Let U be a square matrix such that Upper U Superscript Upper TUequalsI. Show that det Uequalsplus or minus1. Assume that Upper U Superscript Upper TUequalsI. Since the desired result is that det Uequalsplus or minus​1, an intermediate step must be found which contains the expression det U. Which of the following can be applied to the assumption Upper U Superscript Upper TUequalsI to achieve the desired​ result? A. det ​(Upper U Superscript Upper T​U)Superscript negative 1equalsdet I B. det ​(Upper U Superscript Upper T​U)equalsI C. ​(Upper U Superscript Upper T​U)Superscript negative 1equalsISuperscript negative 1 D. det ​(Upper U Superscript Upper T​U)equalsdet I Simplify the right side of the equation found in the first step. nothing Which property can be used to simplify the left side of the equation found in the first​ step? Select all that apply.

Answers

Answer 1
Answer:

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem.


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What is the length of the unknown side of the right triangle?

Answers

Answer:

Hypotenuse

Step-by-step explanation:

Answer:

L= the sum of the square root of the square of the opposite side and  the square of the base the triangle.

Step-by-step explanation:

Using Pythagorean Theorem :

the square of the hypotenuse= the square of the opposite side + the square of the base.

Gabrielle is 10 years older than mike. the sum of their ages is 56. how old is mike

Answers

Answer: 23

Step-by-step explanation:

Let

m be Mike's age.

According to the given information, Gabrielle is

+

10

m+10 years old.

The sum of their ages is given by:

+

(

+

10

)

=

56

m+(m+10)=56

Combining like terms, we get:

2

+

10

=

56

2m+10=56

Subtracting 10 from both sides, we have:

2

=

46

2m=46

Dividing both sides by 2, we get:

=

23

m=23

So, Mike is 23 years old.

mike is 23 years old

What are the zeros of the quadratic function f (x) = 2x^2 -10x-3?

Answers

Answer:

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

Step-by-step explanation:

1. Need to factor or can use the quadratic formula

2x^2-10x-3=0

a=2, b=-10, c=-3

[-b+-sqrt(b^2-4*a*c)]/(2*a)

[10+-sqrt(100-4*(-200)]/4

[10+- sqrt(300)]/4

x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4

a technician charges 25$ per hour plus 50$ for a house call to repair home computers. make a table and a graph to show the cost for 1,2,3, and 4 hours of home computer repair service. is there a direct variation?

Answers

Answer:

75$

Step-by-step explanation:

because 25+50=75

Answer:

The graph starts at $75 since the price for call is $50 and 1 hour of work costs $25.

Direct variation is only noticeable at the beginning of the graph after that the function is linear.

Step-by-step explanation:

Judging on the basis of​ experience, a politician claims that 57​% of voters in a certain area have voted for an independent candidate in past elections. Suppose you surveyed 25 randomly selected people in that​ area, and 18 of them reported having voted for an independent candidate. The null hypothesis is that the overall proportion of voters in the area that have voted for an independent candidate is 57​%. What value of the test statistic should you​ report?

Answers

Answer: z= 1.51

Step-by-step explanation:

Test statistic for proportion is given by :-

z=\frac{p-P}{\sqrt{(PQ)/(n)}}

Where n is sample size ,p is the sample proportion , P Is the population proportion and Q =1 - P.

Given : P=57% = 0.57

Q= 1- P = 1-0.57=0.43

n = 25

p=(18)/(25)=0.72

Test statistic for proportion will be :-

z=\frac{0.72-0.57}{\sqrt{(0.57*0.43)/(25)}}\approx1.51

We should report the value of test statistic z= 1.51

In determining automobile-mileage ratings, it was found that the mpg (X) for a certain model is normally distributed, with a mean of 33 mpg and a standard deviation of 1.7 mpg. Find the following:__________. a. P(X<30)
b. P(28c. P(X>35)
d. P(X>31)
e. the mileage rating that the upper 5% of cars achieve.

Answers

The upper 5% of cars have a mileage rating of 35.805 mpg

What is z score?

Z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = (raw score - mean) / standard deviation

Given;  mean of 33 mpg and a standard deviation of 1.7

a) For < 30:

z = (30 - 33)/1.7 = -1.76

P(x < 30) = P(z < -1.76) = 1 - 0.8413 = 0.0392

b) For < 28:

z = (28 - 33)/1.7 = -2.94

P(x < 28) = P(z < -2.94) = 0.0016

c) For > 35:

z = (35 - 33)/1.7 = 1.18

P(x > 35) = P(z > 1.18) = 1 - P(z < 1.18) = 1 - 0.8810 = 0.119

d) For > 31:

z = (31 - 33)/1.7 = -1.18

P(x > 31) = P(z > -1.18) = 1 - P(z < -1.18) = 0.8810

e) The  upper 5% of cars achieve have a z score of 1.65, hence:

1.65 = (x - 33)/1.7

x = 35.805 mpg

The upper 5% of cars have a mileage rating of 35.805 mpg

Find out more on z score at: brainly.com/question/25638875

Answer:

a) P(X < 30) = 0.0392.

b) P(28 < X < 32) = 0.2760

c) P(X > 35) = 0.1190

d) P(X > 31) = 0.8810

e) At least 35.7965 mpg

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 33, \sigma = 1.7

a. P(X<30)

This is the pvalue of Z when X = 30. So

Z = (X - \mu)/(\sigma)

Z = (30 - 33)/(1.7)

Z = -1.76

Z = -1.76 has a pvalue of 0.0392.

Then

P(X < 30) = 0.0392.

b) P(28 < X < 32)

This is the pvalue of Z when X = 32 subtracted by the pvalue of Z when X = 28. So

X = 32

Z = (X - \mu)/(\sigma)

Z = (32 - 33)/(1.7)

Z = -0.59

Z = -0.59 has a pvalue of 0.2776.

X = 28

Z = (X - \mu)/(\sigma)

Z = (28 - 33)/(1.7)

Z = -2.94

Z = -2.94 has a pvalue of 0.0016.

0.2776 - 0.0016 = 0.2760.

So

P(28 < X < 32) = 0.2760

c) P(X>35)

This is 1 subtracted by the pvalue of Z when X = 35. So

Z = (X - \mu)/(\sigma)

Z = (35 - 33)/(1.7)

Z = 1.18

Z = 1.18 has a pvalue of 0.8810.

1 - 0.8810 = 0.1190

So

P(X > 35) = 0.1190

d. P(X>31)

This is 1 subtracted by the pvalue of Z when X = 31. So

Z = (X - \mu)/(\sigma)

Z = (31 - 33)/(1.7)

Z = -1.18

Z = -1.18 has a pvalue of 0.1190.

1 - 0.1190 = 0.8810

So

P(X > 31) = 0.8810

e. the mileage rating that the upper 5% of cars achieve.

At least the 95th percentile.

The 95th percentile is X when Z has a pvalue of 0.95. So it is X when Z = 1.645. Then

Z = (X - \mu)/(\sigma)

1.645 = (X - 33)/(1.7)

X - 33 = 1.645*1.7

X = 35.7965

At least 35.7965 mpg