MATHEMATICS COLLEGE

Circle O has a center at (-2, 10) and adiameter of 12 units. Which point lies on Circle
O?
A. (-6, -5)
B. (-2, 4)
C. (6,4)
D. (8,8)​

Answers

Answer 1
Answer:

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

distance = \sqrt{(y1 - y2)^(2) + {(x1 - x2)}^(2) }

A. Distance between 2 points

= \sqrt{ {(10 + 5)}^(2) + ( - 2 + 6)^(2) } \n = \sqrt{15 ^(2) + {4}^(2)} \n = √(241) \n = 15.524 \: units

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

= \sqrt{ {(10 - 4)}^(2) + ( - 2 + 2)^(2) } \n = \sqrt{ {6}^(2) } \n = 6 \: units

Since the distance of B from the center is 6 units, pointB lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

= \sqrt{ {(10 - 4)}^(2) + {( - 2 - 6)}^(2) } \n = \sqrt{ {6}^(2) + ( - 8)^(2) } \n = √(100) \n = 10 \: units

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

= \sqrt{ {(10 - 8)}^(2) + {( - 2 - 8)}^(2) } \n = \sqrt{2^(2) + ( - 10)^(2) } \n = √(104) \n = 10.198 \: units

(to 5 s.f.)

Point D also lies outside Circle O.

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Find the distance between the two points

Answers

I got 8.1 units
.
I used the Pythagorean Theorem to find my answer. I plugged in 7 for the long side and 4 for the short side and then solved.
.
Hope this helps :)

If ST=19 and S lies at -4 , where could T be located?

Answers

Answer:

15 or -23

Step-by-step explanation:

I think you probably already turned this in but in case you haven't:

ST = 19 means that line segment ST is 19 units long. If we know that S is at -4, then T has to be 19 units away from -4, right?

So there's two directions we could go.

Add 19 to -4 to get 15, so T could be at 15. (If there's a line drawn between -4 and 15, it would be 19 units long.)

But the line could go left, towards negative infinity, too. So if we subtract 19 from -4, we'd get -23. T could also be at -23. (If there's a line drawn between -4 and -23, it would also be 19 units long. There's no such thing as a negative length.)

Please mark as Brainliest! :)

Please help! (95 points)

Answers

Answer:

303.61

Step-by-step explanation:

if you need explantion tell me and i will edit my answer

Answer:

24.4M

Step-by-step explanation:

I’ll give out Brainly-ist to the correct one Use your calculator to estimate the value of
log740.

Click on the correct answer.
1.519
1.896
1.354

Answers

Answer:

  1.896

Step-by-step explanation:

You can answer this just using your number sense.

  \log_7{(40)}\approx 1.896

You know that 49 = 7², so log₇(49) = 2. The log function has a fairly small slope, so log₇(40) will not be far from 2.

_____

If you want to use your calculator, you can use the "change of base formula".

  log₇(49) = log(49)/log(7) ≈ 1.602060/0.845098 ≈ 1.896

Find the exact values of all 6 trigonometric function for theta=240 degrees

Answers

Answer:

Step-by-step explanation:

4

If the typos are randomly distributed over the 10 pages, find the probability of having a single typo on each page

Answers

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Please help! Thank you!