How much greater is the five in the hundreds place the end of five in the tens place

Answers

Answer 1

Answer: it would be 10 times greater im pretty sure.

Answer 2

Answer: 10 times greater im sure thatll be it

Related Questions

8 = 3(3x + 8) − x whats x and explenation :)
In which quadrant is (1/2, -1.8)?Quadrant II Quadrant IV Quadrant III Quadrant I
Work out 1 2/3 ÷ 2 3/4 ?
Suppose a spring with spring constant 7 N/m is horizontal and has one end attached to a wall and the other end attached to a 3kg mass. Suppose that the friction of the mass with the floor (i.e., the damping constant) is 3 N.s/m, and the forcing function is F(t) = 9sin (3t).
The triangles in the picture are congruent by which method.

S and T are two-digit positive integers that have the same digits but in reverse order. If the positive difference between S and T is less than 40, what is the greatest possible value of S minus T

Answers

Answer :Answer: Did you get helped on this one?

Step-by-step explanation: okay yup yup have a good day OKAY

Step-by-step explanation: HAVE A GOOD ONE OKAY

Any ideas on how to find the value of 'x' on either 13 or 16? Anything helps!

Answers

(x+5)/4=1/2
first get rid of the fraction
multiply both sides by 4
x+5=2
subtract 5
x=-3

(2x+1)/(4x-1)=2/3
get rid of the fractions,
multiply both sdies by (4x-1)(3)
(2x+1)(3)=(2)(4x-1)
distribute
6x+3=8x-2
subtract 6x form both sdies
3=2x-2
add 2
5=2x
divide by 2
5/2=x

What is the area of the kitchen floor in this floor plan?A-24 sq meters
B-28 sq meters
C-35 sq meters
D-42 sq meters

Answers

Answer: The correct option is (C) 35 sq. meters.

Step-by-step explanation: We are given to find the area of the kitchen floor in the floor plan shown in the figure.

From the figure, we see that

the kitchen is in the form of a rectangle with length 7 meters and breadth 5 meters.

We know that

the area of a rectangle with length l units and breadth b units is given by

$A=l* b.$

For the rectangular kitchen, we have

length, l = 7 meters

and

breadth, b = 5 meters.

Therefore, the area of the kitchen floor in the floor plan is given by

$A=l* b=7* 5=35~\textup{sq. meters}.$

Thus, option (C) is CORRECT.

First you would figure out the dimensions, which are 7 ft by 5 ft. Then, multiply those together, which equals 35 sq ft. The answer to your question is C - 35 sq ft. Hope this helps!

The mass of an electron is approximately 9 × 10-28 grams, while the mass of a neutron is approximately 2 × 10-24 grams. Which of the following is true?The mass of a neutron is approximately 2,000 times the mass of an electron.

The mass of a neutron is approximately 10,000 times the mass of an electron.

The mass of a neutron is approximately 20,000 times the mass of an electron.

The mass of a neutron is approximately 1,000 times the mass of an electron.

Answers

We simply divide the Mass of Neutron by Mass of electron

= 2 × 10⁻²⁴ / (9 × 10⁻²⁸)

= (2/9) × 10⁻²⁴ ⁻ ⁻²⁸

= (2/9) × 10⁻²⁴ ⁺ ²⁸

≈ 0.2222... × 10²⁸ ⁻ ²⁴

≈ 0.2222 × 10⁴

≈ 2222

This is approximately 2000 times.

So:

The mass of a neutron is approximately 2,000 times the mass of an electron

The first option. I hope this explains it.

Answer:

The mass of a neutron is approximately 2,000 times the mass of an electron

Step-by-step explanation:

= 2 × 10⁻²⁴ / (9 × 10⁻²⁸)

= (2/9) × 10⁻²⁴ ⁻ ⁻²⁸

= (2/9) × 10⁻²⁴ ⁺ ²⁸

≈ 0.2222... × 10²⁸ ⁻ ²⁴

≈ 0.2222 × 10⁴

≈ 2222

This is approximately 2000 times.

What is the indefinite integral of 6sin(3t) dt?

Answers

Answer:

$\displaystyle \int {6sin(3t)} \, dt = -2cos(3t) + C$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle (d)/(dx) [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals
[Indefinite Integrals] Integration Constant C

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int {6sin(3t)} \, dt$

Step 2: Integrate Pt. 1

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {6sin(3t)} \, dt = 6\int {sin(3t)} \, dt$

Step 3: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 3t$
[u] Differentiate [Basic Power Rule, Multiplied Constant]: $\displaystyle du = 3 \ dt$

Step 4: integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {6sin(3t)} \, dt = 2\int {3sin(3t)} \, dt$
[Integral] U-Substitution: $\displaystyle \int {6sin(3t)} \, dt = 2\int {sin(u)} \, du$
[Integral] Trigonometric Integration: $\displaystyle \int {6sin(3t)} \, dt = -2cos(u) + C$
Back-Substitute: $\displaystyle \int {6sin(3t)} \, dt = -2cos(3t) + C$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Apples sell 5 for a $1.00 how much will 2 1/2 dozen cost

Answers

1 dozen=12

2 and 1/2 dozen means 12 times 2.5=24+6=30 apples

5sellfor1

we know that 5 times 6=30

5 for 1
times 6 both sides
30 for 6

$6 for 2 and 1/2 dozen

$6.00

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Which strategies can be used to solve this problem?The candle factory made 1,200 candles per month in June and July and 1,345 candles per month in August and September. What is the total number of candles they made in four months?Choose all answers that are correct.A.Use logical reasoning.Multiply 1,200 by 2 to figure out how many candles were made in June and July. Multiply 1,345 by 2 to figure out how many candles were made in August and September. Add the two numbers together to find the total number of candles made in four months.B.Draw a diagram.Draw two circles. In one circle write 1,200 and in the other circle write 1,345. Add the numbers in the circles together.C.Work backward.Divide 1,200 by 2 (for the 2 months, June and July). Then divide 1,345 by 2 (for the 2 months August and September). Add these two numbers.D.Translate into an equation.1,200 × 2 + 1,345 × 2 = c

If the dimensions of a figure are doubled, then the perimeter of the figure is