What is the function of law

Answers

Answer 1

Answer: There are many functions and purposes of law, but here are some of the most important ones:
establishing standards, maintaining order, resolving disputes, and protecting liberties and rights.

Related Questions

A 600-N box is pushed up a ramp that is 2 meters high and 5 meters long. The person exerts a force of 300-N. What is the efficiency of the ramp?
Geothermal energy cannot meet all of our energy needs because access to geothermal energy is _________.a. limited to certain regions. b. the earth is not hot enough. c. geothermal energy is intermittent. d. geothermal sources do not have enough energy to generate electricity
A business letter style that shows all text aligned to the left side of the page is calleda. full block.b. left block.c. justified block.d. modified block.
Solids are usually more dense than: gases liquids plasmas all of the above
How many electrons will there be in 5 coulombs of charge? (the charge of one electron is 1.6 x 10^-19 Coulombs) thanks!

In february a little town received snow on a daily basis. The first day they had 10 inches, 3 inches the second, 7 inches the 3rd, and 4 inches on the fourth day. What was the average snowfall?

Answers

The average snowfall of the four days was 6 inches.

What is snow?

When atmospheric water vapor freeze into small ice crystals and falling in small white flakes or lying on the ground as a white layer, it is called snow.

In the question it is said that,

Amount of snow received by the town on first day = 10 inches.

Amount of snow received by the town on second day = 3 inches.

Amount of snow received by the town on third day = 7 inches.

Amount of snow received by the town on fourth day = 4 inches.

Total amount of snow received by the town on these four days = ( 10 + 3+ 7 + 4) inches.

=24 inches.

Hence, average amount of snow received by the town on these four days = total amount of snow received ÷ 4

= ( 24 ÷ 4) inches.

= 6 inches.

Hence, the average snow received by the little town was 6 inches on those days.

Learn more about snowfall here:

brainly.com/question/28294667

#SPJ2

Answer:

The average is 6

Explanation:

To find the average, you have to first add all the numbers. After you add all the numbers up, then you divide by how many numbers there are. This one had 4 numbers so you divide by 4

Describe the factors that determine power in your own words (not from a website)

Answers

As it was categorized in the physics category it must be the mechanical power.

Power is basically the amount of work done per unit time or in simpler words the amount of energy transferred per unit time.

The SI unit for power is Watt. Which is basically J/s or Nm/s as wor has the unit of Nm.

In electrical components power can also be categorized as the amount voltage supplied multiplied by the current passed through the component.

Since you put your question in the <Physics> category, I'll assume
you're talking about mechanical or electrical power, and not political
or military power etc.

Power is the rate of doing work or moving energy from one place
to another.

In mechanical contraptions, Work is (force) x (distance) ,
so
   Power = (work) divided by (time)

   or    = (force) x (distance) divided by (time).

In electrical circuits,

   Power = (voltage) x (current)

   or = (current)² x (resistance)

   or = (voltage)² divided by (resistance) .

(Just use the formula with whatever quantities you know.)

What is the momentum of an object at rest, in m/s?

Answers

Momentum = (mass) x (speed)

If the speed is zero, then the momentum is zero.

Compare the characteristics of 4d orbitals and 3d orbitals and compared the following sentences. Check all that apply4d orbitals would __________ than 3d orbitals

a. be a closer to the nucleus
b. be larger in size
c. hold more elections
d.have different shapes
e.have more nodes

Answers

Answer:

The $4d$ orbitalswolud be larger in size and have more nodes than $3d$ orbitals.

Explanation:

Given: $4d$ orbitals would __________ than $3d$ orbitals.

Since, the distance between nucleus and orbital increases when we electrons moves away fro m one orbital to another orbital.

So, The $4d$ orbitals is far from the nucleus as compared with $3d$ orbitals.

Therefore, The $4d$ orbitals wolud be larger in size than $3d$ orbitals.

