MATHEMATICS COLLEGE

Compute the distance between (a,b,c) and (-2,5,6).a.
(a + 2)^2 + (b - 5)^2 + (c - 6)^2
c.
a + b + c -(-2 + 5 + 6)
b.
sqrt((a+2)^2+(b-5)^2+(c-6)^2)
d.
((a + 2) + (b - 5) + (c - 6))^2

Answers

Answer 1

Answer:

b. sqrt(a+2)^2+(b-5)^2+(c-6)^2

Step-by-step explanation:

Use distance formula

sqrt (a-(-2)^2 + (b-5)^2 + (c-6) ^2

sqrt (a+2)^2 +(b+5)^2 + (c-6)^2

Answer 2

Answer:

Answer:

Step-by-step explanation:

took it on edge, it's the right answer :)

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a map of barn is shown in coordinate plane in which the coordinates are measured in yards. The map shows the barn a (4,6). A well is dug at (4, y). What are the two values of y such that the barn is 70 yards from the well

Answers

Answer:

The values of y such that the barn is 70 yards from the well are y=76 or y=-64

Step-by-step explanation:

Distance in the Plane

Given two points in a rectangular system of coordinates (a,b) and (c,d) the distance measured between them is calculated with the formula

$d=√((c-a)^2+(d-b)^2)$

The barn is located at (4,6) and the well is located at (4,y). The value of y must be calculated in such a way the distance between the barn and the well is 70 yards. Thus, the equation to solve is

$70=√((4-4)^2+(y-6)^2)$

Operating

$70=√((y-6)^2)$

When taking the square root we must be careful for it has two signs:

$70=\pm (y-6)$

Rearranging

$y-6=\pm 70$

which yields to these solutions

$y-6=70$

$\boxed{y=76}$

And also

$y-6=-70$

$\boxed{y=-64}$

The values of y such that the barn is 70 yards from the well are y=76 yards or y=-64 yards

Please help me im stuck

Answers

Answer:

A. by adding an identical classroom and allowing students t use electric ans in it

Step-by-step explanation:

Because Fans are opposite to natural Air

If anyone can help that would be great!

Answers

Answer:

-120/119

Step-by-step explanation:

cos α = -5/13 = adj/hyp

using Pythagoras theorem

hypotenuse ² = opposite² + adjacent ²

13² =opp²+ (-5)²

169 = opp² + 25

169-25 = 144 = opp²

opp = √144 = 12

sinα = opp/hyp = -12/13

sin β = -12/13

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ)

cos α = -5/13

sinα = 12/13

tanα= sinα/cosα = 12/13 / -5/13 = 12/-5 = -12/5

sin β = -12/13

cos β = 5/13

tan β = sinβ/cosβ = -12/13 / 5/13 = -12/5

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ)

tanα = -12/5

tanβ= -12/5

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ) = (-12/5+(-12/5))/(1-(-12/5)(-12/5))

(-12/5+(-12/5)) = -12-12/5 = -24/5

(1-(-12/5)(-12/5)) = 1-(144/25) = (25-144)/25 = 119/25

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ) = (-12/5+(-12/5))/(1-(-12/5)(-12/5)) =-24/5/119/25 = -24/5 x 25/119 = -24x5/119 = -120/119

Fill in the missing numbers to complete the linear equation that gives the rule for this table.

Answers

Answer:

y = -2x + -17

Step-by-step explanation:

Tony worked 9 hours Monday, 9.5 hours Tuesday, 8.75 hours Wednesday,9.25 hours Thursday 8 hours Friday and 6 hours Sunday. How many hours
did he work?

Answers

The answer is 50.5 hours

all you have to do is add all the hours up to get the grand total.

Hope this helps

have a great day!

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