this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.
c1v1 = c2v2
where c1 is concentration and v1 is volume of the concentrated solution
and c2 is concentration and v2 is volume of the diluted solution to be prepared
50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL
substituting these values in the formula
1.50 M x 50.0 mL = C x 250 mL
C = 0.300 M
concentration of the final solution is A) 0.300 M
Answer: 0.300M
Explanation:
1) Data:
a) Initial solution
M = 1.50M
V = 50.0 ml = 0.050 l
b) Solvent added = 200 ml = 0.200 l
2) Formula:
Molarity: M = moles of solute / volume of solution is liters
3) Solution:
a) initial solution:
Clearing moles from the molarity formula: moles = M × V
moles of H₂SO₄ = M × V = 1.5M × 0.050 l = 0.075 mol
b) final solution:
i) Volumen of solution = 0.050 l + 0.200l = 0.250l
ii) M = 0.075 mol / 0.250 l = 0.300M ← answeer
B. 1.00 × 10¹⁵ cm
C. 2.00 × 10⁵ cm
D. 6.00 × 10^{–5}cm
E. 1.20 × 10^{–8} cm
Can someone explain me how to make this one step by step?
sadiq added hydrochloric acid to magnesium chloride in a flask
SUGGEST THE PH OF HYDROCHLORIC ACID ?
the carbon dioxide produced was bubbled through lime water.
HOW WOULD THE LIME WATER CHANGE?
a. Sn.
b. N.
c. S.
d. Na.
Answer: B. Metallic (happy to help)
Explanation: