Which of the following ions has the smallest radius? (1) F– (3) K (2) Cl– (4) Ca2

Answers

Answer 1

Answer: (1) is the correct answer.

(2) Cl- is larger than F- due to having more electron shells
(3) Is not an ion
(4) Is not an ion either.

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2H2 + O2 --> 2H2O can be classified as what type of reaction? A. Both synthesis and combustion. B. Only synthesis. C. Only combustion. D. It cannot be classified.
Josh prepares a solution by mixing sodium nitrate and water. To calculate the molarity of the solution, Josh should calculate the moles of which substance, and why?sodium nitrate, because it is the solvent sodium nitrate, because it is the solute water, because it is the solvent water, because it is the solute

12a. Do i need to find the morality of each ion in the solution to get to the moles? Or do i just do AlCl3

Answers

You just use the morality of the solution, you found out that you have 0.0046mol (about 0.005mol0 of AlCl3, so then since there is 1 Al in a single molecule, you have the number of moles of aluminum, but since there is Cl3 (3 atoms of chlorine per molecule), just multiply the number of moles of molecules by the number of atoms of that type inside a single molecule, to get [Cl-] = 0.0138mol (or round to 0.014)

HELP!!! ILL GIVE BRAINLIEST! Why do nuclear power plants use fission instead of fusion?
A: Scientists have not yet gotten a fusion reaction to happen on Earth.
B: Per gram of fuel, fission releases more energy than fusion.
C: The energy from fusion cannot yet be converted to electricity.
D: Fusion requires conditions that use too much energy to maintain.

Answers

According to the nuclear fission and nuclear fusion reactions,energy from fusion cannot yet be converted to electricity.

What is nuclear fission and nuclear fusion?

There are two types of nuclear reactions which are nuclear fusion and nuclear fission .They involve the combination and disintegration of the element's nucleus respectively.

In nuclear fission, the nucleus of the atom is bombarded with electrons of low energy which splits the nucleus in to two parts .Large amount of energy is released in the process.It is used in nuclear power reactors as it produces large amount of energy.

In nuclear fusion,on the other hand, is a reaction which occurs when two or more atoms combine to form a heavy nucleus.Large amount of energy is released in the process which is greater than that of the energy which is released in nuclear fission process.

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C. The Energy from fusion cannot yet be converted to electricity.

Fusion results in a lot of energy. The sun uses fusion reactions to burn. So, if we were using fusion reactions, we would have little suns going off. Nuclear bombs often use a combination of fission and fusion reactions to maximize devastation. However, we do not currently have the ability to control or convert the energy produced by a fusion reaction.

What is the percent by mass of carbon in C10 H14 N2?

Answers

Answer: The percentage by mass of carbon in the given compound is 45.8 %

Explanation:

We are given a chemical compound having chemical formula $C_(10)H_(14)N_2$

To calculate the percentage composition of an element in a compound, we use the equation:

$\%\text{ composition}=\frac{\text{Mass of carbon element}}{\text{Mass of compound}}* 100$

In 1 mole of given compound, 10 moles of carbon atoms are there.

Mass of $C_(10)H_(14)N_2= [(10* 12)+(14 * 1)+(2* 14)]=262g/mol$

Mass of carbon element = $[10* 12]=120g/mol$

Putting values in above equation, we get:

$\%\text{ composition of carbon}=(120)/(262)* 100=45.8\%$

Hence, percentage of carbon in given compound is 45.8 %.

Multiply the number of each element by its mass on the periodic table.

Add them together.

Put the mass of carbon only over the total mass and multiply the result by 100 to get the percentage.

As the temperature of a chemical reaction in the gas phase is increased, the rate of the reaction increases because(1) fewer particle collisions occur
(2) more effective particle collisions occur
(3) the required activation energy increases
(4) the concentration of the reactants increases

Answers

Answer: option (2) more effective particle collisions occur.

Justification:

Always keep in mind that the temperature is a measure of the average kinetic energy of the particles.

The higher the temperarute the hiigher the kinetic energy.

Also, remeber that the kinetic energy is the energy of motion: the higher the kinetic energy the hgher the speed of the particles and the more energetic the collisions.

Therefore, those more energetic collisions will increase the number of collisions that overcome the activiation energy leading to higher rate of conversion (reaction), whic is what a more effective particle collisions occur mean.

Elements in the same group on the periodic table have the same number of electrons

number of protons

number of neutrons

number of valence electrons

Answers

Elements in the same group have the same number of valence electrons labelled in Roman numerals.

Also, From left side-Right side of the periodic is in the following order - Alkali Metals, Alkali Earth Metals, Halogens then Noble gases in the Far right of the periodic table

Hello,How can you tell if a molecular ion will have one or ore unpaired eletrons?

For example,
"Which of the following molecules is expected to have one or more unpaired electrons? Check all that apply.

O2-
F2+
N22-
O22-"
Any help would be appreciated. ...?

Answers

I believe the correct answers from the choices listed above are the first two options. The molecules O2- and F2+ are expected to have one unpaired electron. This can be determined by looking at the value of the charge. Hope this answers the question.

Final answer:

To determine unpaired electrons, look at the valence electrons in an ion's molecule, accounting for extra or absent electrons due to the ion's charge. For instance, O2- and F2+ have one unpaired electron, but N22- is not a valid ion, and O22- electrons are all paired.

Explanation:

To determine if a molecular ion will have one or more unpaired electrons, we need to look at the number of valence electrons in the molecule and take into account any extra or absent electrons due to the charge of the ion.

For example, O2- has 12 + 1 = 13 valence electrons (6 from each oxygen atom and 1 extra due to the negative charge). It requires 14 for all the electrons to be paired (2 in each oxygen's inner shell and 4 bonds or lone pairs in the outer shell), thus there is one unpaired electron in O2-.

However, in F2+, there are only 13 electrons because one electron is lost due to the positive charge. Like oxygen, fluorine also prefers to have 7 electrons in its outer shell, so there are also unpaired electrons in F2+.

N22- doesn’t exist because nitrogen normally forms triple bond and doesn’t need or want to take extra electrons, so this molecular ion is not valid.

O22- has 14 + 2 = 16 valence electrons and this total number of valence electrons is an even number, which indicates all the electrons are paired.

Learn more about Unpaired Electrons here:

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