Now, finding the number of nodes of an orbital is calculated as $n-1\; \rm\{{where}, n \;is\; priniciple \; quantum \;number\}$

Then, number of orbital in $4d\;\;\rm{is}\; 4-1=3$ .

And number of orbital in $3d\;\;\rm{is}\; 3-1=2$ .

Therefore, $4d$ orbitals wolud have more nodes than $3d$ orbitals.

Learn more about Orbitals here:

brainly.com/question/1482725?referrer=searchResults

Answer :

(b) 4d orbitals would be larger in size than 3d orbitals

(e) 4d orbitals would have more nodes than 3d orbitals

Explanation :

As we move away from one orbital to another, the distance between nucleus and orbital increases. So, 4d orbitals would be far to the nucleus than 3d orbitals.

Hence, 4d orbitals would be larger in size than 3d orbitals.

Number of nodes is any orbital is n - 1 where, n is principal quantum number.

So, number of orbital in 4d is 3.

And number of orbital in 3d is 2.

So, options (b) and (e) are correct.

If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?4.0 x 10^-1 A
1.0 x 10^2 A
1.0 x 10^-10 A
4.0 x 10^0 A

Answers

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

Answer:

Explanation:

A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback car starts from rest and accelerates at 5m/s/s, how far away do the cars meet up again?

Answers

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. $s_(o)$ = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

$v_(i)$ = 33.2 m/s, a = 0 (since the velocity is constant), $s_(o)$ = 0

Using $s =s_(o)+v_(i)t+1/2at^(2)$

s = 33.2t .......... eq (1)

Hatchback:

$a=5m/s^(2)$ , $v_(i)$ = 0 m/s (since initial velocity is zero), $s_(o)$ = 0

Using $s =s_(o)+v_(i)t+1/2at^(2)$

putting in the data we will get

$s=(1/2)(5)t^(2)$

now putting 's' value from eq (1)

$2.5t^(2)-33.2t=0$

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

Answer:

440.9 m

Explanation:

initial speed of the pickup truck (Up) = 33.2 m/s

acceleration of the pickup truck (ap) = 0

initial speed of the hatchback = 0

acceleration of the hatchback (ah) = 5 m/s^{2}

how far away (s) do the cars meet up again?

from the equations of motion distance covered (s) = ut + $0.5at^(2)$

distance covered by the pickup = ut + $0.5at^(2)$

where

u = initial speed of the pickup = 33.2 m/s
t = time it takes
a= acceleration of the pickup = 0
the distance covered by the pickup (s) now becomes = 33.2t + $0.5.(0).t^(2)$ = 33.2t ...equation 1

distance covered by the hatchback = ut + $0.5at^(2)$

where

u = initial speed of the hatchback = 0 m/s
t = time it takes
a= acceleration of the hatchback = 5 m/s^{2}
the distance covered by the hatchback (s) now becomes = (0)t + $0.5x5t^(2)$

= $2.5t^(2)$ ......equation 2

when the cars meet, they both would have covered the same distance, therefore

distance covered by the pickup = distance covered by the hatchback
equation 1 = equation 2

33.2t = $2.5t^(2)$
33.2 = 2.5t
t = 13.28 s

now that we have the time it takes for both cars to meet, we can put the value of the time into equation 1 or equation 2 to get the distance at which they meet

from equation 1

distance (s) = 33.2t = 33.2 x 13.28= 440.9 m

from equation 2

distance (s) = $2.5t^(2)$ = $2.5x12.8^(2)$ = 440.9 m

Other Questions

I a liter jar contains 0.5 moles of gas at a pressure of 2 ATM what is the temperature of the gas

Please help me, i beg you. Which Statement best describes the inner core of the earth?aA metallic liquid substancebA very cold substancecA spherical solid metal made up of Nickel, Iron and small amount of sulfur, silicon and oxygen.dA flatten but thick structure similar to a granite counter top

When evaluating promotional claims, it is important to __________.a.do your own research c.determine if there are other possible solutions b.ask if it makes sensed.all of the above

What is a scientific paradigm