CHEMISTRY HIGH SCHOOL

What is work?O A. Force times an object's displacement
B. The distance an object moves over time
C. The time it takes an object to move a certain distance
D. The force that distance makes
SUBMIT

Answers

Answer 1
Answer:

Answer:

A:force times an object displacement

Explanation:
Answer 2
Answer: Answer Force time an object displacement explanation: Search Results
Featured snippet from the web
A force is said to do work if, when acting, there is a displacement of the point of application in the direction of the force. ... Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J).

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Determine the pH of 0.450 M HC7H5O2. The Ka for HC7H5O2 is 6.5 × 10⁻⁵.

Use the periodic table to identify the element represented by each of the following electron configurations. [He]2s2: ?

Answers

Answer:

Be. Beryllium

Explanation:

After using loops, swabs, toothpicks, spreaders or any other equipment to transfer cultures, immerse the contaminated equipment in ______.pure bleach
a strong acid
tap water
All of the above

Answers

Answer:

Explanation:

pure bleach b/c that is was helps destroy the bacteria

Final answer:

After transferring cultures with any equipment, it is best to immerse the equipment in pure bleach. Bleach is a strong disinfectant that can efficiently destroy various types of microorganisms.

Explanation:

After using loops, swabs, toothpicks, spreaders or any other equipment to transfer cultures, the equipment should ideally be immersed in pure bleach. This is because pure bleach effectively destroys many types of microorganisms found in these cultures. Pure bleach is a strong disinfectant that kills bacteria, viruses, and fungi, reducing the risk of spreading these organisms in the lab. Pouring bleach over the equipment can remove most of these organisms, but immersion guarantees thorough decontamination.

Learn more about Decontamination here:

brainly.com/question/31758739

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Calculate how much gasoline and money could be saved if the automobile's fuel efficiency were increased by 25%.Gasoline = 25 gallons per week
Money = $2 per gallon ($50 total)

Answers

In the question it is already given the amount of actual gasoline and money consumed before the fuel efficiency gets increased by 25%
Gasoline consumption before the increase in fuel efficiency = 25 gallons per week
Gasoline saved after the increase in fuel efficiency = [25 * (25/100)] gallons per week
                                                                                             = 6.25 gallons per week
So every week 6.25 gallons of gasoline can be saved after increasing the efficiency of the automobile by 25%.
Then
The amount of money saved against the 6.25 gallons of gasoline saved = (6.25 * 2) dollars
                                                                                                                   = 12.50 dollars
The amount of money saved is $12.50 per week.

What happens when the number of electrons and protons inside of an atom are Not equel?

Answers

Hello, It's me Moriah Elizabeth!

Answer:

When the number of electrons does not equal the number of protons, the atom is ionized.

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What is the Ksp of barium carbonate?

Answers

The value of {{\text{K}}_{{\text{sp}}}} for barium carbonate is \boxed{{\text{2}}{{.6 * 1}}{{\text{0}}^{{\text{ - 9}}}}}.

Further explanation:

Solubility product constant:

The equilibrium constant between the compound and its ion, when dissolved in solution, is known as solubility product constant. It is denoted by {{\text{K}}_{{\text{sp}}}}. The solubility product constant is used to calculate the product of the concentration of ions at equilibrium.

Higher the solubility product constant more will be the solubility of the compound.

The general reaction is as follows:

{\text{AB}}\left({aq}\right)\to{{\text{A}}^+}\left({aq}\right)+{{\text{B}}^-}\left({aq}\right)

The expression to calculate the solubility product for the general reaction is as follows:

\boxed{{{\text{K}}_{{\text{sp}}}}=\left[{{{\text{A}}^+}}\right]\left[{{{\text{B}}^-}}\right]}

Here,

{{\text{K}}_{{\text{sp}}}} is the solubility product constant.

\left[ {{{\text{A}}^ + }} \right] is the concentration of {{\text{A}}^ + }ions.

\left[ {{{\text{B}}^ - }} \right]is the concentration of {{\text{B}}^ - }ions.

The dissociation of {\text{BaC}}{{\text{O}}_{\text{3}}} occurs as follows:

{\text{BaC}}{{\text{O}}_3}\to{\text{B}}{{\text{a}}^(2+)}+{\text{CO}}_3^(2-)

The given solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is 0.0100 g/L. Firstly, it is to be converted in mol/L. So the solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is calculated as follows:

{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{mol/L}}}\right)= \frac{{{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/L}}}\right)}}{{{\text{Molar mass of BaC}}{{\text{O}}_{\text{3}}}\left({{\text{g/mol}}}\right)}}      …… (1)

The solubility of {\text{BaC}}{{\text{O}}_{\text{3}}} is 0.0100 g/L.

