Which of the following best describes this image?
Which of the following best describes this image? - 1

Answers

Answer 1
Answer:

Answer:

B and D

High Accuracy

Low precision

Explanation:

Its attached below!


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How does Newton's law work? Give an example of the formula in a word problem.

Answers

Newtons Law works with friction, gravity, and falls.

Also, the formula would be: F = ma

Force = acceleration * mass

Example: The force on a bike is 30 Newtons. The mass of the bike is 6 kg. What is the acceleration of the bike?

What is the law of reflection?

Answers

You can observe this law in practice if a ray of light reflects off of a flat mirror

Law of reflection states that both direction of both incoming and outgoing rays of light make the same angle with respect to surface normal.
The law of reflection are, as follows:

The incident Ray, the reflected Ray and the normal to the reflection surface at the point of the incidence lie in the same plane.

If this does not make since than I hope you know I tried.

Tom left for his friend's house. He drove 60 km in an hour. When he got to John's house, he wondered how fast he had been driving. What formula would he use to determine his speed?

Answers

Answer: Tom drove 60 km/hr fast

Speed = Distance traveled / time taken

Explanation:

Given that:

Distance traveled by Tom = 60 km

Time taken by Tom = 1 hour

Speed = ?

Since speed is obtained by dividing distance traveled by the time taken, hence the formula to use is as follows:

speed = distance / time

Speed = 60 km / 1 hour

Speed = 60 km/hr

Thus, Tom had been driving 60 km/hr fast, using the formula "speed = distance / time"

Explain how mirrors can produce images that are larger or smaller than life size, as well as upright or inverted

Answers

Answer:

1) When d_(o) < d_(i) (hence  d_(o) < f ) and they are both in front of the mirror (positive), the image will be larger and inverted

2) When d_(o) > d_(i) (and d_(o) < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted

3) When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror

Explanation:

The position of an object in front of a concave mirror of radius of curvature, R, determines the size and orientation of the image of the object as illustrated in the mirror equation

(1)/(f)=(1)/(d_(o)) + (1)/(d_(i))

Magnification, \, m = (h_(i))/(h_(o)) = -(d_(i))/(d_(o))

Where:

f = Focal length of the mirror = R/2

d_(i) = Image distance from the mirror

d_(o) = Object distance from the mirror

h_(i) = Image height

h_(o) = Object height

d_(o) is positive for an object placed in front of the mirror and negative for an object placed behind the mirror

d_(i) is positive for an image formed in front of the mirror and negative for an image formed behind the mirror

m is positive when the orientation of the image and the object is the same

m is negative when the orientation of the image and the object is inverted

f and R are positive in the situation where the center of curvature is located in front of the mirror (concave mirrors) and f and R are negative in the situation where the center of curvature is located behind the mirror (convex mirrors)

∴ When d_(o) < d_(i) (hence  d_(o) < f ) and they are both in front of the mirror (positive), the image will be larger and inverted

When d_(o) > d_(i) (and d_(o) < f ) such that they are both positive (in front of the mirror), the image will be smaller and inverted

When the image is behind the mirror, for convex mirrors and the object is in front the image will be uptight. The magnification of the image will be the ratio of the image distance to the object distance from the mirror.

Which can be used to determine if an electromagnet is working? A. compass B. a permanent magnet C. a switch D. galvanometer

Answers

The device used to datermine a electromagnet is a /compass

The acceleration of an object depends on the ____________ exerted on it and it's_________ this is to do with newton's seconed law

Answers

force is the first and mass is the second