Please help!!!Which layer of the sun is shown extending into space in the picture above?

Group of answer choices

Corona

Radiative zone

Convective zone

Photosphere

Answer : (C) 854.46 KPa.

Solution : Given,

Initial pressure = 400 KPa

Initial temperature = 110 K

Final temperature = 235 K

According to the Gay-Lussac's law, the absolute pressure is directly proportional to the absolute temperature at constant volume of an ideal gas.

P  ∝  T

Formula used :  

where,

= initial pressure

= final pressure

= initial temperature

= final temperature

Now put all the values in above formula, we get

By rearranging the terms, we get the value of new/final pressure.

= 854.5454 KPa 854.55 KPa

Answer:

-4741 °C

Something is strange, because this is a weird number.

Explanation:

ΔT = Kf . m. i

That's the colligative property of freezing point depression.

Kf = Cyroscopic constant

m = molality (moles of solute in 1kg of solvent)

i = Van't Hoff factor (numbers of ions dissolved)

We assume 100% dissociation:

CaCl₂ → Ca²⁺ + 2Cl⁻   i = 3

ΔT = Freezing point of pure solvent - Freezing point of solution

Let's determine molality

Solute = CaCl₂

Moles of solute = 23.5 g . 1 mol/ 110.98 g = 0.212 moles

We determine the mass of solvent by density. Density's data is in g/L. We need to convert the volume from mL to L

250 mL . 1L / 1000 mL = 0.250 L

0.997 g/L = mass of water / volume of water → 0.997 g/L . volume of water = mass of water

0.997 g/L . 0.250L = 0.249 g

Now, we convert the mass of water from g to kg

0.249 g . 1 kg / 1000 g = 2.49×10⁻⁴ kg

Molality = mol/kg → 0.212 mol / 2.49×10⁻⁴ kg = 850.5 m

We replace data:

0°C - Freezing point of solution = 1.858 °C . kg /mol . 850.5 mol/kg . 3

Freezing point of solution = -4741 °C

Answer:

The freezing point of the solution is -4.74 °C

Explanation:

Step 1: data given

Mass of calcium chloride CaCl2 = 23.50 grams

Step 2: Calculate moles CaCl2

Moles CaCl2 = mass CaCl2 / molar mass CaCl2

Moles CaCl2 = 23.50 grams / 110.98 g/mol

Moles CaCl2 = 0.212 moles

Step 3: Calculate mass H2O

Density = mass / volume

Mass = density * volume

Mass H2O = 997 g/L * 0.250 L

MAss H2O = 249.25 grams

Step 3: calculate molality of the solution

Molality = moles CaCl2 / mass H2O

Molality = 0.212 moles / 0.24925 kg

Molality = 0.851 molal

ΔT = i*Kf*m  

⇒with ΔT = the freezing point depression = TO BE DETERMNED

⇒ with i = the van't Hoff factor = 3

⇒with Kf = the freezing point depression constant of water = 1.858 °C /m

⇒with m = the molality = moles CaCl2 / mass water = 0.851 molal

ΔT = 3 * 1.858 * 0.851

ΔT =  4.74 °C

Step 4: Calculate the freezing point of the solution

ΔT = T (pure solvent) − T (solution)

ΔT  = 0°C - 4.74 °C

The freezing point of the solution is -4.74 °C

NOTE: the density of water = 0.997 kg/L or 997 g/L

Carbon monoxide is an air pollutant that can contribute to asthma. Therefore, option D is correct.

Carbon monoxide (CO) is a colorless and odorless gas produced by the incomplete combustion of fossilfuels, such as gasoline, coal, and wood. It is primarily emitted by vehicles, industrial processes, and the burning of biomass.

When inhaled, carbon monoxide reduces the blood's ability to carry oxygen, leading to oxygen deprivation in the body. Prolonged exposure to carbon monoxide can worsen asthma symptoms and potentially trigger asthma attacks.

To learn more about air pollutants, follow the link:

brainly.com/question/31023039

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Arrhenius acids are substances which produces hydrogen ions in solution, Arrhenius bases are substances which produces hydroxide ions in solution. A Bronsted-Lowry acid is a proton donor (usually hydrogen ion). And a Bronsted-Lowry base is a proton acceptor (usually hydrogen ion). Consider a chemical reaction between HCl and NaOH. We have the reaction HCl + NaOH à NaCl + H2O. The hydroxide ions in the NaOH are bases because they accept hydrogen ions from acids to form water. And an acid produces hydrogen ions in solution by giving a proton to the water molecule. Therefore, the answer is d. a Bronsted-Lowry base.