Implement the logic function ( , , ) (0,4,5) f a b c m =∑ in 4 different ways. You have available 3to-8 decoders with active high (AH) or active low (AL) outputs and OR, AND, NOR and NAND gates with as many inputs as needed. In every case clearly indicate which is the Most Significant bit (MSb) and which is the Least Significant bit (LSb) of the decoder input.

Answer:

//import the Random class

import java.util.Random;

//Begin class definition

public class CoinFlipper {

   //The main method

    public static void main(String []args){

       //Create an object of the Random class

       Random ran = new Random();

       System.out.println("Result");    

       //Use the object and the number of times for simulation

       //to call the flipCoin method

       flipCoin(ran, 25);

    } //End of main method

    //Method to flip coin

    public static void flipCoin(Random ran, int nooftimes){

        //Create a loop to run as many times as specified in variable nooftimes

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}   //End of class definition

====================================================

Sample Output:

Result

1

1

1

2

1

2

2

1

2

1

1

2

1

2

1

1

1

2

1

1

1

2

2

1

2

========================================================

Explanation:

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

The sample output from the execution of the code is also given above.

The code is re-written as follows without comments.

import java.util.Random;

public class CoinFlipper {

    public static void main(String []args){

       Random ran = new Random();

       System.out.println("Result");    

       flipCoin(ran, 25);

    }

    public static void flipCoin(Random ran, int nooftimes){

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}

Explanation: For number 3 I would say shade and darkness.

Answer:

// Here is code in C.

#include "stdio.h"

// create function to print all the combinations

void print_combi(char a,char b,char c)

{

// print all combinations of three characters

   printf("%c%c%c %c%c%c %c%c%c %c%c%c %c%c%c %c%c%c\n",a,b,c,a,c,b,b,a,c,b,c,a,c,a,b,c,b,a);

}

// driver function

int main(void)

{

// create 3 char variable and initialize

char a='x',b='y',c='z';

// call the function

print_combi(a,b,c);

printf("\n");

// initialize with different character

a='1',b='2',c='3';

// call the function

print_combi(a,b,c);

printf("\n");

// initialize with different character

a='#',b='$',c='%';

// call the function

print_combi(a,b,c);

printf("\n");

return 0;

}

Explanation:

Create three char variables a, b, c. First initialize them with x, y, z. then call  the function print_combi() with three parameters . this function will print all the combinations of those characters.We can test the function with different values of all the three char variables.

Output:

xyz xzy yxz yzx zxy zyx

123 132 213 231 312 321

#$% #%$ $#% $%# %#$ %$#

A C program to find all combinations of character variables:

void main ()

{

       char f;

       char s;

       char t;

       f = 'x';

       s = 'y';

       t = 'z';

       System.out.print("" + f + s + t + " " + f + t + s + " " + s +f + t +

       " " + s + t + f + " " + t + f + s + " " + t + s + f);

  }

}

Answer: B. judgment

Explanation: To critique a work of art, there are a 4 steps method:

Description: describe everything you see in the work: name of the artist, the title, what you observe, what media he/she used, the year it was created;

Analysis: describe how the artist uses the elements of art (line, shape, color, texture, space) and the principlesofdesign (balance, movement, pattern, emphasis, contrast);

Interpretation: try to explain what is the meaning of the art, why the artist created it, what was he/she's idea for it, based on the 2 previous steps;

JudgmentorEvaluate: make an opinion of why the art is worth it based on the other steps and give reasons for liking or disliking, its importance or the way it make you feel;

After going through each step, your evaluation or opinion will be expressed in the 4th step: Judgment.

Answer:

d. 24 = 16 subnets, 24 - 2 = 14 hosts per subnetwork

Explanation:

When four bits are borrowed from the fourth octet of class C IP address 200.245.10.150, the IP address is subnetted to 16 subnets, where the number of subnets is equal to two raised to the number of borrowed bits (ie, 2^ number of borrowed bits), and 14 assignable host IP address gotten from the formula;

  = 2^(number of host bits in the fourth octet) - 2

  = (2^4) - 2

  = 16 - 2 = 14 host addresses