3168 cubic centimetres in one cubic foot, so the volume in cm³ is
5.0634e-3 * 28.3168 = 0.1433 cm³.
Finally, we can calculate the mass by multiplying the volume by the density.
Mass = 0.1433 cm³ * 2.70 g/cm³ = 0.3878 grams.
So, The mass of the foil is 0.3878 grams.
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