CHEMISTRY HIGH SCHOOL

For any point on earths surface its height above sea level is called its

Answers

Answer 1
Answer:

Answer:

The correct answer is elevation.

Explanation:

In a geographical place, the elevation refers to the height below or above a precise reference point generally above the sea level. The term elevation is primarily applied when considering towards the points on the surface of the Earth, while geopotential height or altitude terms are used for considering the points above the surface like a spacecraft in orbit or an aircraft in flight, and depths are applied for the points underneath the surface.
Answer 2
Answer: Altitude, If this helped please 5 star me 

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When three pairs of electrons are shared in a molecule, what shape will the molecule be?a. tetrahedral
b. trigonal planar
c. bent
d. linear

Answers

The correct answer is B. The shape of a molecule where three pairs of electrons are shared is a trigonal planar. This is characterized by one central atom and three atoms forming an equilateral triangle which is bonded to the central atom.

Answer:

Trigonal Planar is the correct answer.

How do isotopes of a given element differ? How am they similar?

Answers

Isotopes of a given element differ from one another based on the number of neutrons those atoms of the same element have. They are similar as they are the same element, given to us as they all have the same atomic number, but different in the number of neutrons they possess, which ultimately affects the atomic mass or mass number of that said isotope.

What terms are needed to completely describe velocity... A.units

B.number

C.mass

D.direction

Answers

a, b, and d. mass could be important in your calculations though.

How many grams are in 2.40 mol of sodium chloride (NaCl)?

Answers

In this question, we are asked to convert from moles to grams.
We have 2.40 moles of NaCl. 

We need the molar mass of NaCl. We can calculate this by referencing the periodic table and looking up the atomic weight. 
Na = 22.99g
Cl  = 35.45g
----------------
+      58.44g

2.40 moles x (58.44grams) / (1 mole) = 140.26 grams of NaCl

There are 140.26 grams in 2.40 moles of NaCl. 

Stoichiometry problems which give a known amount of one reactant and solve for an amount of product frequently state that there is "an excess" or "plenty" of the reactant(s) not given. (For example, in the equation 2Na + 2H2O → 2NaOH + H2, how many grams of sodium hydroxide are produced from 3.0 mol of sodium with an excess of water?) Why is it necessary to know that there is an excess of these reactant(s)?

Answers

Dumb. Can. Cabbage. Hn. D ikkk

How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2?

Answers

First we establish the chemical reaction equation. 
2Mg + O2 = 2MgO. 
Then we need to know which of the reactant is limiting. We do that by multiplying the number of moles of reactant to the stoichiomeric coefficient. For Magnesium: 97.2 g* (mol)/(24g) *2 = 8
For O2: 88.5g*(mol)/(32g) *1 = 2.7
Since O2 has the smaller moles, this is the Limiting reactant. Then we solve basing on the number of O2 used. 

88.5g* (mol)/(32g) * (2)/(1) * (56g)/(mol) = 309.75 g

Answer : The mass of magnesium oxide produced will be, 161.2 g

Solution : Given,

Mass of Mg = 97.2 g

Mass of O_2 = 88.5 g

Molar mass of Mg = 24.3 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of MgO = 40.3 g/mole

First we have to calculate the moles of Mg and O_2.

\text{Moles of Mg}=\frac{\text{Mass of Mg}}{\text{Molar mass of Mg}}=(97.2g)/(24.3g/mole)=4\text{ moles}

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=(88.5g)/(32g/mole)=2.7\text{ moles}

The balanced reaction is,

2Mg+O_2\rightarrow 2MgO

As, 2 moles of Mg react with 1 moles of O_2

So, 4 moles of Mg react with (4)/(2)=2 moles of O_2

From this we conclude that the O_2 is in excess amount and Mg is in limited amount.

Now from the reaction we conclude that

As, 2 moles of Mg react to give 2 moles of MgO

So, 4 moles of Mg react to give 4 moles of MgO

Now we have to calculate the mass of MgO.

\text{Mass of MgO}=\text{Moles of MgO}* \text{Molar mass of MgO}

\text{Mass of MgO}=(4moles)* (40.3g/mole)=161.2g

Therefore, the mass of magnesium oxide produced will be, 161.2 g
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