The lengths of a lawn mower part are approximately normally distributed with a given mean mc021-1.jpg = 4 in. and standard deviation mc021-2.jpg = 0.2 in. What percentage of the parts will have lengths between 3.8 in. and 4.2 in.?

Answers

Answer 1

Answer: The best answer that is given to the question that is being presented above would be 68%. Since it is normally distributed and the lengths' range fall between the first lower and upper standard deviations of the distribution (which is 68%), then the answer is 68%.

Answer 2

Answer:

Answer: 68

Step-by-step explanation:

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Write a real world example, then solve.5x + 4 = 2x +14
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Two factors of –48 have a difference of 19. The factor with a greater absolute value is positive.. . Give the sum of the factors given?. . –19.
–13.
13.
16

Answers

x y = - 48
x - y = 19
y = x - 19
x ( x - 19 ) = - 48
x² - 19 x + 48 = 0
x² - 3 x - 16 x + 48 = 0
x ( x - 3 ) - 16 ( x - 3 ) = 0
( x - 3 ) ( x - 16 ) = 0
Factors : x = 16, and y = -3
( 16 * ( -3 ) = -48; 16 - (-3 ) = 16 + 3 = 19 )
Sum of the factors : 16 + ( -3 ) = 16 - 3 = 13
Answer : C ) 13.

What is the solution set of {x | x < -3} ∪ {x | x > 5}

Answers

The union of two sets is defined as all elements that are members of both sets.

The first set evaluuates to (...,...,...-7,-6,-5,-4) and the second eveluates to (6,7,8,9,...,...).

There are no elements that belong to both sets so the solution is the empty set. {∅}

Another way is to think about it in words: "What number(s) are less than -3 and also greater than 5?" There are no numbers that fit both of these.

Polynomial function in standard form with zeros 5,-4,1

Answers

Answer:

$\boxed{\sf \ \ \ x^3-2x^2-19x+20 \ \ \ }$

Step-by-step explanation:

hello,

by definition we can write

$(x-5)(x+4)(x-1)$

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

$(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\n=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\n=x^3-2x^2-19x+20$

hope this helps

A charges $9.95 per month for the first 10 hours of use and $1.69 per hour for all those over 10. Provider B charges a flat fee of $19.95.

Answers

Given:
A = charges 9.95 per month for the first 10 hours and 1.69 per hour for all those over 10 hours.
B = charges a flat fee of 19.95

A = 9.95 + 1.69(x-10) where x is the total number of hours used.
B = 19.95

A = B
9.95 + 1.69(x - 10) = 19.95
1.69x - 16.9 = 19.95 - 9.95
1.69x = 10 + 16.9
1.69x = 26.9
x = 26.9/1.69
x = 15.92 hours

If usage does not go over 10 hours, it is cheaper to use A.
If usage is between 15-16 hours, A or B is acceptable. They cost almost the same.
If usage is beyond 16 hours, it is cheaper to use B.

Jill is building a wooden raised bed garden for her vegetable she wants the frame to have dimension X feet by X +3 feet if she wants the garden to have a maximum area of 50 ft.² what are the possible values of X

Answers

Answer: 0ft < X ≤ 5.73ft

Step-by-step explanation:

In this case, we have a rectangle.

For a rectangle of length L and width W, the area is:

A = L*W.

And we have:

L = X

W = X + 3ft.

Then the area will be:

A = X*(X + 3ft) = X^2 + 3ft*X.

And we want to have a maximum area of 50ft^2.

Then we can write:

A = X^2 + 3ft*X ≤ 50ft^2

Now let's solve this for X.

Now, the first thing we can see is that both coefficients in our quadratic equation are positive, so as the absolute value of X increases, also does the whole equation.

Then makes sense start for the upper limit of X, this is when:

X^2 + 3ft*X = 50ft^2.

Now we can solve the quadratic equation:

X^2 + 3ft*X - 50ft^2 = 0

Applying the Bhaskara formula, the solutions are:

$X = (-3ft +- √((3ft)^2 - 4*1*(-50ft^2)) )/(2) = (-3ft +-14.46ft )/(2)$