The molar mass of {\text{BaC}}{{\text{O}}_{\text{3}}} is 197.3 g/mol.

Substitute these values in equation (1).

\begin{aligned}{\text{Solubility of BaC}}{{\text{O}}_{\text{3}}}&=\left( {\frac{{{\text{0}}{\text{.0100 g}}}}{{{\text{1 L}}}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{197}}{\text{.3 g}}}}} \right)\n&=0.00005068\;{\text{mol/L}}\n\end{aligned}

It is evident from the chemical equation, one mole of {\text{BaC}}{{\text{O}}_{\text{3}}} dissociates to form one mole of {\text{B}}{{\text{a}}^(2+)} and one mole of {\text{CO}}_3^(2-). So the solubility of both {\text{B}}{{\text{a}}^(2+)} and {\text{CO}}_3^(2-)is 0.00005068 mol/L.

The formula to calculate the solubility product of  is as follows:

{{\text{K}}_{{\text{sp}}}}=\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right]\left[{{\text{CO}}{{_3^2}^-}}\right]                                      …… (2)

Substitute 0.00005068 mol/L for\left[{{\text{B}}{{\text{a}}^{{\text{2+}}}}}\right] and 0.00005068 mol/L for \left[{{\text{CO}}_3^(2-)}\right]in equation (2).

\begin{aligned}{{\text{K}}_{{\text{sp}}}}&=\left({{\text{0}}{\text{.00005068}}} \right)\left({{\text{0}}{\text{.00005068}}}\right)\n&=2.6*{10^(-9)}\n\end{aligned}

Therefore, the value of {{\mathbf{K}}_{{\mathbf{sp}} for {\mathbf{BaC}}{{\mathbf{O}}_{\mathbf{3} is {\mathbf{2}}{\mathbf{.6 * 1}}{{\mathbf{0}}^(-9)}.

Learn more:

1. Sort the solubility of gas will increase or decrease: brainly.com/question/2802008.

2. What is the pressure of the gas?: brainly.com/question/6340739.

Answer details:

Grade: School School

Subject: Chemistry

Chapter: Chemical equilibrium

Keywords: solubility, Ba2+, CO32-, BaCO3, Ksp, solubility product, molar mass, 197.3 g/mol, mol/L, g/L, 0.0100 g/L.

It's simple, just follow my steps.

1º - in 1 L we have 0.0100~g of BaCO_3

2º - let's find the number of moles.

\eta=(m)/(MM)

\eta=(0.0100)/(197.3)

\boxed{\boxed{\eta=5.07*10^(-5)~mol}}

3º - The concentration will be

C=5.07*10^(-5)~mol/L

But we have this reaction

BaCO_3\rightleftharpoons Ba^(2+)+CO_3^(2-)

This concentration will be the concentration of Ba^(2+)~~and~~CO_3^(2-)

K_(sp)=([Ba^(2+)][CO_3^(2-)])/([BaCO_3])

considering [BaCO_3]=1~mol/L

K_(sp)=[Ba^(2+)][CO_3^(2-)]

and

[Ba^(2+)]=[CO_3^(2-)]=5.07*10^(-5)~mol/L

We can replace it

K_(sp)=(5.07*10^(-5))*(5.07*10^(-5))

K_(sp)\approx25.70*10^(-10)

Therefore the K_(sp) is:

\boxed{\boxed{\boxed{K_(sp)\approx2.57*10^(-11)}}}

Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distribution of positive charge within the atom.

Answers

Ernest Rutherford applies alpha particle towards an atom, some atom showed deflection by smaller angle, very few through large angle and many just passed without any deflection.

His results changed the idea for distribution of positive charges as he concluded almost all the positive charge is in center of the atom (inside nucleus) and it is very heavy than electrons which revolves outside the nucleus

Hope this helps!
Physicist Ernest Rutherford established the nuclear theory of the atom with his gold-foil experiment. When he shot a beam of alpha particles at a sheet of gold foil, a few of the particles were deflected. He concluded that a tiny, dense nucleus was causing the deflections.
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