Some areas of an ocean are known as dead zones. These zones form when excess organic material decomposes. This increased decomposition uses up the oxygen from the water. Which human activity is most affected by the increasing number of dead zones in the ocean? A.
Offshore oil drilling, because water in dead zones is toxic
B.
Commercial fishing, because fish cannot survive without oxygen
C.
Commercial shipping, because dead zones change the course of ocean currents
D.
Sand mining, because oxygen is not available to form the sands on ocean beaches

Answers

Answer 1

Answer:

The human activity that should be most affected by the rising no of dead zones should be option b.

What is commercial fishing?

It is the activity where the fish should be caught out also the other seafood for the commercial food.

In the case when it gives the large number of quantity of food with respect to the various countries that should be around the earth.

hence, we can conclude that The human activity that should be most affected by the rising no of dead zones should be option b.

Learn more about oxygen here: brainly.com/question/19531144

Answer 2

Answer:

Answer: B

Explanation: I just took the test :)

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The act of performing a task several times is called?

Answers

Answer:

Repetition

Explanation:

In science, the act of performing an experiment several times is called repetition. This involves obtaining multiple trials of an experiment in order to ensure accuracy and precision.

Multiple trials ensures that the best result which eliminates errors represents the findings.

Repetition gives a pool of important statistics to work with which can raise the confidence limit and provide more representation.

Answer:

repition

Explanation:

What is ment by paranoid

Answers

1 : characterized by or resembling paranoia or paranoid schizophrenia a paranoid psychiatric patient. 2 : characterized by suspiciousness, persecutory trends, or megalomania behaving in a paranoid manner with accusations of persecutions. 3 : extremely fearful was so paranoid that he was afraid to walk the streets.

Answer:

when you are seeing thing that is not there or when you are having illusions

Explanation:

The majority of the protein inside a red blood cell (erythrocyte) is:a. albumin
b. hemoglobin
c. fibrinogen
d. immunoglobulin
e. porphyrin

Answers

Answer: Hemoglobin

Explanation: Hemoglobin is a protein very rich in iron found in red blood cells and is responsible for the transportation of Oxygen from the lungs to the whole body. Oxygen binds to the hemoglobin in red blood cells and the red pigmentation of blood that is highly oxygenated is due to the hemoglobin content found in RBC's.

Why do cells have different shapes if most cells have the same organelles?

Answers

Answer:

cells have different shapes because they do different things

Explanation:

each cell type has has its own role to play in helping our bodies

to work properly

In humans there is a dominant allele (A) for the absence of moles; while the recessive allele (a) results in the presence of moles. A couple who are both heterozygous for this locus (Aa) plan to have seven children. a. Expand the binomial (p + q)7.
b. What is the probability that:
(i) The first child that is born will not have moles.
(ii) All of the children will have moles.
(iii) The first two children will have no moles and the last five will have moles.
(iv) Of the 7 children, 4 will have no moles and 3 will have moles
c. Assume this couple now have two children, one with moles and one without moles. What is the probability that the child born without moles is a carrier of the a-allele (ie heterozygous)?

Answers

Answer:

a. $(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. i. 0.75

ii. 0.000061

iii. 0.012

iv. 0.17

c. 0.67

Explanation:

a. The expansion of the binomial (p + q)7 would be such that:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. Both couples are heterozygous:

Aa x Aa

AA Aa Aa aa

Since A is dominant over a,

probability of having mole (aa) = 1/4

probability of not having moles = 3/4

Therefore, the probability of the first child not having moles = 3/4 or 0.75

ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

Probability that all of the children will have moles = $p^0q^7$

since p = 3/4 and q = 1/4

$p^0q^7$ = $(3/4)^0(1/4)^7$ = 0.000061

iii.Probability that the first two children will have no moles and the last five will have moles = $21p^2q5$

= $21(3/4)^2(1/4)^5$

= 0.012

iv. Probability that 4 will have no moles and 3 will have moles out of the 7 children = $35p^4q^3$

= $35(3/4)^4(1/4)^3$

= 0.17

c. Probability that the child born without moles is a carrier of the a-allele = probability of heterozygous.

From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:

= 2/3 or 0.67

Polydactyly is a rare autosomal dominant trait that is 80% penetrant. What is the chance that a child born to an affected father and a normal mother will have the disorder

Answers

The question is incomplete, below is the complete question.

Polydactyly is a rare autosomal dominant trait that is 80% penetrant. What is the chance that a child born to an affected father and a normal mother will have the disorder?

Assume the paternal grandfather is normal.

I will use P to encode polydactyl as it is dominant and use p allele to encode normal phenotype

P= Polydactyl

p= Normal

From what is given in the question,the paternal grandfather is normal and that means that the father of the child receives one wild type allele from the paternal grandfather, however,the father is affected with the disease,hence the genotype is A a but the mother being normal will have the genotype of aa.

That is Parents;

Father Aa × Mother aa

Gametes a a A Aa ( P ) Aa ( P )

a aa ( p ) aa ( p )

So if it is 100% penetrant, that implies that the chances of the affected child is;

(2/4 ) ×100=50%

However, only 80% penetrant is given here,so that is why the chances of the affected is then ; (50/100) ×(80/100) ×100= 40%

That means the affected child chances are 40%.

Final answer:

Polydactyly is a rare autosomal dominant trait with 80% penetrance.

Explanation:

Polydactyly is a rare autosomal dominant trait that is 80% penetrant. This means that if a person carries the genetic mutation for polydactyly, there is an 80% chance that they will express the trait. Therefore, if the father is affected by polydactyly (carries the gene) and the mother is normal (does not carry the gene), each child they have has a 50% chance of inheriting the gene from the father and a 50% chance of inheriting the normal gene from the mother.

However, if a child inherits the gene for polydactyly from the father, there is an 80% chance that they will express the trait, meaning they will have the disorder. On the other hand, if the child inherits the normal gene from the mother, they will not have the disorder.

Learn more about Polydactyly here:

brainly.com/question/33930927

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