CHEMISTRY HIGH SCHOOL

What is the percent by mass of carbon in C10 H14 N2?

Answers

Answer 1

Answer:

Answer: The percentage by mass of carbon in the given compound is 45.8 %

Explanation:

We are given a chemical compound having chemical formula $C_(10)H_(14)N_2$

To calculate the percentage composition of an element in a compound, we use the equation:

$\%\text{ composition}=\frac{\text{Mass of carbon element}}{\text{Mass of compound}}* 100$

In 1 mole of given compound, 10 moles of carbon atoms are there.

Mass of $C_(10)H_(14)N_2= [(10* 12)+(14 * 1)+(2* 14)]=262g/mol$

Mass of carbon element = $[10* 12]=120g/mol$

Putting values in above equation, we get:

$\%\text{ composition of carbon}=(120)/(262)* 100=45.8\%$

Hence, percentage of carbon in given compound is 45.8 %.

Answer 2

Answer: Multiply the number of each element by its mass on the periodic table.

Add them together.

Put the mass of carbon only over the total mass and multiply the result by 100 to get the percentage.

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Which of the following statements does not apply to water?a. Like all liquids, water assumes the shape of its container.
b. Water is a polar molecule.
c. The strong surface tension of water allows it to adhere to the sides of a container and actually move up tubing via capillary action.
d. Water cannot be found in other places in the universe.

Answers

the answer is c the strong surface tension of water allows it to adhere to the sides of the container and actually move up tubing via capillary action

Where are the alkali metals and the halogens located on the periodic table?

Answers

Alkali: Group 1(I A). Halogens: group 17 (VII A)

When a helium atom is stripped of its two electrons, what's left are two protons and two neutrons. This "electron-less" atom is sometimes called a(n)a. quark.
b. beta particle.
c. alpha particle.
d. helium isotope.

Answers

alpha particle. You will see these in nuclear chemistry due to the fact that this is one of the type of radio active decay.

I hope this helps.

Most commercial sports drinks area. calcium-rich.
b. good recovery sources.
c. sodium-poor.
d. highly concentrated

Answers

C. sodium poor is the answer

C. Sodium Poor - I took the test and got it correct

If you determined that the volume of a silver bar is 100.mL,how many atoms of silver would be in the bar? The density of silver is 10.5g/mL. 271

Answers

There are approximately $5.86 \ * \ 10^(24) atoms$ of silver in the 100 mL silver bar.

To determine the number of atoms in a silver bar, you can follow these steps:

Calculate the mass of the silver bar:

Mass (g) = Volume (mL) x Density (g/mL)

Mass = 100 mL x 10.5 g/mL = 1050 g

Calculate the molar mass of silver (Ag):

The molar mass of silver (Ag) is approximately 107.87 g/mol.

Calculate the number of moles of silver in the bar:

Moles = Mass (g) / Molar Mass (g/mol)

Moles = 1050 g / 107.87 g/mol ≈ 9.73 moles

Calculate Avogadro's number:

Avogadro's number is approximately $6.022\ * \ 10^(23) atoms/mol.$

Calculate the number of silver atoms in the bar:

Number of atoms = Moles x Avogadro's number

Number of atoms = $9.73\ moles \ * \ 6.022 \ * \ 10^(23) \ atoms/mol \approx 5.86 \ * \ 10^(24) atoms$

Thus, there are approximately $5.86 \ * \ 10^(24) atoms$ of silver in the 100 mL silver bar.

For more such questions on silver:

brainly.com/question/18510431

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10.5 g/mL * 100 mL = 1050 g of silver

1050 g silver * ( 1 mol silver/107.8682g) = 9.734 mol silver

9.734 moles silver * 6.022E23 atoms/ mole = 5.861E24 atoms of silver

Where molar mass if silver = 107.8682g/mol
Avogadro's number = 6.022E23 atoms/moles

H2O has a mc021-1.jpgHvap = 40.7 kJ/mol. What is the quantity of heat that is released when 27.9 g of H2O condenses?A)60.00 kJ
B)61.05 kJ
C)63.09 kJ
D)68.60 kJ

Answers

Energy released from changing the phase of a substance from the gas phase to liquid phase can be calculated by using the specific latent heat of vaporization. The heat of fusion of water at 0 degrees Celsius is 40.7 kJ/mol. Calculation are as follows:

Energy = 27.9 g (1 mol / 18.02 g) x 40.7 kJ/mol

Energy = 63.09 kJ

Answer:

C- 63.09 kJ

Explanation:

I have several degrees

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