A stadium has 55,000 seats. Seats sell for $28 in Section A, $16 in Section B, and $12 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in $1,158,000 from each sold-out event. How many seats does each section hold?

Answers

Answer 1

Answer: A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C ⇒A-B-C=0
28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1      1     1    55,000
1 -1 -1    0
28 16       12    1,158,000

1      1     1    55,000
0 -2    -2    -55,000      (R₂-R₁)
0    12    16     382,000    (28R₁-R₂)

1 1 1 55,000
0    -2 -2    -55,000
0 0     4     52,000 (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000

-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.

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I am confused on numbers 25 and 29, the instructions are at the top.

Answers

Pretty sure you already had something posted about this... in case you've lost it, or have questions:

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$√(12-(-4)) = √(16) = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
$√(12-3) = √(9) = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= √(2x+3)$
Square both sides to get
$x^(2)=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^(2)-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
$x= √(2x+3)$
$3= √(2(3)+3)$
$3= √(9)$
Extraneous root would be negative 3.

$-1= √(2(-1)+3)$
$-1= √(1)$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

How can I solve for y 13=1/6y+2x

Answers

The value of y will be y = 78 - 12 x.

An expression , 13 = 1/6y + 2x is given.

We have to solve the expression to find out the value of y.

What is algebra ?

Algebra is the branch that deals with various symbols and the arithmetic operations such as multiplication , division , etc.

As per the question ;

The expression given is ;

13 = 1/6y + 2x

Let's solve it to get the value of y ;

So ,

13 = 1/6y + 2x

1/6y = 13 - 2x

multiplying both RHS and LHS by 6 , we get ;

y = 78 - 12 x

Thus , the value of y will be y = 78 - 12 x.

To learn more about algebra click here ;

brainly.com/question/26479183

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13 = 1/6y + 2x

multiply everything by 6 to get rid of the fraction... fractions are bad
78= y + 12x

now you can solve for y by subtracting 12x from both sides
78 - 12x = y

Help
I need help can some help me!! I give you

Answers

Answer:

x=6

Step-by-step explanation:

its an equilateral triangle so all sides are the same measure

9=3x-9

18=3x

x=6

180 euros to exchange rate 1.2 to the pound

Answers

Your answer is 138.61440

Hope this helps.

What is the distance between points A begin ordered triple (0,0,8) end ordered triple and B begin ordered triple (0,6,0) end ordered triple?Answer is 10 units, but why is this rational?

Answers

Step 1: Obtain the difference vector AB= (0-0, 0-6, 8-0)=(0, -6, 8) it size (module) is the distance between A and B Step 2: Add-Up the squares of its components: 0^2+(-6)^2 + 8^2=100 Step3: Extract the squareroot of the above: sqrt(100)=10 Voilá!

Martin has 5/6 of a pizza Liam has four times as much pizza is Martin how much pizza does Liam have? (Put it in a fraction)