MATHEMATICS HIGH SCHOOL

Two points are shown on the graph. What is the midpoint between these two points?A) (1, 5)
B) (-1, 2)
C) (-2, 1)
D) (-5, -3)

Answers

Answer 1
Answer:

Answer: C (-2,1)

Step-by-step explanation:
Answer 2
Answer: Can you show the graph please

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Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, Area of ABCD

Answers

1. Consider right triangle ABK. In this triangle AB is the hypotenuse, BK and AK are legs. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\n\n6^2=3^2+BK^2,\n\nBK^2=36-9=27,\n\nBK=3√(3)\ un.

2. Use the definition of \cos \angle A:

\cos \angle A=\frac{\text{adjacent leg}}{\text{hypotenuse}}=(AK)/(AB)=(3)/(6)=(1)/(2).

Then m\angle A=60^(\circ).

3. Consider right triangle ABD. In this triangle AD is the hypotenuse, AB and BD are legs. Since  m\angle A=60^(\circ), then

m\angle BDA=180^(\circ)-90^(\circ)-60^(\circ)=30^(\circ).

The leg that is opposite to the angle of 30° is half of the hypotenuse, so

AD=2AB=12\ un.

4. The area of parallelogram aBCD is

A_(ABCD)=AD\cdot BK=12\cdot 3√(3)=36√(3)\ sq. un.

two angles are supplementary the first angle measures 40 degrees what is the measurement of the second angle

Answers

Supplementary angles add up to 180
40+x=180
x=140
The answer would be 160

Slope intercept equation

Answers

Sorry I’m confused! Maybe....

A curve is described by the following parametric equations:x = 2 - t
y = x^2 + 1
Which statement best describes the curve?

The curve is a parabola with a vertex at (2, 1) and is traced from left to right for increasing values of t.
The curve is a parabola with a vertex at (2, 1) and is traced from right to left for increasing values of t.
The curve is a parabola with a vertex at (-2, -1) and is traced from left to right for increasing values of t.
The curve is a parabola with a vertex at (-2, -1) and is traced from right to left for increasing values of t.

Answers

When you use a parameter to describe equations then you are talking about Parametric Equations, that is, you can write both x and y as functions of a parameter t. In this problem we have the following equations:

x=2-t \n y=x^(2)+1

So substituting x in y we have:

y=(2-t)^2+1 \n y=4-4t+t^2+1 \n y=t^2-4t+5

So this equation represents a parabola where y is the dependent variable and t is the independent variable. This equation is shown in the figure below, the best statement that describes this curve is:

The curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t. 

A curve is described by parametric equations x = 2 - t;

y = x^2 + 1 statement the curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t is the best-described curve.

We use a parameter to describe equations then we are talking about Parametric Equations, that isWe can write both as functions of a parameter.

We have given the parametric equation

x = 2 - t\ny = x^2 + 1

What is the parametric equation?

The parametric equation defines a group of quantities as functions of one or more independent variables called parameters.

So substituting the value of x in y we get,

y=(2-t)^2+1\ny=2^2-4t+t^2+1\ny=4-4t+t^2+1\ny=5-4t+t^2\n

So this equation represents a parabola where y is the dependent variable and t is the independent variable.

This equation is shown in the following figure, the best statement that describes the curve.

Therefore we can say that the curve is a parabola with a vertex at (2,1) and is traced from left to right for increasing values of t.

To learn more about the parametric equation visit:

brainly.com/question/51019

HELP PLEASSEEE QUICKLYY IM BEGGINGTrain A and Train B leave a central station at the same time. They travel the same speed, but in opposite directions, with train A heading towards station A, and train B heading towards station B. Train A reaches station A after 4h. Train B reaches station B after 3 1/2 h. Station A and Station B are 562.5 mi apart. What is the rate of the trains?

Answers

Hope this helps. If not lmk

A top fuel dragster can use a s much as 6 gallons in 4seconds to travelmile. At this rate, how many gallonsof fuel will it take for the dragster to go 1 mile?

Answers

Hi There! :)

A top fuel dragster can use a s much as 6 gallons in 4seconds to travelmile. At this rate, how many gallonsof fuel will it take for the dragster to go 1mile?

6 gallons in 4 1/2 seconds to travel 1/4 mile
Multiply through by 4

The dragster will :
use 24 gallons in 18 seconds to travel 1 mile.
Hope this helps.
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