The standard deviation of a sample taken from population A is 17.6 for a sample of 25. The standard deviation of a sample taken from population B is 21.2 for a sample of 30. The standard deviation of the sample mean differences is _____. Round your answer to the nearest hundredth.

Answers

Answer 1
Answer: The standard deviation of the sample mean differences should be calculated using the standard deviations of the two populations. In order to see how they differ, we need to first subtract them from each other, so: 21.2-17.6 = 3.6 We then divide this number with the first standard deviation as follows: 3.6/21.2 and multiply this answer by 100. Therefore, the standard deviation of the sample mean is 3.6/21.2 x 100 = 16.98.
Answer 2
Answer:

The standard deviation of the sample mean differences is 16.98.

What is population standard deviation?

It is defined to be the square root of the population variance of the vector. The sample standard deviation s is defined to the square root of the sample variance of the vector.

The standard deviation of the sample mean differences should be calculated using the standard deviations of the two populations. In order to see how they differ, we need to first subtract them from each other, so: 21.2-17.6 = 3.6 We then divide this number with the first standard deviation as follows: 3.6/21.2 and multiply this answer by 100. Therefore, the standard deviation of the sample mean is 3.6/21.2 x 100 = 16.98.

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Answers

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Which of the following would a specialized tissue cell NOT differentiate into?A. Neuron cell
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Answers

Answer:

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Explanation:

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Answers

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please help me If a heterozygous dominant tall pea plant is crossed with a short pea plant, what is the expected phenotypic ratio of tall:short plants? 1:1 1:2 3:1 all tall all short

Answers

Assuming a diallelic gene exhibiting complete dominance, with tall plants being the dominant phenotype and short plants the recessive one, the cross of a heter0zyg0us plant with a short one results in a phenotypic ratio 1:1.

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We know that the cross involved a heter0zyg0us dominant tall pea plant and a short pea plant.

We will assume a diallelic gene coding for this trait, and exhibiting complete dominance. This means that the dominant allele completely masks the expression of the recessive allele.

So,

  • h0m0zyg0us dominant genotype    ⇒     dominant phenotype
  • heter0zyg0us genotype                    ⇒     dominant phenotype
  • h0m0zygous recessive genotype    ⇒     recessive phenotype

If the heter0zyg0us plant exhibits the dominant phenotype, it means that the allele coding for tall plants in the dominant allele.

So let us say that

  • T is the dominant allele that codes for tall plants
  • t is the recessive allele that codes for short plant

According to this information, the tall plant is Tt and the short plant is tt.

So let us make the cross,

Cross:  tall plant with short plant

Parentals)    Tt      x       tt

Gametes)   T     t        t     t

Punnett square)      T            t

                       t       Tt            tt

                       t       Tt            tt

F1) Genotype

  • 2/4 = 1/2 = 50% of the progeny is expected to be heter0zygous, Tt
  • 2/4 = 1/2 = 50% of the progeny is expected to be h0m0zyg0us recessive, tt

Genotypic ratio ⇒ 1:1

    Phenotype

  • 2/4 = 1/2 = 50% of the progeny is expected to be tall plants
  • 2/4 = 1/2 = 50% of the progeny is expected to be short plants

Phenotypic ratio ⇒ 1:1

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dominant trait = T (tall)
recessive trait = t (short)

heterozygous, meaning different, tall pea plant = Tt
short, short being recessive, pea plant = tt

phenotype means physical looks, which is either tall or short

T t

t | Tt tt
t | Tt tt

two Tt & two tt meaning there are 2 tall and two short. therefore,
1:1