You are tiling a kitchen floor that is 10 ft wide by 4 yd long. How many square yards of tile do you need?

Answers

Answer 1

Answer: there are three feet in a yard, so it is 3 and 1/3 yards wide, and 4 yards long.
you can just multiply both numbers together to get your answer, 40/3 or 13 1/3 yards.

Answer 2

Answer:

Answer:

Step-by-step explanation:

13 1/2 yd^2

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What passes through the points (-4,3) and (-4,-2)

Answers

The equation of the line through those two points is . . . . . . . . . . X = -4 . / / / The line has no y-intercept and undefined slope. It's the vertical line that crosses the x-axis at -4 and goes up and down forever.

DESCRIBE the probability of a woman growing to be 5 metres tall

Answers

Answer:

the answer might be unlikely

At Silver Gym, membership is $25 per month, and personal training sessions are $45 each. At Fit Factor, membership is $85 per month, and personal training sessions are $35 each. In one month, how many personal training sessions would Sarah have to buy to make the total cost at the two gyms equal?

Answers

Answer:

6 training sessions.

Step-by-step explanation:

Let there be x training sessions at both the gyms.

At silver gym,

Total cost = membership + personal training session

= 25+45x ...(1)

At Fit Factor,

Total cost = 85+35x ....(2)

If the total cost at the two gyms equal,

25+45x=85+35x

Taking like terms together,

45x-35x=85-25

10x=60

x = 6

Hence, Sarah must buy 6 training sessions.

Charlie is 24 years older than Marty. If the total years old of both are 130, find the years old of each one.

Answers

C- Charlie

M-Marty

C=24+M

C+M=130

_______

24+M+M=130

2M=106

M=53

C=53+24=77

C=77

$x-Charlie\ age\ny-Marty\ age\n\nChrlie\ is\ 24\ years\ older\ than\ Marty:x=y+24\nThe\ total\ years\ old\ of\ both\ are\ 130:x+y=130\n\nTherefore\ we\ have:\n \left\{\begin{array}{ccc}x=y+24&(1)\nx+y=130&(2)\end{array}\right\n\nsubtitute\ (1)\ to\ (2):\n\n(y+24)+y=130\ny+24+y=130\n2y+24=130\ \ \ \ |subtract\ 24\ from\ both\ sides\n2y=106\ \ \ |divide\ both\ sdies\ by\ 2\n\boxed{y=53}$

$Subtract\ the\ value\ of\ y=53\ to\ the\ (1):\n\nx=53+24=\boxed{77}\n\n\boxed{ \left\{\begin{array}{ccc}x=77\ny=53\end{array}\right}\n\nAnswer:\nCharlie\ age:77\nMarty\ age:53$

Solve the equation.x^2 = 150

A. ± 25√6

B. 15

C. -15,15

D. ± 5√6

Answers

x^2 = 150
√x^2 = √150
x = 5√6 (or) ≈12.25

HOPE THIS HELPS!!!!

Hi Brainiac

x²= 150

Just take the square root of 150

x= +/- 5√6 or x= -5√6

I hope that's help:0

$800 is deposited in an account that pays 9% compounded semi-annually. Find the balance after 4 years.

Answers

The formula for compound interest is the following:

A=P(1+r/n)^nt
A=accumulated amount (what we're looking for)
P=Principal amount (initial amount). $800 in this case
r=rate. 0.09 in this case which we get from converting 9% to decimal by dividing by a 100.
n=number of times interest is compounded. In this case semi-annually which means 2
t=time. In this case 4 years
Let's calculate:
A=800(1+0.09/2)^(2*4)
A=800(1+0.045)^8
A=800(1.045)^8
A=800(1.42210061284)
A=1137.68049027
Let's round to the hundredth place (to represent cents) since the amount represents money.
Answer=The balance after 4 years will be $1,137.68

Answer:

Principal = $ 800

Time = 4 years

Rate of Interest = 9% compounded Semi Annually

$=(9\pr)/(2)$

Time = 4× 2=8 periods

As, we have to find balance after 4 years, so we will use the formula for amount in terms of Compound interest.

Amount(A)

$A=P[1+(R)/(100)]^n\n\n A=800* [1+(9)/(200)]^8\n\n A=800 * [(209)/(200)]^8\n\n A=800 * (1.045)^8\n\n A=800 * 1.422\n\n A=1137.680$

Balance after 4 years = $ 1137.68

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